Printing an array in C

Question

Is there a way of printing arrays in C     I m trying to make a function that reverses a user-input array and then prints it out  I tried Googling this problem and it seemed like C   can t print arrays  That can t be true can it

User · Answer

It certainly is  You ll have to loop through the array and print out each item individually

User · Answer

This might help   Printing The Array  for  int i   0  i  lt  n  i     cout  lt  lt  numbers i      n is the size of the array

User · Answer

There are declared arrays and arrays that are not declared  but otherwise created  particularly using new   int  p   new int 3     That array with 3 elements is created dynamically  and that 3 could have been calculated at runtime  too   and a pointer to it which has the size erased from its type is assigned to p  You cannot get the size anymore to print that array  A function that only receives the pointer to it can thus not print that array    Printing declared arrays is easy  You can use sizeof to get their size and pass that size along to the function including a pointer to that array s elements  But you can also create a template that accepts the array  and deduces its size from its declared type   template lt typename Type  int Size gt  void print Type const  amp  array  Size       for int i 0  i lt Size  i        std  cout  lt  lt  array i   lt  lt  std  endl      The problem with this is that it won t accept pointers  obviously   The easiest solution  I think  is to use std  vector  It is a dynamic  resizable  array   with the semantics you would expect from a real one   which has a size member function   void print std  vector lt int gt  const  amp v      std  vector lt int gt   size type i    for i   0  i lt v size    i        std  cout  lt  lt  v i   lt  lt  std  endl      You can  of course  also make this a template to accept vectors of other types

User · Answer

Just do this  use a vector with this code and you re good lol -Daniel   include  lt Windows h gt   include  lt iostream gt   include  lt vector gt   using namespace std    int main          std  vector lt const char  gt  arry      quot Item 0 quot   quot Item 1 quot   quot Item 2 quot   quot Item 3 quot    quot Item 4 quot   quot Yay we at the end of the array quot             if  arry size      arry size      arry empty              printf  quot what happened to the array lol n  quot            system  quot PAUSE quot              for  int i   0  i  lt  arry size    i                     if  arry max size      true                cout  lt  lt   quot Max size of array reached  quot                     cout  lt  lt   quot Array Value  quot   lt  lt  i  lt  lt   quot     quot   lt  lt  arry at i   lt  lt  endl

User · Answer

Besides the for-loop based solutions  you can also use an ostream iterator lt     Here s an example that leverages the sample code in the  now retired  SGI STL reference    include  lt iostream gt   include  lt iterator gt   include  lt algorithm gt   int main       short foo       1  3  5  7       using namespace std    copy foo         foo   sizeof foo    sizeof foo 0           ostream iterator lt short gt  cout    n         This generates the following      a out  1 3 5 7   However  this may be overkill for your needs   A straight for-loop is probably all that you need  although litb s template sugar is quite nice  too   Edit  Forgot the  printing in reverse  requirement   Here s one way to do it    include  lt iostream gt   include  lt iterator gt   include  lt algorithm gt   int main       short foo       1  3  5  7       using namespace std     reverse iterator lt short   gt  begin foo   sizeof foo    sizeof foo 0       reverse iterator lt short   gt  end foo      copy begin         end         ostream iterator lt short gt  cout    n         and the output       a out  7 5 3 1   Edit  C  14 update that simplifies the above code snippets using array iterator functions like std  begin   and std  rbegin      include  lt iostream gt   include  lt iterator gt   include  lt algorithm gt   int main         short foo       1  3  5  7            Generate array iterators using C  14 std   r begin          and std   r end            Forward     std  copy std  begin foo                 std  end foo                 std  ostream iterator lt short gt  std  cout    n             Reverse     std  copy std  rbegin foo                 std  rend foo                 std  ostream iterator lt short gt  std  cout    n

User · Answer

May I suggest using the fish bone operator   for  auto x   std  end a   x    std  begin a           std  cout  lt  lt  --x lt  lt            Can you spot it

User · Answer

Just iterate over the elements  Like this   for  int i   numElements - 1  i  gt   0  i--       cout  lt  lt  array i     Note  As Maxim Egorushkin pointed out  this could overflow  See his comment below for a better solution

User · Answer

My simple answer is    include  lt iostream gt  using namespace std   int main         int data    1  2  7        for  int i   sizeof data    sizeof data 0  -1  i  gt   0  i--            cout  lt  lt  data i              return 0

User · Answer

Use the STL   include  lt iostream gt   include  lt vector gt   include  lt algorithm gt   include  lt iterator gt   int main         std  vector lt int gt     userInput          Read until end of input         Hit control D       std  copy std  istream iterator lt int gt  std  cin                 std  istream iterator lt int gt                   std  back inserter userInput                          Print in Normal order     std  copy userInput begin                  userInput end                  std  ostream iterator lt int gt  std  cout                          std  cout  lt  lt    n           Print in reverse order      std  copy userInput rbegin                  userInput rend                  std  ostream iterator lt int gt  std  cout                          std  cout  lt  lt    n           Update for C  11        Range based for is now a good alternative      for auto const amp  value  userInput                std  cout  lt  lt  value  lt  lt                 std  cout  lt  lt    n

User · Answer

C   can print whatever you want if you program it to do so  You ll have to go through the array yourself printing each element

User · Answer

Most of the libraries commonly used in C   can t print arrays  per se  You ll have to loop through it manually and print out each value   Printing arrays and dumping many different kinds of objects is a feature of higher level languages

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