Convert hex to binary

Question

I have ABC123EFFF   I want to have 001010101111000001001000111110111111111111  i e  binary repr  with  say  42 digits and leading zeroes    How

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import binascii hexa input   input  Enter hex String to convert to Binary     pad bits len hexa input  4 Integer output int hexa input 16  Binary output  bin Integer output  2    zfill pad bits  print Binary output     zfill x  i e  x no of 0 s to be padded left - Integers will overwrite 0 s starting from right side but remaining 0 s will display till quantity x  y   where y is no of output chars which need to destroy starting from left

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Use Built-in format   function and int   function It s simple and easy to understand  It s little bit simplified version of Aaron answer  int    int string  base    format    format integer    of bits    Example    w o 0b prefix  gt  gt  format int  ABC123EFFF   16    040b   1010101111000001001000111110111111111111    with 0b prefix  gt  gt  format int  ABC123EFFF   16     042b   0b1010101111000001001000111110111111111111    w o 0b prefix   64bit  gt  gt  format int  ABC123EFFF   16    064b   0000000000000000000000001010101111000001001000111110111111111111   See also this answer

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Here s a fairly raw way to do it using bit fiddling to generate the binary strings   The key bit to understand is    n    1  lt  lt  i   and 1  Which will generate either a 0 or 1 if the i th bit of n is set    import binascii  def byte to binary n       return    join str  n    1  lt  lt  i   and 1  for i in reversed range 8     def hex to binary h       return    join byte to binary ord b   for b in binascii unhexlify h    print hex to binary  abc123efff        1010101111000001001000111110111111111111   Edit  using the  new  ternary operator this    n    1  lt  lt  i   and 1  Would become   1 if n    1  lt  lt  i  or 0   Which TBH I m not sure how readable that is

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0 020b   format int  ABC123EFFF   16

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For solving the left-side trailing zero problem     my hexdata    1a   scale   16    equals to hexadecimal  num of bits   8  bin int my hexdata  scale   2   zfill num of bits      It will give 00011010 instead of the trimmed version

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no raw input  Enter your number in hexa decimal     def convert a       if a   0           c  0000      elif a   1           c  0001      elif a   2           c  0010      elif a   3           c  0011      elif a   4           c  0100      elif a   5           c  0101      elif a   6           c  0110      elif a   7           c  0111      elif a   8           c  1000      elif a   9           c  1001      elif a   A           c  1010      elif a   B           c  1011      elif a   C           c  1100      elif a   D           c  1101      elif a   E           c  1110      elif a   F           c  1111      else          c  invalid      return c  a len no  b 0 l    while b lt a      l l convert no b       b  1 print l

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a   raw input  hex number n   length   len a  ab   bin int a  16   2   while len ab  lt  length   4       ab    0    ab print ab

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This is a slight touch up to Glen Maynard s solution  which I think is the right way to do it   It just adds the padding element        def hextobin self  hexval                       Takes a string representation of hex data with         arbitrary length and converts to string representation         of binary   Includes padding 0s                     thelen   len hexval  4         binval   bin int hexval  16   2           while   len binval    lt thelen               binval    0    binval         return binval    Pulled it out of a class   Just take out self   if you re working in a stand-alone script

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Another way   import math  def hextobinary hex string       s   int hex string  16       num digits   int math ceil math log s    math log 2        digit lst     0     num digits     idx   num digits     while s  gt  0          idx -  1         if s   2    1  digit lst idx     1          s   s   2     return    join digit lst   print hextobinary  abc123efff

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Python Program - Convert Hexadecimal to Binary hexdec   input  Enter Hexadecimal string     print hexdec   in Binary      end          end is by default   n  which prints a new line for  hex in hexdec      dec   int  hex  16       16 means base-16 wich is hexadecimal     print bin dec  2   rjust 4  0    end          the  2   skips 0b  and the

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Convert hex to binary      I have ABC123EFFF       I want to have 001010101111000001001000111110111111111111  i e  binary   repr  with  say  42 digits and leading zeroes     Short answer   The new f-strings in Python 3 6 allow you to do this using very terse syntax    gt  gt  gt  f  0xABC123EFFF 0 gt 42b    001010101111000001001000111110111111111111    or to break that up with the semantics    gt  gt  gt  number  pad  rjust  size  kind   0xABC123EFFF   0     gt    42   b   gt  gt  gt  f  number  pad  rjust  size  kind     001010101111000001001000111110111111111111    Long answer   What you are actually saying is that you have a value in a hexadecimal representation  and you want to represent an equivalent value in binary   The value of equivalence is an integer  But you may begin with a string  and to view in binary  you must end with a string   Convert hex to binary  42 digits and leading zeros   We have several direct ways to accomplish this goal  without hacks using slices   First  before we can do any binary manipulation at all  convert to int  I presume this is in a string format  not as a literal     gt  gt  gt  integer   int  ABC123EFFF   16   gt  gt  gt  integer 737679765503   alternatively we could use an integer literal as expressed in hexadecimal form    gt  gt  gt  integer   0xABC123EFFF  gt  gt  gt  integer 737679765503   Now we need to express our integer in a binary representation   Use the builtin function  format  Then pass to format    gt  gt  gt  format integer   0 gt 42b    001010101111000001001000111110111111111111    This uses the formatting specification s mini-language    To break that down  here s the grammar form of it     fill align  sign     0  width      precision  type    To make that into a specification for our needs  we just exclude the things we don t need    gt  gt  gt  spec     fill  align  width  type   format fill  0   align   gt    width 42  type  b    gt  gt  gt  spec  0 gt 42b    and just pass that to format   gt  gt  gt  bin representation   format integer  spec   gt  gt  gt  bin representation  001010101111000001001000111110111111111111   gt  gt  gt  print bin representation  001010101111000001001000111110111111111111   String Formatting  Templating  with str format  We can use that in a string using str format method    gt  gt  gt   here is the binary form   0  spec    format integer  spec spec   here is the binary form  001010101111000001001000111110111111111111    Or just put the spec directly in the original string    gt  gt  gt   here is the binary form   0 0 gt 42b   format integer   here is the binary form  001010101111000001001000111110111111111111    String Formatting with the new f-strings  Let s demonstrate the new f-strings  They use the same mini-language formatting rules    gt  gt  gt  integer   0xABC123EFFF  gt  gt  gt  length   42  gt  gt  gt  f  integer 0 gt  length b    001010101111000001001000111110111111111111    Now let s put this functionality into a function to encourage reusability   def bin format integer  length       return f  integer 0 gt  length b     And now    gt  gt  gt  bin format 0xABC123EFFF  42   001010101111000001001000111110111111111111          Aside  If you actually just wanted to encode the data as a string of bytes in memory or on disk  you can use the int to bytes method  which is only available in Python 3    gt  gt  gt  help int to bytes  to bytes          int to bytes length  byteorder     signed False  - gt  bytes       And since 42 bits divided by 8 bits per byte equals 6 bytes    gt  gt  gt  integer to bytes 6   big   b  x00 xab xc1  xef xff

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i have a short snipped hope that helps  -   input    ABC123EFFF  for index  value in enumerate input       print value      print bin int value 16  16  3     string      join  bin int x 16  16  3   for y x in enumerate input    print string    first i use your input and enumerate it to get each symbol  then i convert it to binary and trim from 3th position to the end  The trick to get the 0 is to add the max value of the input -  in this case always 16  -    the short form ist the join method  Enjoy

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I added the calculation for the number of bits to fill to Onedinkenedi s solution   Here is the resulting function   def hextobin h     return bin int h  16   2   zfill len h    4    Where 16 is the base you re converting from  hexadecimal   and 4 is how many bits you need to represent each digit  or log base 2 of the scale

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def conversion        e raw input  enter hexadecimal no         e1   a   b   c   d   e   f       e2  10 11 12 13 14 15      e3 1     e4 len e      e5        while e3 lt  e4          e5 e5  e e3-1            e3 e3 1     print e5     e6 1     e8        while e6 lt  e4          e7 e5 e6-1          if e7   A               e7 10         if e7   B               e7 11         if e7   C               e7 12         if e7   D               e7 13         if e7   E               e7 14         if e7   F               e7 15         else              e7 int e7          e8 e8  e7           e6 e6 1     print e8      e9 1     e10 len e8      e11        while e9 lt  e10          e12 e8 e9-1          a1 e12         a2            a3 1          while a3 lt  1              a4 a1 2             a2 a2  a4               a1 a1 2             if a1 lt 2                  if a1  1                      a2 a2  1                   if a1  0                      a2 a2  0                   a3 a3 1         a5 len a2          a6 1         a7            a56 a5         while a6 lt  a5              a7 a7 str a2 a56-1               a6 a6 1             a56 a56-1         if a5 lt  3              if a5  1                  a8  000                  a7 a8 a7             if a5  2                  a8  00                  a7 a8 a7             if a5  3                  a8  0                  a7 a8 a7         else              a7 a7         print a7          e9 e9 1

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bin int  abc123efff   16   2

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gt  gt  gt  bin  0xABC123EFFF      0b1010101111000001001000111110111111111111

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Just use the module coden  note  I am the author of the module  You can convert haxedecimal to binary there   Install using pip  pip install coden   Convert  a hexadecimal number    quot f1ff quot  binary output   coden hex to bin a hexadecimal number   The converting Keywords are   hex for hexadeimal bin for binary int for decimal  to  - the converting keyword for the function  So you can also format  e  hexadecimal output   bin to hex a binary number

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HEX TO BINARY CONVERSION TABLE      0    0000                                  1    0001                                   2    0010                                   3    0011                                   4    0100                                   5    0101                                   6    0110                                   7    0111                                   8    1000                                   9    1001                                   a    1010                                   b    1011                                   c    1100                                   d    1101                                   e    1110                                   f    1111    def hex to binary hex string       binary string    quot  quot      for character in hex string          binary string    HEX TO BINARY CONVERSION TABLE character      return binary string

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The binary version of ABC123EFFF is actually 1010101111000001001000111110111111111111  For almost all applications you want the binary version to have a length that is a multiple of 4 with leading padding of 0s   To get this in Python   def hex to binary  hex code      bin code   bin  hex code   2     padding    4-len bin code  4  4   return  0  padding   bin code   Example 1    gt  gt  gt  hex to binary  0xABC123EFFF    1010101111000001001000111110111111111111    Example 2    gt  gt  gt  hex to binary  0x7123    0111000100100011    Note that this also works in Micropython

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import binascii  binary string   binascii unhexlify hex string    Read  binascii unhexlify  Return the binary data represented by the hexadecimal string specified as the parameter

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Replace each hex digit with the corresponding 4 binary digits   1 - 0001 2 - 0010     a - 1010 b - 1011     f - 1111

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hex --  decimal then decimal --  binary   decimal to binary  def d2b n       bStr          if n  lt  0  raise ValueError   must be a positive integer      if n    0  return  0      while n  gt  0          bStr   str n   2    bStr         n   n  gt  gt  1         return bStr   hex to binary def h2b hex       return d2b int hex 16

[python] Convert hex to binary

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