[php] Time calculation in php (add 10 hours)?

I get the time:

$today = time();
$date = date('h:i:s A', strtotime($today));

if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am??

Full code that shows now and 10 minutes added.....

$nowtime = date("Y-m-d H:i:s");
echo $nowtime;
$date = date('Y-m-d H:i:s', strtotime($nowtime . ' + 10 minute'));
echo "<br>".$date;

$date = date('h:i:s A', strtotime($today . ' + 10 hours'));

(untested)

In order to increase or decrease time using strtotime you could use a Relative format in the first argument.

In your case to increase the current time by 10 hours:

$date = date('h:i:s A', strtotime('+10 hours'));

In case you need to apply the change to another timestamp, the second argument can be specified.

Note:

Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.

So, the recommended way since PHP 5.3:

$dt = new DateTime(); // assuming we need to add to the current time
$dt->add(new DateInterval('PT10H'));
$date = $dt->format('h:i:s A');

or using aliases:

$dt = date_create(); // assuming we need to add to the current time
date_add($dt, date_interval_create_from_date_string('10 hours')); 
$date = date_format($dt, 'h:i:s A');

In all cases the default time zone will be used unless a time zone is specified.

You can simply make use of the DateTime class , OOP Style.

<?php
$date = new DateTime('1:00:00');
$date->add(new DateInterval('PT10H'));
echo $date->format('H:i:s a'); //"prints" 11:00:00 a.m

$tz = new DateTimeZone('Europe/London');
$date = new DateTime($today, $tz);
$date->modify('+10 hours');
// use $date->format() to outputs the result.

see DateTime Class (PHP 5 >= 5.2.0)

$date = date('h:i:s A', strtotime($today . " +10 hours"));