[php] How to find the last day of the month from date?

How can I get the last day of the month in PHP?

Given:

$a_date = "2009-11-23"

I want 2009-11-30; and given

$a_date = "2009-12-23"

I want 2009-12-31.

An other way using mktime and not date('t') :

$dateStart= date("Y-m-d", mktime(0, 0, 0, 10, 1, 2016)); //2016-10-01
$dateEnd = date("Y-m-d", mktime(0, 0, 0, 11, 0, 2016)); //This will return the last day of october, 2016-10-31 :)

So this way it calculates either if it is 31,30 or 29

You can use "t" in date function to get the number of day in a particular month.

The code will be something like this:

function lastDateOfMonth($Month, $Year=-1) {
    if ($Year < 0) $Year = 0+date("Y");
    $aMonth         = mktime(0, 0, 0, $Month, 1, $Year);
    $NumOfDay       = 0+date("t", $aMonth);
    $LastDayOfMonth = mktime(0, 0, 0, $Month, $NumOfDay, $Year);
    return $LastDayOfMonth;
}

for($Month = 1; $Month <= 12; $Month++)
    echo date("Y-n-j", lastDateOfMonth($Month))."\n";

The code is self-explained. So hope it helps.

Try this , if you are using PHP 5.3+,

$a_date = "2009-11-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');

For finding next month last date, modify as follows,

 $date->modify('last day of 1 month');
 echo $date->format('Y-m-d');

and so on..

$date1 = $year.'-'.$month; 
$d = date_create_from_format('Y-m',$date1); 
$last_day = date_format($d, 't');

What is wrong - The most elegant for me is using DateTime

I wonder I do not see DateTime::createFromFormat, one-liner

$lastDay = \DateTime::createFromFormat("Y-m-d", "2009-11-23")->format("Y-m-t");

I know this is a little bit late but i think there is a more elegant way of doing this with PHP 5.3+ by using the DateTime class :

$date = new DateTime('now');
$date->modify('last day of this month');
echo $date->format('Y-m-d');

You could create a date for the first of the next month, and then use strtotime("-1 day", $firstOfNextMonth)

If you use the Carbon API extension for PHP DateTime, you can get the last day of the month with:

$date = Carbon::now();
$date->addMonth();
$date->day = 0;
echo $date->toDateString(); // use toDateTimeString() to get date and time 

Using Zend_Date it's pretty easy:

$date->setDay($date->get(Zend_Date::MONTH_DAYS));

    $startDate = '2011-12-01';
    $endDate = date('Y-m');
    while (true) {
        try {
            $startDateTime = new DateTime($startDate);
            $startDateTime->add(new DateInterval('P1M'));
            $startDate = $startDateTime->format('Y-m-d');
            $endTime = $startDateTime->format('Y-m-t');
            echo $startDate . ' => ' . $endTime . PHP_EOL;
            if ($startDateTime->format('Y-m') == $endDate) {
                break;
            }
        } catch (Exception $exception) {
            var_dump($exception->getMessage());
            break;
        }
    }

After testing many solutions, this works best for me.

Nowadays DateTime does this quite conveniently if you have month and year you can

$date = new DateTime('last day of '.$year.'-'.$month);

From another DateTime object that would be

$date = new DateTime('last day of '.$otherdate->format('Y-m'));

If you have a month wise get the last date of the month then,

public function getLastDateOfMonth($month)
    {
        $date = date('Y').'-'.$month.'-01';  //make date of month 
        return date('t', strtotime($date)); 
    }

$this->getLastDateOfMonth(01); //31

The code using strtotime() will fail after year 2038. (as given in the first answer in this thread) For example try using the following:

$a_date = "2040-11-23";
echo date("Y-m-t", strtotime($a_date));

It will give answer as: 1970-01-31

So instead of strtotime, DateTime function should be used. Following code will work without Year 2038 problem:

$d = new DateTime( '2040-11-23' ); 
echo $d->format( 'Y-m-t' );

Your solution is here..

$lastday = date('t',strtotime('today'));

Carbon API extension for PHP DateTime

Carbon::parse("2009-11-23")->lastOfMonth()->day;

or

Carbon::createFromDate(2009, 11, 23)->lastOfMonth()->day;

will return

30

There are ways to get last day of month.

//to get last day of current month
echo date("t", strtotime('now'));

//to get last day from specific date
$date = "2014-07-24";
echo date("t", strtotime($date));

//to get last day from specific date by calendar
$date = "2014-07-24";
$dateArr=explode('-',$date);
echo cal_days_in_month(CAL_GREGORIAN, $dateArr[1], $dateArr[0]); 

if you want to go back few months you can do something like this as well.

 $list = [
        0, 1, 2, 3
    ];

    $date = new \Datetime();
    $dates = [];
    foreach($list as $item)
    {

        $set = clone $date;
        $set->modify("-$item month ");
       $dates[] = $set->modify("last day of this month");
       
    }
    return $dates;

This a much more elegant way to get the end of the month:

  $thedate = Date('m/d/Y'); 
  $lastDayOfMOnth = date('d', mktime(0,0,0, date('m', strtotime($thedate))+1, 0, date('Y', strtotime($thedate)))); 

You can also use it with datetime

$date = new \DateTime();
$nbrDay = $date->format('t');
$lastDay = $date->format('Y-m-t');

This should work:

$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());

$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());

$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());

echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';

echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';

echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';

I am late but there are a handful of easy ways to do this as mentioned:

$days = date("t");
$days = cal_days_in_month(CAL_GREGORIAN, date('m'), date('Y'));
$days = date("j",mktime (date("H"),date("i"),date("s"),(date("n")+1),0,date("Y")));

Using mktime() is my go to for complete control over all aspects of time... I.E.

echo "<br> ".date("Y-n-j",mktime (date("H"),date("i"),date("s"),(11+1),0,2009));

Setting the day to 0 and moving your month up 1 will give you the last day of the previous month. 0 and negative numbers have the similar affect in the different arguements. PHP: mktime - Manual

As a few have said strtotime isn't the most solid way to go and little if none are as easily versatile.

I am using strtotime with cal_days_in_month as following:

$date_at_last_of_month=date('Y-m-d', strtotime('2020-4-1
+'.(cal_days_in_month(CAL_GREGORIAN,4,2020)-1).' day'));

I needed the last day of the next month, maybe someone will need it:

echo date("Y-m-t", strtotime("next month")); //is 2020-08-13, return 2020-09-30

You can find last day of the month several ways. But simply you can do this using PHP strtotime() and date() function.I'd imagine your final code would look something like this:

$a_date = "2009-11-23";
echo date('Y-m-t',strtotime($a_date));

Live Demo

But If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:

$a_date = "2009-11-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');

Live Demo

Also, you can solve this using your own function like below:

/**
 * Last date of a month of a year
 *
 * @param[in] $date - Integer. Default = Current Month
 *
 * @return Last date of the month and year in yyyy-mm-dd format
 */
function last_day_of_the_month($date = '')
{
    $month  = date('m', strtotime($date));
    $year   = date('Y', strtotime($date));
    $result = strtotime("{$year}-{$month}-01");
    $result = strtotime('-1 second', strtotime('+1 month', $result));

    return date('Y-m-d', $result);
}

$a_date = "2009-11-23";
echo last_day_of_the_month($a_date);

There is also the built in PHP function cal_days_in_month()?

"This function will return the number of days in the month of year for the specified calendar." http://php.net/manual/en/function.cal-days-in-month.

echo cal_days_in_month(CAL_GREGORIAN, 11, 2009); 
// = 30

function first_last_day($string, $first_last, $format) {
    $result = strtotime($string);
    $year = date('Y',$result);
    $month = date('m',$result);
    $result = strtotime("{$year}-{$month}-01");
    if ($first_last == 'last'){$result = strtotime('-1 second', strtotime('+1 month', $result)); }
    if ($format == 'unix'){return $result; }
    if ($format == 'standard'){return date('Y-m-d', $result); }
}

http://zkinformer.com/?p=134

Here is a complete function:

public function get_number_of_days_in_month($month, $year) {
    // Using first day of the month, it doesn't really matter
    $date = $year."-".$month."-1";
    return date("t", strtotime($date));
}

This would output following:

echo get_number_of_days_in_month(2,2014);

Output: 28

I have wrapped it in my date time helper class here https://github.com/normandqq/Date-Time-Helper using $dateLastDay = Model_DTHpr::getLastDayOfTheMonth();

And it is done

2 lines code and you are done:

$oDate = new DateTime("2019-11-23");

// now your date object has been updated with last day of month    
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));

// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");