The best solution I have found is this:
function subtracMonth($currentMonth, $monthsToSubtract){
$finalMonth = $currentMonth;
for($i=0;$i<$monthsToSubtract;$i++) {
$finalMonth--;
if ($finalMonth=='0'){
$finalMonth = '12';
}
}
return $finalMonth;
}
So if we are in 3(March) and we want to subtract 5 months that would be
subtractMonth(3,5);
which would give 10(October). If the year is also desired, one could do this:
function subtracMonth($currentMonth, $monthsToSubtract){
$finalMonth = $currentMonth;
$totalYearsToSubtract = 0;
for($i=0;$i<$monthsToSubtract;$i++) {
$finalMonth--;
if ($finalMonth=='0'){
$finalMonth = '12';
$totalYearsToSubtract++;
}
}
//Get $currentYear
//Calculate $finalYear = $currentYear - $totalYearsToSubtract
//Put resulting $finalMonth and $finalYear into an object as attributes
//Return the object
}