In Java, char is technically a "16-bit integer", so you can simply cast it to int and you'll get it's code. From Oracle:
The char data type is a single 16-bit Unicode character. It has a minimum value of '\u0000' (or 0) and a maximum value of '\uffff' (or 65,535 inclusive).
So you can simply cast it to int.
char registered = '®';
System.out.println(String.format("This is an int-code: %d", (int) registered));
System.out.println(String.format("And this is an hexa code: %x", (int) registered));
There is an open source library MgntUtils that has a Utility class StringUnicodeEncoderDecoder. That class provides static methods that convert any String into Unicode sequence vise-versa. Very simple and useful. To convert String you just do:
String codes = StringUnicodeEncoderDecoder.encodeStringToUnicodeSequence(myString);
For example a String "Hello World" will be converted into
"\u0048\u0065\u006c\u006c\u006f\u0020\u0057\u006f\u0072\u006c\u0064"
It works with any language. Here is the link to the article that explains all te ditails about the library: MgntUtils. Look for the subtitle "String Unicode converter". The library could be obtained as a Maven artifact or taken from Github (including source code and Javadoc)
For me, only "Integer.toHexString(registered)" worked the way I wanted:
char registered = '®';
System.out.println("Answer:"+Integer.toHexString(registered));
This answer will give you only string representations what are usually presented in the tables. Jon Skeet's answer explains more.
A more complete, albeit more verbose, way of doing this would be to use the Character.codePointAt method. This will handle 'high surrogate' characters, that cannot be represented by a single integer within the range that a char
can represent.
In the example you've given this is not strictly necessary - if the (Unicode) character can fit inside a single (Java) char
(such as the registered
local variable) then it must fall within the \u0000
to \uffff
range, and you won't need to worry about surrogate pairs. But if you're looking at potentially higher code points, from within a String/char array, then calling this method is wise in order to cover the edge cases.
For example, instead of
String input = ...;
char fifthChar = input.charAt(4);
int codePoint = (int)fifthChar;
use
String input = ...;
int codePoint = Character.codePointAt(input, 4);
Not only is this slightly less code in this instance, but it will handle detection of surrogate pairs for you.
dear friend, Jon Skeet said you can find character Decimal codebut it is not character Hex code as it should mention in unicode, so you should represent character codes via HexCode not in Deciaml.
there is an open source tool at http://unicode.codeplex.com that provides complete information about a characer or a sentece.
so it is better to create a parser that give a char as a parameter and return ahexCode as string
public static String GetHexCode(char character)
{
return String.format("{0:X4}", GetDecimal(character));
}//end
hope it help
Source: Stackoverflow.com