How to resolve TypeError can only concatenate str not int to str

Question

I decided to make some kind of secret code for testing purposes with Unicode  I ve done that by adding numbers to Unicode so it would be kind of secret  I ve been getting this error  but I don t know how to solve it    Is there any solution     Original Code  message   input  Enter a message you want to be revealed     secret string      for char in message      secret string    str chr char   7429146   print  Revealed   secret string  q   input       Original Error  --------------------------------------------------------------------------- TypeError                                 Traceback  most recent call last   lt ipython-input-182-49ece294a581 gt  in  lt module gt        2 secret string            3 for char in message  ---- gt  4     secret string    str chr char   7429146         5 print  Revealed   secret string        6 q   input      TypeError  can only concatenate str  not  int   to str   Updated code  while True      try          message   int input  Enter a message you want to be decrypt              break     except ValueError          print  Error  it must be an integer   secret string      for char in message      secret string    chr ord char - str 742146    print  Decrypted   secret string  q   input

User · Answer

Change secret string    str chr char   7429146    To secret string    chr ord char    7429146   ord   converts the character to its Unicode integer equivalent  chr   then converts this integer into its Unicode character equivalent   Also  7429146 is too big of a number  it should be less than 1114111

User · Answer

Use this   print  Program for calculating sum   numbers  1  2  3  4  5  6  7  8  sum 0 for number in numbers      sum    number print  Total Sum is   d   sum

User · Answer

Use f-strings to resolve the TypeError  f-Strings  A New and Improved Way to Format Strings in Python PEP 498 - Literal String Interpolation    the following line causes a TypeError   test    Here is a test that can be run    15    times     same intent with a f-string i   15  test   f Here is a test that can be run  i  times   print test     output  Here is a test that can be run 15 times   i   15   t    test    i    will cause a TypeError    should be t   f test i    print t     output  test15    The issue may be attempting to evaluate an expression where a variable is the string of a numeric  Convert the string to an int  This scenario is specific to this question When iterating  it s important to be aware of the dtype  i    15    t   15   i    will cause a TypeError    convert the string to int t   15   int i  print t     output 30  Note  The preceding part of the answer addresses the TypeError shown in the question title  which is why people seem to be coming to this question  However  this doesn t resolve the issue in relation to the example provided by the OP  which is addressed below   Original Code Issues  TypeError is caused because message type is a str  The code iterates each character and attempts to add char  a str type  to an int That issue can be resolved by converting char to an int As the code is presented  secret string needs to be initialized with 0 instead of  quot  quot   The code also results in a ValueError  chr   arg not in range 0x110000  because 7429146 is out of range for chr    Resolved by using a smaller number The output is not a string  as was intended  which leads to the Updated Code in the question   message   input  quot Enter a message you want to be revealed   quot    secret string   0  for char in message      char   int char      value   char   742146     secret string    ord chr value        print f  nRevealed   secret string       Output Enter a message you want to be revealed   999  Revealed  2226465  Updated Code Issues  message is now an int type  so for char in message  causes TypeError   int  object is not iterable message is converted to int to make sure the input is an int  Set the type with str   Only convert value to Unicode with chr Don t use ord  while True      try          message   str int input  quot Enter a message you want to be decrypt   quot             break     except ValueError          print  quot Error  it must be an integer quot            secret string    quot  quot  for char in message           value   int char    10000          secret string    chr value   print  quot Decrypted quot   secret string     output Enter a message you want to be decrypt   999 Decrypted      Enter a message you want to be decrypt   100 Decrypted

User · Answer

Problem is you are doing the following   str chr char   7429146     where char is a string  You cannot add a int with a string  this will cause that error  maybe if you want to get the ascii code and add it with a constant number  if so   you can just do ord char  and add it to a number  but again  chr can take values between 0 and 1114112

User · Answer

instead of using       operator  print   Alireza    1980    Use comma       operator  print   Alireza    1980

User · Answer

Python working a bit differently to JavaScript for example  the value you are concatenating needs to be same type  both int or str      So for example the code below throw an error   print   Alireza    1980    like this   Traceback  most recent call last     File   lt pyshell 12 gt    line 1  in  lt module gt      print   Alireza    1980  TypeError  can only concatenate str  not  int   to str   To solve the issue  just add str to your number or value like   print   Alireza    str 1980     And the result as   Alireza1980

[python] How to resolve TypeError: can only concatenate str (not "int") to str

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