How to convert an int to a hex string

Question

I want to take an integer  that will be  lt   255   to a hex string representation  e g   I want to pass in 65 and get out   x41   or 255 and get   xff    I ve tried doing this with the struct pack  c  65   but that chokes on anything above 9 since it wants to take in a single character string

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This will convert an integer to a 2 digit hex string with the 0x prefix   strHex    0x 0 2X    255

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This worked best for me   0x 02X    5      gt  0x05  0x 02X    17     gt  0x11   Change the  2  if you want a number with a bigger width  2 is for 2 hex printned chars  so 3 will give you the following   0x 03X    5      gt  0x005  0x 03X    17     gt  0x011

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I wanted a random integer converted into a six-digit hex string with a   at the beginning   To get this I used     6x    random randint 0xFFFFFF

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Try    0x x    255     gt  0xff   or   0x X    255     gt  0xFF   Python Documentation says   keep this under Your pillow  http   docs python org library index html

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What about hex     hex 255     0xff   If you really want to have   in front you can do   print        hex 255  1

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You are looking for the chr function   You seem to be mixing decimal representations of integers and hex representations of integers  so it s not entirely clear what you need  Based on the description you gave  I think one of these snippets shows what you want    gt  gt  gt  chr 0x65       x65  True    gt  gt  gt  hex 65   0x41   gt  gt  gt  chr 65       x41  True   Note that this is quite different from a string containing an integer as hex  If that is what you want  use the hex builtin

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Note that for large values  hex   still works  some other answers don t    x   hex 349593196107334030177678842158399357  print x    Python 2  0x4354467b746f6f5f736d616c6c3f7dL Python 3  0x4354467b746f6f5f736d616c6c3f7d  For a decrypted RSA message  one could do the following   import binascii  hexadecimals   hex 349593196107334030177678842158399357   print binascii unhexlify hexadecimals 2 -1      python 2 print binascii unhexlify hexadecimals 2       python 3

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int variable  to bytes bytes length  byteorder  big   little   hex     For example    gt  gt  gt   434  to bytes 4  byteorder  big   hex    000001b2   gt  gt  gt   434  to bytes 4  byteorder  little   hex    b2010000

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Also you can convert any number in any base to hex  Use this one line code here it s easy and simple to use   hex int n x   replace  0x       You have a string n that is your number and x  the base of that number  First  change it to integer and then to hex but hex has 0x at the first of it so with replace we remove it

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If you want to pack a struct with a value  lt 255  one byte unsigned  uint8 t  and end up with a string of one character  you re probably looking for the format B instead of c  C converts a character to a string  not too useful by itself  while B converts an integer   struct pack  B   65     And yes  65 is  x41  not  x65    The struct class will also conveniently handle endianness for communication or other uses

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As an alternative representation you could use   in    s    hex 15   out  0xf

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Let me add this one  because sometimes you just want the single digit representation   x can be lower   x   or uppercase   X   the choice determines if the output letters are upper or lower       x   format 15   gt  f  And now with the new f   format strings you can do  f  15 x    gt  f  To add 0 padding you can use 0 gt n  f  2034 0 gt 4X    gt  07F2   NOTE  the initial  f  in f  15 x   is to signify a format string

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With format    as per format-examples  we can do    gt  gt  gt    format also supports binary numbers  gt  gt  gt   int   0 d    hex   0 x    oct   0 o    bin   0 b   format 42   int  42   hex  2a   oct  52   bin  101010   gt  gt  gt    with 0x  0o  or 0b as prefix   gt  gt  gt   int   0 d    hex   0  x    oct   0  o    bin   0  b   format 42   int  42   hex  0x2a   oct  0o52   bin  0b101010

[python] How to convert an int to a hex string?

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