As others stated, it's likely failing because the requested key doesn't exist in the array. I have a helper function here that takes the array, the suspected key, as well as a default return in the event the key does not exist.
protected function _getArrayValue($array, $key, $default = null)
{
if (isset($array[$key])) return $array[$key];
return $default;
}
hope it helps.
$value = ( array_key_exists($key, $array) && !empty($array[$key]) )
? $array[$key]
: 'non-existant or empty value key';
It should work the way you intended.
$array = array('value-0', 'value-1', 'value-2', 'value-3', 'value-4', 'value-5' /* … */);
$key = 4;
$value = $array[$key];
echo $value; // value-4
But maybe there is no element with the key 4
. If you want to get the fiveth item no matter what key it has, you can use array_slice
:
$value = array_slice($array, 4, 1);
Source: Stackoverflow.com