I have a file that looks something like this:
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
I want it to look like this (remove indentations):
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
How can this be done (using sed
maybe?)?
For this specific problem, something like this would work:
$ sed 's/^ *//g' < input.txt > output.txt
It says to replace all spaces at the start of a line with nothing. If you also want to remove tabs, change it to this:
$ sed 's/^[ \t]+//g' < input.txt > output.txt
The leading "s" before the / means "substitute". The /'s are the delimiters for the patterns. The data between the first two /'s are the pattern to match, and the data between the second and third / is the data to replace it with. In this case you're replacing it with nothing. The "g" after the final slash means to do it "globally", ie: over the entire file rather than on only the first match it finds.
Finally, instead of < input.txt > output.txt
you can use the -i
option which means to edit the file "in place". Meaning, you don't need to create a second file to contain your result. If you use this option you will lose your original file.
For what it's worth, if you are editing this file, you can probably highlight all the lines and use your un-tab button.
I am not sure if there is some requirement that this must be done from the command line. If so, then :thumbs-up: to the accepted answer! =)
Use:
sed -e **'s/^[ \t]*//'** name_of_file_from_which_you_want_to_remove_space > 'name _file_where_you_want_to_store_output'
For example:
sed -e 's/^[ \t]*//' file1.txt > output.txt
Note:
s/
: Substitute command ~ replacement for pattern (^[ \t]*
) on each addressed line
^[ \t]*
: Search pattern ( ^ – start of the line; [ \t]*
match one or more blank spaces including tab)
//
: Replace (delete) all matched patterns
You can use AWK:
$ awk '{$1=$1}1' file
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
$ sed 's|^[[:blank:]]*||g' file
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
for (i = 0; i < 100; i++)
while
/read
loopwhile read -r line
do
echo $line
done <"file"
Here you go:
user@host:~$ sed 's/^[\t ]*//g' < file-in.txt
Or:
user@host:~$ sed 's/^[\t ]*//g' < file-in.txt > file-out.txt
This Perl code edits your original file:
perl -i -ne 's/^\s+//;print' file
The next one makes a backup copy before editing the original file:
perl -i.bak -ne 's/^\s+//;print' file
Notice that Perl borrows heavily from sed (and AWK).
Source: Stackoverflow.com