[php] Add number of days to a date

I want to add number of days to current date: I am using following code:

$i=30;
echo $date = strtotime(date("Y-m-d", strtotime($date)) . " +".$i."days");

But instead of getting proper date i am getting this: 2592000

Please suggest.

This question is related to php date

The answer is


You could also try:

$date->modify("+30 days");


You could use the DateTime class built in PHP. It has a method called "add", and how it is used is thoroughly demonstrated in the manual: http://www.php.net/manual/en/datetime.add.php

It however requires PHP 5.3.0.


I know this is an old question, but for PHP <5.3 you could try this:

$date = '05/07/2013';
$add_days = 7;
$date = date('Y-m-d',strtotime($date) + (24*3600*$add_days)); //my preferred method
//or
$date = date('Y-m-d',strtotime($date.' +'.$add_days.' days');

Keep in mind, the change of clock changes because of daylight saving time might give you some problems when only calculating the days.

Here's a little php function which takes care of that:

function add_days($date, $days) {
    $timeStamp = strtotime(date('Y-m-d',$date));
    $timeStamp+= 24 * 60 * 60 * $days;

    // ...clock change....
    if (date("I",$timeStamp) != date("I",$date)) {
        if (date("I",$date)=="1") { 
            // summer to winter, add an hour
            $timeStamp+= 60 * 60; 
        } else {
            // summer to winter, deduct an hour
            $timeStamp-= 60 * 60;           
        } // if
    } // if
    $cur_dat = mktime(0, 0, 0, 
                      date("n", $timeStamp), 
                      date("j", $timeStamp), 
                      date("Y", $timeStamp)
                     ); 
    return $cur_dat;
}

//Set time zone
date_default_timezone_set("asia/kolkata");
$pastdate='2016-07-20';
$addYear=1;
$addMonth=3;
$addWeek=2;
$addDays=5;
$newdate=date('Y-m-d', strtotime($pastdate.' +'.$addYear.' years +'.$addMonth. ' months +'.$addWeek.' weeks +'.$addDays.' days'));
echo $newdate;

Use the following code.

<?php echo date('Y-m-d', strtotime(' + 5 days')); ?>

Reference has found from here - How to Add Days to Current Date in PHP


You can use strtotime()
$data['created'] = date('Y-m-d H:m:s', strtotime('+1 week'));


You can do it by manipulating the timecode or by using strtotime(). Here's an example using strtotime.

$data['created'] = date('Y-m-d H:i:s', strtotime("+1 week"));


//add the two day

$date = "**2-4-2016**"; //stored into date to variable

echo date("d-m-Y",strtotime($date.**' +2 days'**));

//print output
**4-4-2016**

Use this addDate() function to add or subtract days, month or years (you will need the auxiliar function reformatDate() as well)

/**
 * $date self explanatory
 * $diff the difference to add or subtract: e.g. '2 days' or '-1 month'
 * $format the format for $date
 **/
    function addDate($date = '', $diff = '', $format = "d/m/Y") {
        if (empty($date) || empty($diff))
            return false;
        $formatedDate = reformatDate($date, $format, $to_format = 'Y-m-d H:i:s');
        $newdate = strtotime($diff, strtotime($formatedDate));
        return date($format, $newdate);
    }
    //Aux function
    function reformatDate($date, $from_format = 'd/m/Y', $to_format = 'Y-m-d') {
        $date_aux = date_create_from_format($from_format, $date);
        return date_format($date_aux,$to_format);
    }

Note: only for php >=5.3


$date = "04/28/2013 07:30:00";

$dates = explode(" ",$date);

$date = strtotime($dates[0]);

$date = strtotime("+6 days", $date);

echo date('m/d/Y', $date)." ".$dates[1];

You may try this.

$i=30;
echo  date("Y-m-d",mktime(0,0,0,date('m'),date('d')+$i,date('Y')));

$today=date('d-m-Y');
$next_date= date('d-m-Y', strtotime($today. ' + 90 days'));
echo $next_date;

$date = new DateTime();
$date->modify('+1 week');
print $date->format('Y-m-d H:i:s');

or print date('Y-m-d H:i:s', mktime(date("H"), date("i"), date("s"), date("m"), date("d") + 7, date("Y"));


Simple and Best

echo date('Y-m-d H:i:s')."\n";
echo "<br>";
echo date('Y-m-d H:i:s', mktime(date('H'),date('i'),date('s'), date('m'),date('d')+30,date('Y')))."\n";

Try this


You can add like this as well, if you want the date 5 days from a specific date :

You have a variable with a date like this (gotten from an input or DB or just hard coded):

$today = "2015-06-15"; // Or can put $today = date ("Y-m-d");

$fiveDays = date ("Y-m-d", strtotime ($today ."+5 days"));

echo $fiveDays; // Will output 2015-06-20

This one might be good

function addDayswithdate($date,$days){

    $date = strtotime("+".$days." days", strtotime($date));
    return  date("Y-m-d", $date);

}

Even though this is an old question, this way of doing it would take of many situations and seems to be robust. You need to have PHP 5.3.0 or above.

$EndDateTime = DateTime::createFromFormat('d/m/Y', "16/07/2017");
$EndDateTime->modify('+6 days');
echo $EndDateTime->format('d/m/Y');

You can have any type of format for the date string and this would work.