[c++] Replace part of a string with another string

Is it possible in C++ to replace part of a string with another string?

Basically, I would like to do this:

QString string("hello $name");
string.replace("$name", "Somename");

But I would like to use the Standard C++ libraries.

To have the new string returned use this:

std::string ReplaceString(std::string subject, const std::string& search,
                          const std::string& replace) {
    size_t pos = 0;
    while ((pos = subject.find(search, pos)) != std::string::npos) {
         subject.replace(pos, search.length(), replace);
         pos += replace.length();
    }
    return subject;
}

If you need performance, here is an optimized function that modifies the input string, it does not create a copy of the string:

void ReplaceStringInPlace(std::string& subject, const std::string& search,
                          const std::string& replace) {
    size_t pos = 0;
    while ((pos = subject.find(search, pos)) != std::string::npos) {
         subject.replace(pos, search.length(), replace);
         pos += replace.length();
    }
}

Tests:

std::string input = "abc abc def";
std::cout << "Input string: " << input << std::endl;

std::cout << "ReplaceString() return value: " 
          << ReplaceString(input, "bc", "!!") << std::endl;
std::cout << "ReplaceString() input string not modified: " 
          << input << std::endl;

ReplaceStringInPlace(input, "bc", "??");
std::cout << "ReplaceStringInPlace() input string modified: " 
          << input << std::endl;

Output:

Input string: abc abc def
ReplaceString() return value: a!! a!! def
ReplaceString() input string not modified: abc abc def
ReplaceStringInPlace() input string modified: a?? a?? def

I use generally this:

std::string& replace(std::string& s, const std::string& from, const std::string& to)
{
    if(!from.empty())
        for(size_t pos = 0; (pos = s.find(from, pos)) != std::string::npos; pos += to.size())
            s.replace(pos, from.size(), to);
    return s;
}

It repeatedly calls std::string::find() to locate other occurrences of the searched for string until std::string::find() doesn't find anything. Because std::string::find() returns the position of the match we don't have the problem of invalidating iterators.

If all strings are std::string, you'll find strange problems with the cutoff of characters if using sizeof() because it's meant for C strings, not C++ strings. The fix is to use the .size() class method of std::string.

sHaystack.replace(sHaystack.find(sNeedle), sNeedle.size(), sReplace);

That replaces sHaystack inline -- no need to do an = assignment back on that.

Example usage:

std::string sHaystack = "This is %XXX% test.";
std::string sNeedle = "%XXX%";
std::string sReplace = "my special";
sHaystack.replace(sHaystack.find(sNeedle),sNeedle.size(),sReplace);
std::cout << sHaystack << std::endl;

std::string replace(std::string base, const std::string from, const std::string to) {
    std::string SecureCopy = base;

    for (size_t start_pos = SecureCopy.find(from); start_pos != std::string::npos; start_pos = SecureCopy.find(from,start_pos))
    {
        SecureCopy.replace(start_pos, from.length(), to);
    }

    return SecureCopy;
}

My own implementation, taking into account that string needs to be resized only once, then replace can happen.

template <typename T>
std::basic_string<T> replaceAll(const std::basic_string<T>& s, const T* from, const T* to)
{
    auto length = std::char_traits<T>::length;
    size_t toLen = length(to), fromLen = length(from), delta = toLen - fromLen;
    bool pass = false;
    std::string ns = s;

    size_t newLen = ns.length();

    for (bool estimate : { true, false })
    {
        size_t pos = 0;

        for (; (pos = ns.find(from, pos)) != std::string::npos; pos++)
        {
            if (estimate)
            {
                newLen += delta;
                pos += fromLen;
            }
            else
            {
                ns.replace(pos, fromLen, to);
                pos += delta;
            }
        }

        if (estimate)
            ns.resize(newLen);
    }

    return ns;
}

Usage could be for example like this:

std::string dirSuite = replaceAll(replaceAll(relPath.parent_path().u8string(), "\\", "/"), ":", "");

Yes, you can do it, but you have to find the position of the first string with string's find() member, and then replace with it's replace() member.

string s("hello $name");
size_type pos = s.find( "$name" );
if ( pos != string::npos ) {
   s.replace( pos, 5, "somename" );   // 5 = length( $name )
}

If you are planning on using the Standard Library, you should really get hold of a copy of the book The C++ Standard Library which covers all this stuff very well.

I'm just now learning C++, but editing some of the code previously posted, I'd probably use something like this. This gives you the flexibility to replace 1 or multiple instances, and also lets you specify the start point.

using namespace std;

// returns number of replacements made in string
long strReplace(string& str, const string& from, const string& to, size_t start = 0, long count = -1) {
    if (from.empty()) return 0;

    size_t startpos = str.find(from, start);
    long replaceCount = 0;

    while (startpos != string::npos){
        str.replace(startpos, from.length(), to);
        startpos += to.length();
        replaceCount++;

        if (count > 0 && replaceCount >= count) break;
        startpos = str.find(from, startpos);
    }

    return replaceCount;
}

This sounds like an option

string.replace(string.find("%s"), string("%s").size(), "Something");

You could wrap this in a function but this one-line solution sounds acceptable. The problem is that this will change the first occurence only, you might want to loop over it, but it also allows you to insert several variables into this string with the same token (%s)

This could be even better to use

void replace(string& input, const string& from, const string& to)
{
    while(true)
    {
        size_t startPosition = input.find(from);
        if(startPosition == string::npos)
            break;
        input.replace(startPosition, from.length(), to);
    }
}

std::string has a replace method, is that what you are looking for?

You could try:

s.replace(s.find("$name"), sizeof("$name") - 1, "Somename");

I haven't tried myself, just read the documentation on find() and replace().

You can use this code for remove subtring and also replace , and also remove extra white space . code :

#include<bits/stdc++.h>
using namespace std ;
void removeSpaces(string &str)
{
   
    int n = str.length();

    int i = 0, j = -1;

    bool spaceFound = false;

    while (++j <= n && str[j] == ' ');

    while (j <= n)
    {
        if (str[j] != ' ')
        {
          
            if ((str[j] == '.' || str[j] == ',' ||
                 str[j] == '?') && i - 1 >= 0 &&
                 str[i - 1] == ' ')
                str[i - 1] = str[j++];

            else
                
                str[i++] = str[j++];

            
            spaceFound = false;
        }
        else if (str[j++] == ' ')
        {
            
            if (!spaceFound)
            {
                str[i++] = ' ';
                spaceFound = true;
            }
        }
    }

    if (i <= 1)
        str.erase(str.begin() + i, str.end());
    else
        str.erase(str.begin() + i - 1, str.end());
}
int main()
{
    string s;
    cin>>s;
    for(int i=s.find("WUB");i>=0;i=s.find("WUB"))
    {
        s.replace(i,3," ");
    }
    removeSpaces(s);
    cout<<s<<endl;

    return 0;
}

With C++11 you can use std::regex like so:

#include <regex>
...
std::string string("hello $name");
string = std::regex_replace(string, std::regex("\\$name"), "Somename");

The double backslash is required for escaping an escape character.

If you want to do it quickly you can use a two scan approach. Pseudo code:

1. first parse. find how many matching chars.
2. expand the length of the string.
3. second parse. Start from the end of the string when we get a match we replace, else we just copy the chars from the first string.

I am not sure if this can be optimized to an in-place algo.

And a C++11 code example but I only search for one char.

#include <string>
#include <iostream>
#include <algorithm>
using namespace std;

void ReplaceString(string& subject, char search, const string& replace)
{   
    size_t initSize = subject.size();
    int count = 0;
    for (auto c : subject) { 
        if (c == search) ++count;
    }

    size_t idx = subject.size()-1 + count * replace.size()-1;
    subject.resize(idx + 1, '\0');

    string reverseReplace{ replace };
    reverse(reverseReplace.begin(), reverseReplace.end());  

    char *end_ptr = &subject[initSize - 1];
    while (end_ptr >= &subject[0])
    {
        if (*end_ptr == search) {
            for (auto c : reverseReplace) {
                subject[idx - 1] = c;
                --idx;              
            }           
        }
        else {
            subject[idx - 1] = *end_ptr;
            --idx;
        }
        --end_ptr;
    }
}

int main()
{
    string s{ "Mr John Smith" };
    ReplaceString(s, ' ', "%20");
    cout << s << "\n";

}

wstring myString = L"Hello $$ this is an example. By $$.";
wstring search = L"$$";
wstring replace = L"Tom";
for (int i = myString.find(search); i >= 0; i = myString.find(search))
    myString.replace(i, search.size(), replace);