[c++] declaring a priority_queue in c++ with a custom comparator

I'm trying to declare a priority_queue of nodes, using bool Compare(Node a, Node b) as the comparator function (which is outside the node class).

What I currently have is:

priority_queue<Node, vector<Node>, Compare> openSet;

For some reason, I'm getting Error: "Compare" is not a type name

Changing the declaration to priority_queue <Node, vector<Node>, bool Compare>

gives me Error: expected a '>'

I've also tried:

priority_queue<Node, vector<Node>, Compare()> openSet;
priority_queue<Node, vector<Node>, bool Compare()> openSet;
priority_queue<Node, vector<Node>, Compare<Node, Node>> openSet; 

How should I correctly declare my priority_queue?

prefer struct, and it's what std::greater do

struct Compare {
  bool operator()(Node const&, Node &) {}
}

The accepted answer makes you believe that you must use a class or a std::function as comparator. This is not true! As cute_ptr's answer shows, you can pass a function pointer to the constructor. However, the syntax to do so is much simpler than shown there:

class Node;
bool Compare(Node a, Node b);

std::priority_queue<Node, std::vector<Node>, decltype(&Compare)> openSet(Compare);

That is, there is no need to explicitly encode the function's type, you can let the compiler do that for you using decltype.

This is very useful if the comparator is a lambda. You cannot specify the type of a lambda in any other way than using decltype. For example:

auto compare = [](Node a, Node b) { return a.foo < b.foo; }
std::priority_queue<Node, std::vector<Node>, decltype(compare)> openSet(compare);

One can also use a lambda function.

auto Compare = [](Node &a, Node &b) { //compare };
std::priority_queue<Node, std::vector<Node>, decltype(Compare)> openset(Compare);

You have to define the compare first. There are 3 ways to do that:

1. use class
2. use struct (which is same as class)
3. use lambda function.

It's easy to use class/struct because easy to declare just write this line of code above your executing code

struct compare{
  public:
  bool operator()(Node& a,Node& b) // overloading both operators 
  {
      return a.w < b.w: // if you want increasing order;(i.e increasing for minPQ)
      return a.w > b.w // if you want reverse of default order;(i.e decreasing for minPQ)
   }
};

Calling code:

priority_queue<Node,vector<Node>,compare> pq;

Answering your question directly:

I'm trying to declare a priority_queue of nodes, using bool Compare(Node a, Node b) as the comparator function

What I currently have is:

priority_queue<Node, vector<Node>, Compare> openSet;

For some reason, I'm getting Error:

"Compare" is not a type name

The compiler is telling you exactly what's wrong: Compare is not a type name, but an instance of a function that takes two Nodes and returns a bool.
What you need is to specify the function pointer type:
std::priority_queue<Node, std::vector<Node>, bool (*)(Node, Node)> openSet(Compare)

The third template parameter must be a class who has operator()(Node,Node) overloaded. So you will have to create a class this way:

class ComparisonClass {
    bool operator() (Node, Node) {
        //comparison code here
    }
};

And then you will use this class as the third template parameter like this:

priority_queue<Node, vector<Node>, ComparisonClass> q;

In case this helps anyone :

static bool myFunction(Node& p1, Node& p2) {}
priority_queue <Node, vector<Node>, function<bool(Node&, Node&)>> pq1(myFunction);