How to convert char to int

Question

What is the proper way to convert a char to int  This gives 49   int val   Convert ToInt32  1      int val   Int32 Parse  1       Works   I don t want to convert to string and then parse it

User · Answer

int val    1  -  0     This can be done using ascii codes where  0  is the lowest and the number characters count up from there

User · Answer

int i    int char GetNumericValue c     Yet another option   int i   c  amp  0x0f    This should accomplish this as well

User · Answer

how about  for char c   int i    int  c -  0      which does substraction of the char value   Re the API question  comments   perhaps an extension method   public static class CharExtensions       public static int ParseInt32 this char value            int i    int  value -  0            if  i  lt  0    i  gt  9  throw new ArgumentOutOfRangeException  value            return i            then use int x   c ParseInt32

User · Answer

The most secure way to accomplish this is using Int32 TryParse method  See here  http   dotnetperls com int-tryparse

User · Answer

What everyone is forgeting is explaining WHY this happens    A Char  is basically an integer  but with a pointer in the ASCII table  All characters have a corresponding integer value as you can clearly see when trying to parse it    Pranay has clearly a different character set  thats why HIS code doesnt work   the only way is   int val    1  -  0     because this looks up the integer value in the table of  0  which is then the  base value   subtracting your number in char format from this will give you the original number

User · Answer

int val    1  - 48

User · Answer

An extension of some other answers that covers hexadecimal representation   public int CharToInt char c         if  c  gt    0   amp  amp  c  lt    9                  return c -  0             else if  c  gt    a   amp  amp  c  lt    f                  return 10   c -  a             else if  c  gt    A   amp  amp  c  lt    F                  return 10   c -  A              return -1

User · Answer

You can try something like this   int val   Convert ToInt32       1

User · Answer

int val    1   amp  15    The binary of the ASCII charecters 0-9 is   0     -     00110000  1     -     00110001  2     -     00110010  3     -     00110011  4     -     00110100  5     -     00110101  6     -     00110110  7     -     00110111  8     -     00111000  9     -     00111001  and if you take in each one of them the first 4 LSB using bitwise AND with 8 b00001111 that equels to 15  you get the actual number  0000   0 0001 1 0010 2

User · Answer

You may use the following extension method   public static class CharExtensions               public static int CharToInt this char c                        if  c  lt   0     c  gt   9                   throw new ArgumentException  The character should be a number    c                 return c -  0

User · Answer

I m surprised nobody has mentioned the static method built right into System Char     int val    int Char GetNumericValue  8       val    8

[c#] How to convert char to int?

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