Adding days to Date in PHP

Question

I have a date returned as part of a mySQL query in the form 2010-09-17  I would like to set the variables  Date2 to  Date5 as follows    Date2    Date   1   Date3    Date   2  etc    so that it returns 2010-09-18  2010-09-19 etc     I have tried   date  Y-m-d   strtotime  Date      1 day      but this gives me the date BEFORE  Date   What is the correct way to get my Dates in the format form  Y-m-d  so that they may be used in another query

User · Answer

If you re using PHP 5 3  you can use a DateTime object and its add method    Date1    2010-09-17    date   new DateTime  Date1    date- gt add new DateInterval  P1D        P1D means a period of 1 day  Date2    date- gt format  Y-m-d      Take a look at the DateInterval constructor manual page to see how to construct other periods to add to your date  2 days would be  P2D   3 would be  P3D   and so on    Without PHP 5 3  you should be able to use strtotime the way you did it  I ve tested it and it works in both 5 1 6 and 5 2 10     Date1    2010-09-17    Date2   date  Y-m-d   strtotime  Date1       1 day        var dump  Date2  returns  2010-09-18

User · Answer

You can also use the following format  strtotime  -3 days   time     strtotime   1 day   strtotime  date      You can stack changes this way   strtotime   1 day   strtotime   1 year   strtotime  date       Note the difference between this approach and the one in other answers  instead of concatenating the values  1 day and  lt timestamp gt   you can just pass in the timestamp as the second parameter of strtotime

User · Answer

From PHP 5 2 on you can use modify with a DateTime object   http   php net manual en datetime modify php   Date1    2010-09-17    date   new DateTime  Date1    date- gt modify   1 day     Date2    date- gt format  Y-m-d      Be careful when adding months     and to a lesser extent  years

User · Answer

All have to use bellow code    nday   time       24   60   60       echo  Now           date  Y-m-d      n       echo  Next Day     date  Y-m-d    nday     n

User · Answer

Here has an easy way to solve this    lt  php     date    2015-11-17      echo date  Y-m-d   strtotime  date      5 days       gt    Output will be   2015-11-22   Solution has found from here - How to Add Days to Date in PHP

User · Answer

Here is a small snippet to demonstrate the date modifications    date   date  Y-m-d      increment 2 days  mod date   strtotime  date    2 days    echo date  Y-m-d   mod date      n      decrement 2 days  mod date   strtotime  date  - 2 days    echo date  Y-m-d   mod date      n      increment 1 month  mod date   strtotime  date    1 months    echo date  Y-m-d   mod date      n      increment 1 year  mod date   strtotime  date    1 years    echo date  Y-m-d   mod date      n

User · Answer

Here is the simplest solution to your query   date date create  2013-03-15       or your date string date add  date date interval create from date string  40 days       add number of days  echo date format  date  Y-m-d      set date format of the result

User · Answer

All you have to do is use days instead of day like this    lt  php  Date    2010-09-17   echo date  Y-m-d   strtotime  Date      1 days     echo date  Y-m-d   strtotime  Date      2 days       gt    And it outputs correctly   2010-09-18 2010-09-19

User · Answer

Using a variable for Number of days  myDate    quot 2014-01-16 quot    nDays   16   newDate   strtotime  myDate         nDays  days    echo new Date  d m Y    soma     format new date

[php] Adding days to $Date in PHP

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