How to pass all arguments passed to my bash script to a function of mine

Question

Let s say I have defined a function abc   that will handle the logic related to analyzing the arguments passed to my script   How can I pass all arguments my bash script has received to it  The number of params is variable  so I can t just hardcode the arguments passed like this   abc  1  2  3  4   Edit  Better yet  is there any way for my function to have access to the script arguments  variables

User · Answer

It s worth mentioning that you can specify argument ranges with this syntax   function example         echo  line1     1 1     First argument     echo  line2     2 1     Second argument     echo  line3     3     Third argument onwards     I hadn t seen it mentioned

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abc      is generally the correct answer  But I was trying to pass a parameter through to an su command  and no amount of quoting could stop the error su  unrecognized option  --myoption    What actually worked for me was passing all the arguments as a single string    abc        My exact case  I m sure someone else needs this  was in my  bashrc    run all aws commands as Jenkins user aws          sudo su jenkins -c  aws

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Here s a simple script      bin bash  args         echo Number of arguments     echo 1st argument    args 0   echo 2nd argument    args 1        is the number of arguments received by the script  I find easier to access them using an array  the args        line puts all the arguments in the args array  To access them use   args index

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The    variable expands to all command-line parameters separated by spaces   Here is an example  abc  quot    quot   When using     you should  almost  always put it in double-quotes to avoid misparsing of arguments containing spaces or wildcards  see below    This works for multiple arguments  It is also portable to all POSIX-compliant shells  It is also worth nothing that  0  generally the script s name or path  is not in     The Bash Reference Manual Special Parameters Section says that    expands to the positional parameters starting from one   When the expansion occurs within double quotes  each parameter expands to a separate word   That is  quot    quot  is equivalent to  quot  1 quot   quot  2 quot   quot  3 quot      Passing some arguments  If you want to pass all but the first arguments  you can first use shift to  quot consume quot  the first argument and then pass  quot    quot  to pass the remaining arguments to another command   In bash  and zsh and ksh  but not in plain POSIX shells like dash   you can do this without messing with the argument list using a variant of array slicing   quot     3  quot  will get you the arguments starting with  quot  3 quot     quot     3 4  quot  will get you up to four arguments starting at  quot  3 quot   i e   quot  3 quot   quot  4 quot   quot  5 quot   quot  6 quot    if that many arguments were passed  Things you probably don t want to do   quot    quot  gives all of the arguments stuck together into a single string  separated by spaces  or whatever the first character of  IFS is   This looses the distinction between spaces within arguments and the spaces between arguments  so is generally a bad idea  Although it might be ok for printing the arguments  e g  echo  quot    quot   provided you don t care about preserving the space within between distinction  Assigning the arguments to a regular variable  as in args  quot    quot   mashes all the arguments together just like  quot    quot  does  If you want to store the arguments in a variable  use an array with args   quot    quot    the parentheses make it an array   and then reference them as e g   quot   args 0   quot  etc  note that bash array indexes start at 0  so  1 will be in args 0   etc   Leaving off the double-quotes  with either    or     will try to split each argument up into separate words  based on whitespace or whatever s in  IFS   and also try to expand anything that looks like a filename wildcard into a list of matching filenames  This can have really weird effects  and should almost always be avoided

User · Answer

abc           represents all the parameters given to your bash script

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I needed a variation on this  which I expect will be useful to others   function diffs             diff      3    lt  sort   1    lt  sort   2       The      3   part means all the members of the array starting at 3   So this function implements a sorted diff by passing the first two arguments to diff through sort and then passing all other arguments to diff  so you can call it similarly to diff   diffs file1 file2  other diff args  e g  -y

User · Answer

Use the    variable  which expands to all command-line parameters separated by spaces   abc

[bash] How to pass all arguments passed to my bash script to a function of mine?

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