Casting an int to a string in Python

Question

I want to be able to generate a number of text files with the names fileX txt where X is some integer   for i in range key       filename    ME    i     txt    Error here  Can t concat a string and int     filenum   filename     filenum   open filename    w       Does anyone else know how to do the filename    ME    i  part so I get a list of files with the names   ME0 txt     ME1 txt     ME2 txt    and etc

User · Answer

Either    ME    str i    Or    ME d    i   The second one is usually preferred  especially if you want to build a string from several tokens

User · Answer

You can use str   to cast it  or formatters    ME d txt     num

User · Answer

Here answer for your code as whole   key  10  files     ME i txt    i for i in range key     opening files     open filename   w   for filename in files     processing for i  file in zip range key  files       file write str i     closing for openfile in files      openfile close

User · Answer

For Python versions prior to 2 6  use the string formatting operator     filename    ME d txt    i   For 2 6 and later  use the str format   method   filename    ME 0  txt  format i    Though the first example still works in 2 6  the second one is preferred   If you have more than 10 files to name this way  you might want to add leading zeros so that the files are ordered correctly in directory listings   filename    ME 02d txt    i filename    ME 0 02d  txt  format i    This will produce file names like ME00 txt to ME99 txt  For more digits  replace the 2 in the examples with a higher number  eg  ME 0 03d  txt

User · Answer

x   1 y    foo    str x    Please see the Python documentation  https   docs python org 2 library functions html str

[python] Casting an int to a string in Python

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