[php] Get the current script file name

If I have PHP script, how can I get the filename from inside that script?

Also, given the name of a script of the form jquery.js.php, how can I extract just the "jquery.js" part?

This might help:

basename($_SERVER['PHP_SELF'])

it will work even if you are using include.

This works for me, even when run inside an included PHP file, and you want the filename of the current php file running:

$currentPage= $_SERVER["SCRIPT_NAME"];
$currentPage = substr($currentPage, 1);
echo $currentPage;

Result:

index.php

$argv[0]

I've found it much simpler to use $argv[0]. The name of the executing script is always the first element in the $argv array. Unlike all other methods suggested in other answers, this method does not require the use of basename() to remove the directory tree. For example:

• echo __FILE__; returns something like /my/directory/path/my_script.php

• echo $argv[0]; returns my_script.php

$filename = "jquery.js.php";
$ext = pathinfo($filename, PATHINFO_EXTENSION);//will output: php
$file_basename = pathinfo($filename, PATHINFO_FILENAME);//will output: jquery.js

Try This

$current_file_name = $_SERVER['PHP_SELF'];
echo $current_file_name;

A more general way would be using pathinfo(). Since Version 5.2 it supports PATHINFO_FILENAME.

So

pathinfo(__FILE__,PATHINFO_FILENAME)

will also do what you need.

you can also use this:

echo $pageName = basename($_SERVER['SCRIPT_NAME']);

See http://php.net/manual/en/function.pathinfo.php

pathinfo(__FILE__, PATHINFO_FILENAME);

alex's answer is correct but you could also do this without regular expressions like so:

str_replace(".php", "", basename($_SERVER["SCRIPT_NAME"]));

As some said basename($_SERVER["SCRIPT_FILENAME"], '.php') and basename( __FILE__, '.php') are good ways to test this.

To me using the second was the solution for some validation instructions I was making

Try this

$file = basename($_SERVER['PATH_INFO']);//Filename requested

When you want your include to know what file it is in (ie. what script name was actually requested), use:

basename($_SERVER["SCRIPT_FILENAME"], '.php')

Because when you are writing to a file you usually know its name.

Edit: As noted by Alec Teal, if you use symlinks it will show the symlink name instead.

__FILE__ use examples based on localhost server results:

echo __FILE__;
// C:\LocalServer\www\templates\page.php

echo strrchr( __FILE__ , '\\' );
// \page.php

echo substr( strrchr( __FILE__ , '\\' ), 1);
// page.php

echo basename(__FILE__, '.php');
// page

Here is a list what I've found recently searching an answer:

//self name with file extension
echo basename(__FILE__) . '<br>';
//self name without file extension
echo basename(__FILE__, '.php') . '<br>';
//self full url with file extension
echo __FILE__ . '<br>';

//parent file parent folder name
echo basename($_SERVER["REQUEST_URI"]) . '<br>';
//parent file parent folder name with //s
echo $_SERVER["REQUEST_URI"] . '<br>';

// parent file name without file extension
echo basename($_SERVER['PHP_SELF'], ".php") . '<br>';
// parent file name with file extension
echo basename($_SERVER['PHP_SELF']) . '<br>';
// parent file relative url with file etension
echo $_SERVER['PHP_SELF'] . '<br>';

// parent file name without file extension
echo basename($_SERVER["SCRIPT_FILENAME"], '.php') . '<br>';
// parent file name with file extension
echo basename($_SERVER["SCRIPT_FILENAME"]) . '<br>';
// parent file full url with file extension
echo $_SERVER["SCRIPT_FILENAME"] . '<br>';

//self name without file extension
echo pathinfo(__FILE__, PATHINFO_FILENAME) . '<br>';
//self file extension
echo pathinfo(__FILE__, PATHINFO_EXTENSION) . '<br>';

// parent file name with file extension
echo basename($_SERVER['SCRIPT_NAME']);

Don't forget to remove :)

<br>

Here is the difference between basename(__FILE__, ".php") and basename($_SERVER['REQUEST_URI'], ".php").

basename(__FILE__, ".php") shows the name of the file where this code is included - It means that if you include this code in header.php and current page is index.php, it will return header not index.

basename($_SERVER["REQUEST_URI"], ".php") - If you use include this code in header.php and current page is index.php, it will return index not header.