How do I split an int into its digits

Question

How can I split an int in c   to its single numbers  For example  I d like to split 23 to 2 and 3

User · Accepted Answer

Given the number 12345    5 is 12345   10 4 is 12345   10   10 3 is 12345   100   10 2 is 12345   1000   10 1 is 12345   10000   10  I won t provide a complete code as this surely looks like homework  but I m sure you get the pattern

User · Answer

Start with the highest power of ten that fits into an int on your platform  for 32 bit int  1 000 000 000  and perform an integer division by it  The result is the leftmost digit  Subtract this result multipled with the divisor from the original number  then continue the same game with the next lower power of ten and iterate until you reach 1

User · Answer

Based on icecrime s answer I wrote this function  std  vector lt int gt  intToDigits int num         std  vector lt int gt  ret      string iStr   to string num         for  int i   iStr size   - 1  i  gt   0  --i                int units   pow 10  i           int digit   num    units   10          ret push back digit                 return ret

User · Answer

You can just use a sequence of x 10 0f and std  floor operations to have  math approach   Or you can also use boost  lexical cast the number  to obtain a string and then you can simply do the string c str   i  to access the individual characters  the  string approach

User · Answer

cast it to a string or char   and loop on it

User · Answer

You can count how many digits you want to print first    include  lt iostream gt   include  lt cmath gt  using namespace std   int main    int number  result  counter 0  zeros   do      cout  lt  lt   Introduce un numero entero       cin  gt  gt  number      while  number  lt  0         We count how many digits we are going print   for int i   number  i  gt  0  i   i 10          counter        while number  gt  0           zeros   pow 10  counter - 1           result   number   zeros         number   number   zeros         counter--            Muestra resultados        cout  lt  lt       lt  lt  result          cout lt  lt endl

User · Answer

int n   1234  std  string nstr   std  to string n   std  cout  lt  lt  nstr 0      nstr 0  - gt  1   I think this is the easiest way   We need to use std  to string   function to convert our int to string so it will automatically create the array with our digits  We can access them simply using index - nstr 0  will show 1

User · Answer

the classic trick is to use modulo 10  x 10 gives you the first digit ie the units digit   For others  you ll need to divide first as shown by many other posts already   Here s a little function to get all the digits into a vector which is what you seem to want to do    using namespace std  vector lt int gt  digits int x       vector lt int gt  returnValue      while x gt  10           returnValue push back x 10    take digit         x x 10    or x  10 if you like brevity             don t forget the last digit      returnValue push back x       return returnValue

User · Answer

Declare an Array and store Individual digits to the array like this  int num  temp  digits   0  s  td 1  int d 10   cout  lt  lt   Enter the Number     cin  gt  gt  num  temp   num  do        digits      temp    10    while  temp    for  int i   0  i  lt  digits-1  i          td    10     s   num  for  int i   0  i  lt  digits  i          d i    s   td  10      td    10

User · Answer

Reversed order digit extractor  eg  for 23 will be 3 and 2    while  number  gt  0        int digit   number 10      number    10        print digit     Normal order digit extractor  eg  for 23 will be 2 and 3    std  stack lt int gt  sd   while  number  gt  0        int digit   number 10      number    10      sd push digit      while   sd empty          int digit   sd top        sd pop          print digit

User · Answer

The following will do the trick  void splitNumber std  list lt int gt  amp  digits  int number      if  0    number         digits push back 0       else       while  number    0          int last   number   10        digits push front last         number    number - last    10

User · Answer

int power int n  int b        int number      number   pow n  b       return number      void NumberOfDigits         int n  a      printf  Eneter number  n        scanf s   d    amp n       int i   0      do          i          while  n   pow 10  i   gt  1       printf  Number of digits is   t  d  n   i        for  int j   i-1  j  gt   0  j--            a   n   power 10  j    10          printf   d  n   a            int main void        NumberOfDigits

User · Answer

I don t necessarily recommend this  it s more efficient to work with the number rather than converting it to a string   but it s easy and it works      include  lt algorithm gt   include  lt iostream gt   include  lt iterator gt   include  lt string gt    include  lt boost lexical cast hpp gt   int main         int n   23984      std  string s   boost  lexical cast lt std  string gt  n       std  copy s begin    s end    std  ostream iterator lt char gt  std  cout    n         return 0

User · Answer

include  lt iostream gt   using namespace std   int main        int n1    cout  lt  lt  quot Please enter five digits number   quot   cin  gt  gt  n1       cout  lt  lt  n1   10000   10  lt  lt   quot   quot       cout  lt  lt  n1   1000   10  lt  lt   quot   quot       cout  lt  lt  n1   100   10  lt  lt   quot   quot       cout  lt  lt  n1   10   10  lt  lt   quot   quot       cout  lt  lt  n1   10  lt  lt   quot     quot       cout  lt  lt  endl   return 0

User · Answer

A simple answer to this question can be    Read A Number  n  From The User  Using While Loop Make Sure Its Not Zero  Take modulus 10 Of The Number  n   This Will Give You Its Last Digit  Then Divide The Number  n  By 10  This Removes The Last Digit of Number  n  since in int decimal part is omitted  Display Out The Number    I Think It Will Help  I Used Simple Code Like    include  lt iostream gt  using namespace std  int main    int n r       cout lt  lt  Enter Your Number        cin gt  gt n        while n  0                       r n 10                 n n 10                  cout lt  lt r            cout lt  lt endl       system  PAUSE        return 0

User · Answer

int n   say 12345 string s  scanf   d   amp n   sprintf s   5d  n     Now you can access each digit via s 0   s 1   etc

[c++] How do I split an int into its digits?

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