python Appending a dictionary to a list - I see a pointer like behavior

Question

I tried the following in the python interpreter    gt  gt  gt   gt  gt  gt  a       gt  gt  gt  b    1  one    gt  gt  gt  a append b   gt  gt  gt  a   1   one     gt  gt  gt  b 1     ONE   gt  gt  gt  a   1   ONE     gt  gt  gt    Here  after appending the dictionary  b  to the list  a   I m changing the value corresponding to the key 1 in dictionary  a   Somehow this change gets reflected in the list too  When I append a dictionary to a list  am I not just appending the value of dictionary  It looks as if I have appended a pointer to the dictionary to the list and hence the changes to the dictionary are getting reflected in the list too   I do not want the change to get reflected in the list  How do I do it   Thank you for your time

User · Accepted Answer

You are correct in that your list contains a reference to the original dictionary.

a.append(b.copy()) should do the trick.

Bear in mind that this makes a shallow copy. An alternative is to use copy.deepcopy(b), which makes a deep copy.

User · Answer

Also with dict  a      b    1  one    a append dict b   print a b 1   iuqsdgf  print a   result    1   one      1   one

User · Answer

use copy and deep copy     http   docs python org library copy html

[python] python: Appending a dictionary to a list - I see a pointer like behavior

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