If it's always going to be an even LHS/RHS split, you can also use the partition
method that's built into strings. It returns a 3-tuple as (LHS, separator, RHS)
if the separator is found, and (original_string, '', '')
if the separator wasn't present:
>>> "2.7.0_bf4fda703454".partition('_')
('2.7.0', '_', 'bf4fda703454')
>>> "shazam".partition("_")
('shazam', '', '')