The correct answer is:
Blah.find({}).sort({date: -1}).execFind(function(err,docs){
});
You can also sort by the _id
field. For example, to get the most recent record, you can do,
const mostRecentRecord = await db.collection.findOne().sort({ _id: -1 });
It's much quicker too, because I'm more than willing to bet that your date
field is not indexed.
See if this helps > How to sort in mongoose?
Also read this > http://www.mongodb.org/display/DOCS/Sorting+and+Natural+Order
ES6 solution with Koa.
async recent() {
data = await ReadSchema.find({}, { sort: 'created_at' });
ctx.body = data;
}
I do this:
Data.find( { $query: { user: req.user }, $orderby: { dateAdded: -1 } } function ( results ) {
...
})
This will show the most recent things first.
Been dealing with this issue today using Mongoose 3.5(.2) and none of the answers quite helped me solve this issue. The following code snippet does the trick
Post.find().sort('-posted').find(function (err, posts) {
// user posts array
});
You can send any standard parameters you need to find()
(e.g. where clauses and return fields) but no callback. Without a callback it returns a Query object which you chain sort()
on. You need to call find()
again (with or without more parameters -- shouldn't need any for efficiency reasons) which will allow you to get the result set in your callback.
Post.find().sort({date:-1}, function(err, posts){
});
Should work as well
EDIT:
You can also try using this if you get the error sort() only takes 1 Argument
:
Post.find({}, {
'_id': 0, // select keys to return here
}, {sort: '-date'}, function(err, posts) {
// use it here
});
This one works for me.
`Post.find().sort({postedon: -1}).find(function (err, sortedposts){
if (err)
return res.status(500).send({ message: "No Posts." });
res.status(200).send({sortedposts : sortedposts});
});`
Short solution:
const query = {}
const projection = {}
const options = { sort: { id: 1 }, limit: 2, skip: 10 }
Room.find(query, projection, options).exec(function(err, docs) { ... });
Source: Stackoverflow.com