How to create an array for JSON using PHP

Question

From PHP code I want to create an json array         region   valore   price   valore2        region   valore   price   valore2        region   valore   price   valore2       How can I do this

User · Answer

Just typing this single line would give you a json array ,

echo json_encode($array);

Normally you use json_encode to read data from an ios or android app. so make sure you do not echo anything else other than the accurate json array.

User · Answer

Simple  Just create a  nested  PHP array and call json encode on it  Numeric arrays translate into JSON lists       associative arrays and PHP objects translate into objects       Example    a   array          array  foo    gt   bar            array  foo    gt   baz      json   json encode  a     Gives you      foo   bar     foo   baz

User · Answer

I created a crude and simple jsonOBJ class to use for my code  PHP does not include json functions like JavaScript Node do  You have to iterate differently  but may be helpful    lt  php     define a JSON Object class class jsonOBJ       private   arr      private   arrName       function   construct  arrName            this- gt  arrName    arrName           this- gt  arr  this- gt  arrName    array                function toArray   return  this- gt  arr       function toString   return json encode  this- gt  arr         function push  newObjectElement            this- gt  arr  this- gt  arrName       newObjectElement     array  key   val             function add  key  val            this- gt  arr  this- gt  arrName      array  key  gt  val               create an instance of the object  jsonObj   new jsonOBJ  locations        add items using one of two methods  jsonObj- gt push json decode     location     TestLoc1     true       from a JSON String  jsonObj- gt push json decode     location     TestLoc2     true      jsonObj- gt add  location   TestLoc3       from key val pairs  echo   lt pre gt     print r  jsonObj- gt toArray   1      lt  pre gt    echo   lt br   gt      jsonObj- gt toString      gt    Will output   Array        locations    gt  Array                        0    gt  Array                                        location    gt  TestLoc1                                 1    gt  Array                                        location    gt  TestLoc2                                 2    gt  Array                                        location    gt  TestLoc3                                     locations     location   TestLoc1     location   TestLoc2     location   TestLoc3       To iterate  convert to a normal object    myObj    jsonObj- gt toArray      Then   foreach  myObj  locations   as  locationObj       echo  locationObj  location      lt br   gt        Outputs   TestLoc1 TestLoc2 TestLoc3  Access direct    location    myObj  locations   0   location     location    myObj  locations   1   location      A practical example      return a JSON Object  jsonOBJ  from the rows     function ParseRowsAsJSONObject  arrName   rowRS            jsonArr   new jsonOBJ  arrName      name of the json array           rows   mysqli num rows  rowRS           if  rows  gt  0               while  rows  gt  0                    rd   mysqli fetch assoc  rowRS                    jsonArr- gt push  rd                    rows--                            mysqli free result  rowRS                     return  jsonArr- gt toArray

User · Answer

also for array you can use short annotattion    arr                    region    gt   valore            price    gt   valore2                        region    gt   valore            price    gt   valore2                        region    gt   valore            price    gt   valore2            echo json encode  arr

User · Answer

That s how I am able to do with the help of solution given by  tdammers below   The following line will be placed inside foreach loop    array     array  power    gt  trim  Some value     time    gt   time here       And then encode the array with json encode function  json encode array  newvalue   gt   array   200

User · Answer

Best way that you should go every time for creating json in php is to first convert values in ASSOCIATIVE array   After that just simply encode using json encode  associativeArray   I think it is the best way to create json in php because whenever we are fetching result form sql query in php most of the time we got values using fetch assoc function  which also return one associative array    associativeArray   array     associativeArray   FirstValue      FirstValue         etc   After that   json encode  associativeArray

User · Answer

json data       Languages        English    Spanish         lang data   json decode  json data   var dump  lang data

User · Answer

Use PHP s native json encode  like this    lt  php  arr   array      array           region    gt   valore            price    gt   valore2             array           region    gt   valore            price    gt   valore2             array           region    gt   valore            price    gt   valore2            echo json encode  arr     gt      Update  To answer your question in the comment  You do it like this    named array   array       nome array    gt  array          array               foo    gt   bar                     array               foo    gt   baz                     echo json encode  named array

User · Answer

lt  php        username urldecode   POST  log user           user  select   from tbl registration where member id      username            rsuser    obj- gt select  user       if count  rsuser  gt 0                      Status if 2 then its expire      1  use    0   not use            cheknew  select name ldate offer photo  from tbl offer where status 1             rscheknew    obj- gt selectjson  cheknew            if count  rscheknew  gt 0                           nik json encode  rscheknew               echo     status       200      responce       201      message       Get Record     feed     str replace   lt p gt       nik                          else                        row2  No Record Found                nik1 json encode  row2               echo     status       202       responce       604     message       No Record Found      feed     str replace   lt p gt       nik1                            else                row2  Invlid User            nik1 json encode  row2           echo     status       404      responce       602     message       Invlid User      feed     str replace   lt p gt       nik1                  gt

User · Answer

Easy peasy lemon squeezy  http   www php net manual en function json-encode php   lt  php  arr   array  a    gt  1   b    gt  2   c    gt  3   d    gt  4   e    gt  5    echo json encode  arr     gt    There s a post by andyrusterholz at g-m-a-i-l dot c-o-m on the aforementioned page that can also handle complex nested arrays  if that s your thing

[php] How to create an array for JSON using PHP?

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