[php] json_decode() expects parameter 1 to be string, array given

What causes this error in my code?

$query = $this->db->query("SELECT * FROM tour_foreign ORDER BY id desc");
        $data = array();
        foreach ($query->result() as $row)
            $data[] = array('guide' => $row->guide);

            echo json_decode($data); //Line 167

error:

erro: json_decode() expects parameter 1 to be string, array given: Line Number: 167

UPDATE:

If I use json_encode instead of json_decode, my output is this:

[{"guide":["\u0633\u06cc\u062f \u0633\u0639\u06cc\u062f \u062f\u0627\u062f\u0627\u0634\u0632\u0627\u062f\u0647"]},{"guide":["\u0633\u06c??c\u062f \u0633\u0639\u06cc\u062f \u062f\u0627\u062f\u0627\u0634\u0632\u0627\u062f\u0647"]},{"guide":null}]

They are persian words.

here is the solution for similar problem which i was facing while extracting name from user profile facebook json object

$uname=json_encode($userprof);
$uname=json_decode($uname);
echo "Welcome " . $uname -> name  ;

Set decoding to true

Your decoding is not set to true. If you don't have access to set the source to true. The code below will fix it for you.

$WorkingArray = json_decode(json_encode($data),true);

json_decode() is used to decode a json string to an array/data object. json_encode() creates a json string from an array or data. You are using the wrong function my friend, try json_encode();

Ok I was running into the same issue. What I failed to notice is that I was using json_decode() instead of using json_encode() so for those who are going to come here please make sure you are using the right function, which is json_encode()

Note: Depends on what you are working on but make sure you are using the right function.

• Make an object

  $obj = json_decode(json_encode($need_to_json));

• Show data from this $obj

  $obj->{'needed'};

Reference