I was trying a simple piece of code, get someone's name and age and let him/her know when they turn 21... not considering negatives and all that, just random.
I keep getting this 'int' object is not subscriptable
error.
name1 = raw_input("What's your name? ")
age1 = raw_input ("how old are you? ")
x = 0
int([x[age1]])
twentyone = 21 - x
print "Hi, " + name1+ " you will be 21 in: " + twentyone + " years."
This question is related to
python
python-2.7
type-conversion
x is already integer(x=0) and again you trying to make x again integer and also you gave indexing which is beyound the limit because x already has only one indexing (0) and you are trying to give indexing same as age so thats why you get this error. use this simple code
name1 = input("What's your name? ")
age1 = int(input ("how old are you?" ))
x=0
twentyone = str(21-age1)
print("Hi, " +name1+ " you will be 21 in: " + twentyone + " years.")
'int' object is not subscriptable is TypeError in Python. To better understand how this error occurs, let us consider the following example:
list1 = [1, 2, 3]
print(list1[0][0])
If we run the code, you will receive the same TypeError in Python3.
TypeError: 'int' object is not subscriptable
Here the index of the list is out of range. If the code was modified to:
print(list1[0])
The output will be 1(as indexing in Python Lists starts at zero), as now the index of the list is in range.
1
When the code(given alongside the question) is run, the TypeError occurs and it points to line 4 of the code :
int([x[age1]])
The intention may have been to create a list of an integer number(although creating a list for a single number was not at all required). What was required was that to just assign the input(which in turn converted to integer) to a variable.
Hence, it's better to code this way:
name = input("What's your name? ")
age = int(input('How old are you? '))
twenty_one = 21 - age
if(twenty_one < 0):
print('Hi {0}, you are above 21 years' .format(name))
elif(twenty_one == 0):
print('Hi {0}, you are 21 years old' .format(name))
else:
print('Hi {0}, you will be 21 years in {1} year(s)' .format(name, twenty_one))
The output:
What's your name? Steve
How old are you? 21
Hi Steve, you are 21 years old
name1 = input("What's your name? ")
age1 = int(input ("how old are you? "))
twentyone = str(21 - int(age1))
if age1<21:
print ("Hi, " + name1+ " you will be 21 in: " + twentyone + " years.")
else:
print("You are over the age of 21")
What are you trying to do here: int([x[age1]])
?? It makes no sense.
You just have to cast the age input as an int
:
name1 = raw_input("What's your name? ")
age1 = raw_input ("how old are you? ")
twentyone = 21 - int(age1)
print "Hi, %s you will be 21 in: %d years." % (name1, twentyone)
You need to convert age1 into int first, so it can do the minus. After that turn the result back to string for display:
name1 = raw_input("What's your name? ")
age1 = raw_input ("how old are you? ")
twentyone = str(21 - int(age1))
print "Hi, " + name1+ " you will be 21 in: " + twentyone + " years."
When you type x = 0
that is creating a new int
variable (name) and assigning a zero to it.
When you type x[age1]
that is trying to access the age1
'th entry, as if x
were an array.
Here is a more modern way of doing this:
name1 : str = input("What's your name? ")
age1 : int = int(input ("how old are you? "))
twentyone : int = 21 - age1
print('Hi, {}, you will be 21 in: {} years'.format(name1, twentyone))
It would be a lot more simple just to do this;
name = input("What's your name? ")
age = int(input("How old are you? "))
print ("Hi,{0} you will be 21 in {1} years.".format(name, 21 - age))`
When you write x = 0
, x
is an int...so you can't do x[age1]
because x
is int
Source: Stackoverflow.com