[c#] How to put a new line into a wpf TextBlock control?

I'm fetching text from an XML file, and I'd like to insert some new lines that are interpreted by the textblock render as new lines.

I've tried:

<data>Foo bar baz \n baz bar</data>

But the data is still displayed without the new line. I set the contents of <data> via the .Text property via C#.

What do I need to put in the XML in order for it to render the new line in the GUI?

I've tried something like this manually setting the text in the XAML:

<TextBlock Margin="0 15 0 0" Width="600">
There &#10;
is a new line.
</TextBlock>

And while the encoded character doesn't appear in the GUI it also doesn't give me a new line.

Even though this is an old question, I've just come across the problem and solved it differently from the given answers. Maybe it could be helpful to others.

I noticed that even though my XML files looked like:

<tag>
 <subTag>content with newline.\r\nto display</subTag>
</tag>

When it was read into my C# code the string had double backslashes.

\\r\\n

To fix this I wrote a ValueConverter to strip the extra backslash.

public class XmlStringConverter : IValueConverter
{
    public object Convert(
        object value,
        Type targetType,
        object parameter,
        CultureInfo culture)
    {
        string valueAsString = value as string;
        if (string.IsNullOrEmpty(valueAsString))
        {
            return value;
        }

        valueAsString = valueAsString.Replace("\\r\\n", "\r\n");
        return valueAsString;
    }

    public object ConvertBack(
        object value,
        Type targetType,
        object parameter,
        CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

<TextBlock Margin="4" TextWrapping="Wrap" FontFamily="Verdana" FontSize="12">
        <Run TextDecorations="StrikeThrough"> Run cannot contain inline</Run>
        <Span FontSize="16"> Span can contain Run or Span or whatever 
            <LineBreak />
        <Bold FontSize="22" FontFamily="Times New Roman" >Bold can contains 
            <Italic>Italic</Italic></Bold></Span>
</TextBlock>

Using System.Environment.NewLine is the only solution that worked for me. When I tried \r\n, it just repeated the actual \r\n in the text box.

You have to ensure that the textblock has this option enabled:

AcceptsReturn="True"

Insert a "line break" or a "paragraph break" in a RichTextBox "rtb" like this:

var range = new TextRange(rtb.SelectionStart, rtb.Selection.End); 
range.Start.Paragraph.ContentStart.InsertLineBreak();
range.Start.Paragraph.ContentStart.InsertParagraphBreak();

The only way to get the NewLine items is by inserting text with "\r\n" items first, and then applying more code which works on Selection and/or TextRange objects. This makes sure that the \par items are converted to \line items, are saved as desired, and are still correct when reopening the *.Rtf file. That is what I found so far after hard tries. My three code lines need to be surrounded by more code (with loops) to set the TextPointer items (.Start .End .ContentStart .ContentEnd) where the Lines and Breaks should go, which I have done with success for my purposes.

You can also use binding

<TextBlock Text="{Binding MyText}"/>

And set MyText like this:

Public string MyText
{
    get{return string.Format("My Text \n Your Text");}
}

If all else fails you can also use

"My text needs a line break here" + System.Environment.NewLine + " This should be a new line"

For completeness: You can also do this:

 <TextBlock Text="Line1&#x0a;Line 2"/>

x0A is the escaped hexadecimal Line Feed. The equivalent of \n

you must use

 < SomeObject xml:space="preserve" > once upon a time ...
      this line will be below the first one < /SomeObject>

Or if you prefer :

 <SomeObject xml:space="preserve" />  once upon a time... &#10; this line below < / SomeObject>

watch out : if you both use &10 AND you go to the next line in your text, you'll have TWO empty lines.

here for details : http://msdn.microsoft.com/en-us/library/ms788746.aspx