finding first day of the month in python

Question

I m trying to find the first day of the month in python with one condition  if my current date passed the 25th of the month  then the first date variable will hold the first date of the next month instead of the current month  I m doing the following   import datetime  todayDate   datetime date today   if  todayDate - todayDate replace day 1   days  gt  25      x  todayDate   datetime timedelta 30      x replace day 1      print x else      print todayDate replace day 1    is there a cleaner way for doing this

User · Answer

Use arrow   import arrow arrow utcnow   span  month   0

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Can be done on the same line using date replace   from datetime import datetime  datetime today   replace day 1

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from datetime import datetime  date today   datetime now   month first day   date today replace day 1  hour 0  minute 0  second 0  microsecond 0  print month first day

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My solution to find the first and last day of the current month   def find current month last day today  datetime  - gt  datetime      if today month    2          return today replace day 28       if today month in  4  6  9  11           return today replace day 30       return today replace day 31    def current month first and last days   - gt  tuple      today   datetime now   replace hour 0  minute 0  second 0  microsecond 0      first date   today replace day 1      last date   find current month last day today      return first date  last date

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The arrow module will steer you around and away from subtle mistakes  and it s easier to use that older products   import arrow  def cleanWay oneDate       if currentDate date   day  gt  25          return currentDate replace months  1 day 1      else          return currentDate replace day 1    currentDate   arrow get  25-Feb-2017    DD-MMM-YYYY   print  currentDate format  DD-MMM-YYYY    cleanWay currentDate  format  DD-MMM-YYYY     currentDate   arrow get  28-Feb-2017    DD-MMM-YYYY   print  currentDate format  DD-MMM-YYYY    cleanWay currentDate  format  DD-MMM-YYYY      In this case there is no need for you to consider the varying lengths of months  for instance  Here s the output from this script   25-Feb-2017 01-Feb-2017 28-Feb-2017 01-Mar-2017

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This could be an alternative to Gustavo Eduardo Belduma s answer   import datetime  first day of the month   datetime date today   replace day 1

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Yes  first set a datetime to the start of the current month   Second test if current date day   25 and get a true false on that  If True then add add one month to the start of month datetime object  If false then use the datetime object with the value set to the beginning of the month   import datetime  from dateutil relativedelta import relativedelta  todayDate   datetime date today   resultDate   todayDate replace day 1   if   todayDate - resultDate  days  gt  25       resultDate   resultDate   relativedelta months 1   print resultDate

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You can use dateutil rrule   In  1   from dateutil rrule import    In  2   rrule DAILY  bymonthday 1  0  date   Out 2   datetime date 2018  10  1   In  3   rrule DAILY  bymonthday 1  1  date   Out 3   datetime date 2018  11  1

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Use dateutil   from datetime import date from dateutil relativedelta import relativedelta  today   date today   first day   today replace day 1  if today day  gt  25      print first day   relativedelta months 1   else      print first day

User · Answer

This is a pithy solution    import datetime   todayDate   datetime date today   if todayDate day  gt  25      todayDate    datetime timedelta 7  print todayDate replace day 1    One thing to note with the original code example is that using timedelta 30  will cause trouble if you are testing the last day of January  That is why I am using a 7-day delta

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First day of next month  from datetime import datetime class SomeClassName models Model       if datetime now   month    12          new start month   1     else          new start month   datetime now   month   1  Then we replace the month and the day     start date   models DateField default datetime today   replace month new start month  day 1  hour 0  minute 0  second 0  microsecond 0

[python] finding first day of the month in python

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