[c] C - error: storage size of ‘a’ isn’t known

This is my C program...

#include <stdio.h>

struct xyx {
    int x;
    int y;
    char c;
    char str[20];
    int arr[2];
};

int main(void)
{
    struct xyz a;
    a.x = 100;
    printf("%d\n", a.x);
    return 0;
}

This is the error that I am getting....

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13structtest.c: In function ‘main’:
13structtest.c:13:13: error: storage size of ‘a’ isn’t known
13structtest.c:13:13: warning: unused variable ‘a’ [-Wunused-variable]

you define the struct as xyx but you're trying to create the struct called xyz.

You define your struct as xyx, however in your main, you use struct xyz a; , which only creates a forward declaration of a differently named struct.

Try using xyx a; instead of that line.

In this case the user has done mistake in definition and its usage. If someone has done a typedef to a structure the same should be used without using struct following is the example.

typedef struct
{
   int a;
}studyT;

When using in a function

int main()
{
   struct studyT study; // This will give above error.
   studyT stud; // This will eliminate the above error.
   return 0;
}

Say it like this: struct xyx a;

correct typo of

struct xyz a;

to

struct xyx a;

Better you can try typedef, easy to b

1)declare the structs before the main function. it worked for me. 2) And also fix the spelling mistake of that variable name if any e

To anyone with who is having this problem, its a typo error. Check your spelling of your struct delcerations and your struct

Your struct is called struct xyx but a is of type struct xyz. Once you fix that, the output is 100.

#include <stdio.h>

struct xyx {
    int x;
    int y;
    char c;
    char str[20];
    int arr[2];
};

int main(void)
{
    struct xyx a;
    a.x = 100;
    printf("%d\n", a.x);
    return 0;
}