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How do I treat an ASCII string as unicode and unescape the escaped characters in it in python?
How do convert unicode escape sequences to unicode characters in a python string
I have a string that contains unicode characters e.g. \u2026 etc. Somehow it is not received to me as unicode, but is received as a str. How do I convert it back to unicode?
>>> a="Hello\u2026"
>>> b=u"Hello\u2026"
>>> print a
Hello\u2026
>>> print b
Hello…
>>> print unicode(a)
Hello\u2026
>>>
So clearly unicode(a) is not the answer. Then what is?
This question is related to
python
string
unicode
python-2.x
python-unicode
Unicode escapes only work in unicode strings, so this
a="\u2026"
is actually a string of 6 characters: '\', 'u', '2', '0', '2', '6'.
To make unicode out of this, use decode('unicode-escape'):
a="\u2026"
print repr(a)
print repr(a.decode('unicode-escape'))
## '\\u2026'
## u'\u2026'
>>> a="Hello\u2026"
>>> print a.decode('unicode-escape')
Hello…
Decode it with the unicode-escape codec:
>>> a="Hello\u2026"
>>> a.decode('unicode-escape')
u'Hello\u2026'
>>> print _
Hello…
This is because for a non-unicode string the \u2026 is not recognised but is instead treated as a literal series of characters (to put it more clearly, 'Hello\\u2026'). You need to decode the escapes, and the unicode-escape codec can do that for you.
Note that you can get unicode to recognise it in the same way by specifying the codec argument:
>>> unicode(a, 'unicode-escape')
u'Hello\u2026'
But the a.decode() way is nicer.
Source: Stackoverflow.com