[c#] inherit from two classes in C#

Possible Duplicate:
Multiple Inheritance in C#

I have two classes Class A and Class B. These two classes cannot inherit each other. I am creating new class called Class C. Now, I want to implement the methods in class A and class B by inheriting. I am aware that multiple inheritance is not possible in C# but is there any other way to do this?

If you want to literally use the method code from A and B you can make your C class contain an instance of each. If you code against interfaces for A and B then your clients don't need to know you're giving them a C rather than an A or a B.

interface IA { void SomeMethodOnA(); }
interface IB { void SomeMethodOnB(); }
class A : IA { void SomeMethodOnA() { /* do something */ } }
class B : IB { void SomeMethodOnB() { /* do something */ } }
class C : IA, IB
{
    private IA a = new A();
    private IB b = new B();
    void SomeMethodOnA() { a.SomeMethodOnA(); }
    void SomeMethodOnB() { b.SomeMethodOnB(); }
}

Use composition:

class ClassC
{
    public ClassA A { get; set; }
    public ClassB B { get; set; }   

    public C (ClassA  a, ClassB  b)
    {
        this.A = a;
        this.B = b;
    }
}

Then you can call C.A.DoA(). You also can change the properties to an interface or abstract class, like public InterfaceA A or public AbstractClassA A.

Do you mean you want Class C to be the base class for A & B in that case.

public abstract class C
{
    public abstract void Method1();

    public abstract void Method2();
}

public class A : C
{
    public override void Method1()
    {
        throw new NotImplementedException();
    }

    public override void Method2()
    {
        throw new NotImplementedException();
    }
}


public class B : C
{
    public override void Method1()
    {
        throw new NotImplementedException();
    }

    public override void Method2()
    {
        throw new NotImplementedException();
    }
}

Make two interfaces IA and IB:

public interface IA
{
    public void methodA(int value);
}

public interface IB
{
    public void methodB(int value);
}

Next make A implement IA and B implement IB.

public class A : IA
{
    public int fooA { get; set; }
    public void methodA(int value) { fooA = value; }
}

public class B : IB
{
    public int fooB { get; set; }
    public void methodB(int value) { fooB = value; }
}

Then implement your C class as follows:

public class C : IA, IB
{
    private A _a;
    private B _b;

    public C(A _a, B _b)
    {
        this._a = _a;
        this._b = _b;
    }

    public void methodA(int value) { _a.methodA(value); }
    public void methodB(int value) { _b.methodB(value); }
}

Generally this is a poor design overall because you can have both A and B implement a method with the same name and variable types such as foo(int bar) and you will need to decide how to implement it, or if you just call foo(bar) on both _a and _b. As suggested elsewhere you should consider a .A and .B properties instead of combining the two classes.

An common alternative to inheritance is delegation (also called composition): X "has a" Y rather than X "is a" Y. So if A has functionality for dealing with Foos, and B has functionality for dealing with Bars, and you want both in C, then something like this:

public class A() {
  private FooManager fooManager = new FooManager(); // (or inject, if you have IoC)

  public void handleFoo(Foo foo) {
    fooManager.handleFoo(foo);
  }
}

public class B() {
  private BarManager barManager = new BarManager(); // (or inject, if you have IoC)

  public void handleBar(Bar bar) {
    barManager.handleBar(bar);
  }
}

public class C() {
  private FooManager fooManager = new FooManager(); // (or inject, if you have IoC)
  private BarManager barManager = new BarManager(); // (or inject, if you have IoC)

  ... etc
}

You can define a base class for A and B where you can hold a common methods/properties/fields of those.

After implement C:Base.

Or in order to simulate multiple inheritance, define a common interface(s) and implement them in C

Hope this helps.