How to check if a String contains any letter from a to z

Question

Possible Duplicate    C  Regex  Checking for    a-z    and    A-Z          I could just use the code below   String hello    Hello1   Char   convertedString   String ToCharArray    int errorCounter   0  for  int i   0  i  lt  CreateAccountPage PasswordBox Password Password Length  i          if  convertedString i  Equals  a      convertedString i  Equals  A                                        convertedString i  Equals  z      convertedString i  Equals  Z              errorCounter            if errorCounter  gt  0          do something     but I suppose it takes too much line for just a simple purpose  I believe there is a way which is much more simple  the way which I have not yet mastered

User · Answer

Use regular expression no need to convert it to char array  if Regex IsMatch  yourString       a-zA-Z          errorCounter

User · Answer

What about     true if it doesn t contain letters bool result   hello Any x   gt   char IsLetter x

User · Answer

Replace your for loop by this     errorCounter   Regex Matches yourstring    a-zA-Z    Count    Remember to use Regex class  you have to using System Text RegularExpressions  in your import

User · Answer

You could use RegEx   Regex IsMatch hello      a-zA-Z         If you don t like that  you can use LINQ   hello All Char IsLetter     Or  you can loop through the characters  and use isAlpha   Char IsLetter character

User · Answer

For a minimal change   for int i 0  i lt str Length  i        if str i   gt    a   amp  amp  str i   lt    z     str i   gt    A   amp  amp  str i   lt    Z         errorCount      You could use regular expressions  at least if speed is not an issue and you do not really need the actual exact count

User · Answer

You can look for regular expression   Regex IsMatch str      a-zA-Z

[c#] How to check if a String contains any letter from a to z?

Examples related to c#

Examples related to windows

Examples related to string

Examples related to char