Get the decimal part from a double

Question

I want to receive the number after the decimal dot in the form of an integer  For example  only 05 from 1 05 or from 2 50 only 50 not 0 50

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public static string FractionPart this double instance                var result   string Empty          var ic   CultureInfo InvariantCulture          var splits   instance ToString ic  Split new     ic NumberFormat NumberDecimalSeparator    StringSplitOptions RemoveEmptyEntries           if  splits Count    gt  1                        result   splits 1                     return result

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That may be overhead but should work   double yourDouble   1 05  string stringForm   yourDouble ToString    int dotPosition   stringForm IndexOf       decimal decimalPart   Decimal Parse  0    stringForm Substring dotPosition     Console WriteLine decimalPart      0 05

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Better Way -          double value   10 567          int result    int   value -  int value    100           Console WriteLine result     Output -   56

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the best of the best way is   var floatNumber   12 5523   var x   floatNumber - Math Truncate floatNumber     result you can convert however you like

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Why not use int y   value Split      1     The Split   function splits the value into separate content and the 1 is outputting the 2nd value after the

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Use a regex  Regex Match       d     Someone correct me if I m wrong here

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Here s an extension method I wrote for a similar situation  My application would receive numbers in the format of 2 3 or 3 11 where the integer component of the number represented years and the fractional component represented months      Sample Usage int years  months  double test1   2 11  test1 Split out years  out months      years   2 and months   11  public static class DoubleExtensions       public static void Split this double number  out int years  out int months                years   Convert ToInt32 Math Truncate number             double tempMonths   Math Round number - years  2           while   tempMonths - Math Floor tempMonths    gt  0  amp  amp  tempMonths    0  tempMonths    10          months   Convert ToInt32 tempMonths

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You may remove the dot   from the double you are trying to get the decimals from using the Remove   function after converting the double to string so that you could do the operations required on it  Consider having a double  Double of value of 0 66781  the following code will only show the numbers after the dot   which are 66781  double  Double   0 66781    Declare a new double with a value of 0 66781 string  Decimals    Double ToString   Remove 0   Double ToString   IndexOf        1     Remove everything starting with index 0 and ending at the index of   the dot      1     Another Solution  You may use the class Path as well which performs operations on string instances in a cross-platform manner  double  Double   0 66781    Declare a new double with a value of 0 66781 string Output   Path GetExtension D ToString    Replace            Get  the dot and the content after the last dot available and replace the dot with nothing  as a new string object Output   Do something

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string input    quot 0 55 quot       var regex1   new System Text RegularExpressions Regex  quot    lt         0-9   quot        if  regex1 IsMatch input                 string dp  regex1 Match input   Value

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var result   number ToString   Split System Globalization NumberDecimalSeparator  2    Returns it as a string  but you can always cast that back to an int   and assumes the number does have a     somewhere

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I guess this thread is getting old but I can t believe nobody has mentioned Math Floor    will always be  02 cents  10 02m - System Math Floor 10 02m

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The simplest variant is possibly with Math truncate    double value   1 761 double decPart   value - Math truncate value

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int last2digits   num -  int    double   num    100    100

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There is a cleaner and ways faster solution than the  Math Truncate  approach   double frac   value   1

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var decPlaces    int    decimal number   1    100     This presumes your number only has two decimal places

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Updated Answer    Here I am giving 3 approaches for the same    1  Math Solution using Math Truncate   var float number   12 345   var result   float number - Math Truncate float number        input    1 05    output    0 050000000000000044        input    10 2    output   0 19999999999999929  If this is not the result what you are expecting  then you have to change the result to the form which you want  but you might do some string manipulations again     2  using multiplier  which is 10 to the power of N  e g  10   or 10    where N is the number of decimal places             multiplier is   10 to the power of  N   where  N  is the number            of decimal places        int multiplier   1000           double double value   12 345         int double result    int   double value -  int double value    multiplier        output 345    If the number of decimal places is not fixed  then this approach may create problems    3  using  Regular Expressions  REGEX    we should be very careful while writing solutions with string  This would not be preferable except some cases   If you are going to do some string operations with decimal places  then this would be preferable      string input decimal number    1 50       var regex   new System Text RegularExpressions Regex     lt         0-9          if  regex IsMatch input decimal number                 string decimal places   regex Match input decimal number  Value             input      1 05     output     05      input      2 50     output     50      input      0 0550     output     0550   you can find more about Regex on http   www regexr com

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It is very simple          float moveWater    Mathf PingPong theTime   speed  100     015f         int    m    int  moveWater          float decimalPart  moveWater -m           Debug Log decimalPart

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Solution without rounding problem   double number   10 20  var first2DecimalPlaces    int    decimal number   1    100   Console Write   0 00    first2DecimalPlaces     Outputs  20     Note if we did not cast to decimal  it would output 19    Also    for 318 40 outputs  40  instead of 39  for 47 612345 outputs  61  instead of 612345  for 3 01 outputs  01  instead of 1       If you are working with financial numbers  for example if in this case you are trying to get the cents part of a transaction amount  always use the decimal data type    Update   The following will also work if processing it as a string  building on  SearchForKnowledge s answer    10 2d ToString  0 00   CultureInfo InvariantCulture  Split      1    You can then use Int32 Parse to convert it to int

[c#] Get the decimal part from a double

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