I want to remove square brackets from a string, but I don't know how.
String str = "[Chrissman-@1]";
str = replaceAll("\\[\\]", "");
String[] temp = str.split("-@");
System.out.println("Nickname: " + temp[0] + " | Power: " + temp[1]);
But my result is: [Chrissman | 1] The square brackets doesn't get removed.
I tried using a different regex: "\\[.*?\\]"
, "\\[\\d+\\]"
but the result is the same, the square brackets still attached on the string.
Edit:
I tried:
str.replaceAll("]", "");
str.replaceAll("[", "");
And now I'm getting:
Exception in thread "Thread-4" java.util.regex.PatternSyntaxException: Unclosed character class near index 0
[
^
at java.util.regex.Pattern.error(Unknown Source)
at java.util.regex.Pattern.clazz(Unknown Source)
at java.util.regex.Pattern.sequence(Unknown Source)
at java.util.regex.Pattern.expr(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.util.regex.Pattern.<init>(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.lang.String.replaceAll(Unknown Source)
You're currently trying to remove the exact string []
- two square brackets with nothing between them. Instead, you want to remove all [
and separately remove all ]
.
Personally I would avoid using replaceAll
here as it introduces more confusion due to the regex part - I'd use:
String replaced = original.replace("[", "").replace("]", "");
Only use the methods which take regular expressions if you really want to do full pattern matching. When you just want to replace all occurrences of a fixed string, replace
is simpler to read and understand.
(There are alternative approaches which use the regular expression form and really match patterns, but I think the above code is significantly simpler.)
Your regex matches (and removes) only subsequent square brackets. Use this instead:
str = str.replaceAll("\\[|\\]", "");
If you only want to replace bracket pairs with content in between, you could use this:
str = str.replaceAll("\\[(.*?)\\]", "$1");
Use this line:) String result = strCurBal.replaceAll("[(" what ever u need to remove ")]", "");_x000D_
_x000D_
String strCurBal = "(+)3428";_x000D_
Log.e("Agilanbu before omit ", strCurBal);_x000D_
String result = strCurBal.replaceAll("[()]", ""); // () removing special characters from string_x000D_
Log.e("Agilanbu after omit ", result);_x000D_
_x000D_
o/p :_x000D_
Agilanbu before omit : (+)3428_x000D_
Agilanbu after omit : +3428_x000D_
_x000D_
String finalVal = result.replaceAll("[+]", ""); // + removing special characters from string_x000D_
Log.e("Agilanbu finalVal ", finalVal);_x000D_
o/p_x000D_
Agilanbu finalVal : 3428_x000D_
_x000D_
String finalVal1 = result.replaceAll("[+]", "-"); // insert | append | replace the special characters from string_x000D_
Log.e("Agilanbu finalVal ", finalVal1);_x000D_
o/p_x000D_
Agilanbu finalVal : -3428 // replacing the + symbol to -
_x000D_
You may also do it like this:
String data = "[yourdata]";
String regex = "\\[|\\]";
data = data .replaceAll(regex, "");
System.out.println(data);
String str, str1;
Scanner sc = new Scanner(System.in);
System.out.print("Enter a String : ");
str = sc.nextLine();
str1 = str.replaceAll("[aeiouAEIOU]", "");
System.out.print(str1);
use regex [\\[\\]]
-
String str = "[Chrissman-@1]";
String[] temp = str.replaceAll("[\\[\\]]", "").split("-@");
System.out.println("Nickname: " + temp[0] + " | Power: " + temp[1]);
output -
Nickname: Chrissman | Power: 1
Source: Stackoverflow.com