How to do left join in Doctrine?

57

This is my function where I'm trying to show the User history. For this I need to display the user's current credits along with his credit history.

This is what I am trying to do:

 public function getHistory($users) {
    $qb = $this->entityManager->createQueryBuilder();
    $qb->select(array('a','u'))
            ->from('Credit\Entity\UserCreditHistory', 'a')
            ->leftJoin('User\Entity\User', 'u', \Doctrine\ORM\Query\Expr\Join::WITH, 'a.user = u.id')
            ->where("a.user = $users ")
            ->orderBy('a.created_at', 'DESC');

    $query = $qb->getQuery();
    $results = $query->getResult();

    return $results;
}

However, I get this error :

[Syntax Error] line 0, col 98: Error: Expected Doctrine\ORM\Query\Lexer::T_WITH, got 'ON'

Edit: I replaced 'ON' with 'WITH' in the join clause and now what I see is only 1 value from the joined column.

This question is tagged with php doctrine-orm zend-framework2

~ Asked on 2013-02-26 11:27:16

The Best Answer is


123

If you have an association on a property pointing to the user (let's say Credit\Entity\UserCreditHistory#user, picked from your example), then the syntax is quite simple:

public function getHistory($users) {
    $qb = $this->entityManager->createQueryBuilder();
    $qb
        ->select('a', 'u')
        ->from('Credit\Entity\UserCreditHistory', 'a')
        ->leftJoin('a.user', 'u')
        ->where('u = :user')
        ->setParameter('user', $users)
        ->orderBy('a.created_at', 'DESC');

    return $qb->getQuery()->getResult();
}

Since you are applying a condition on the joined result here, using a LEFT JOIN or simply JOIN is the same.

If no association is available, then the query looks like following

public function getHistory($users) {
    $qb = $this->entityManager->createQueryBuilder();
    $qb
        ->select('a', 'u')
        ->from('Credit\Entity\UserCreditHistory', 'a')
        ->leftJoin(
            'User\Entity\User',
            'u',
            \Doctrine\ORM\Query\Expr\Join::WITH,
            'a.user = u.id'
        )
        ->where('u = :user')
        ->setParameter('user', $users)
        ->orderBy('a.created_at', 'DESC');

    return $qb->getQuery()->getResult();
}

This will produce a resultset that looks like following:

array(
    array(
        0 => UserCreditHistory instance,
        1 => Userinstance,
    ),
    array(
        0 => UserCreditHistory instance,
        1 => Userinstance,
    ),
    // ...
)

~ Answered on 2013-02-26 11:42:38


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