This is my function where I'm trying to show the User history. For this I need to display the user's current credits along with his credit history.
This is what I am trying to do:
public function getHistory($users) {
$qb = $this->entityManager->createQueryBuilder();
$qb->select(array('a','u'))
->from('Credit\Entity\UserCreditHistory', 'a')
->leftJoin('User\Entity\User', 'u', \Doctrine\ORM\Query\Expr\Join::WITH, 'a.user = u.id')
->where("a.user = $users ")
->orderBy('a.created_at', 'DESC');
$query = $qb->getQuery();
$results = $query->getResult();
return $results;
}
However, I get this error :
[Syntax Error] line 0, col 98: Error: Expected Doctrine\ORM\Query\Lexer::T_WITH, got 'ON'
Edit: I replaced 'ON' with 'WITH' in the join clause and now what I see is only 1 value from the joined column.
This question is related to
php
doctrine-orm
zend-framework2
If you have an association on a property pointing to the user (let's say Credit\Entity\UserCreditHistory#user, picked from your example), then the syntax is quite simple:
public function getHistory($users) {
$qb = $this->entityManager->createQueryBuilder();
$qb
->select('a', 'u')
->from('Credit\Entity\UserCreditHistory', 'a')
->leftJoin('a.user', 'u')
->where('u = :user')
->setParameter('user', $users)
->orderBy('a.created_at', 'DESC');
return $qb->getQuery()->getResult();
}
Since you are applying a condition on the joined result here, using a LEFT JOIN or simply JOIN is the same.
If no association is available, then the query looks like following
public function getHistory($users) {
$qb = $this->entityManager->createQueryBuilder();
$qb
->select('a', 'u')
->from('Credit\Entity\UserCreditHistory', 'a')
->leftJoin(
'User\Entity\User',
'u',
\Doctrine\ORM\Query\Expr\Join::WITH,
'a.user = u.id'
)
->where('u = :user')
->setParameter('user', $users)
->orderBy('a.created_at', 'DESC');
return $qb->getQuery()->getResult();
}
This will produce a resultset that looks like following:
array(
array(
0 => UserCreditHistory instance,
1 => Userinstance,
),
array(
0 => UserCreditHistory instance,
1 => Userinstance,
),
// ...
)
Source: Stackoverflow.com