There is already a string handling function Series.str.startswith()
.
You should try foo[foo.b.str.startswith('f')]
.
Result:
a b
1 2 foo
2 3 fat
I think what you expect.
Alternatively you can use contains with regex option. For example:
foo[foo.b.str.contains('oo', regex= True, na=False)]
Result:
a b
1 2 foo
na=False
is to prevent Errors in case there is nan, null etc. values