Replace multiple strings with multiple other strings

Question

I m trying to replace multiple words in a string with multiple other words  The string is  I have a cat  a dog  and a goat    However  this does not produce  I have a dog  a goat  and a cat   but instead it produces  I have a cat  a cat  and a cat   Is it possible to replace multiple strings with multiple other strings at the same time in JavaScript  so that the correct result will be produced   var str    I have a cat  a dog  and a goat    str   str replace  cat gi   dog    str   str replace  dog gi   goat    str   str replace  goat gi   cat       this produces  I have a cat  a cat  and a cat    but I wanted to produce the string  I have a dog  a goat  and a cat

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String prototype replaceSome   function         var replaceWith   Array prototype pop apply arguments           i   0          r   this          l   arguments length      for   i lt l i              r   r replace arguments i  replaceWith             return r          replaceSome method for strings it takes as  much arguments as we want and replaces all  of them with the last argument we specified  2013 CopyRights saved for  Max Ahmed this is an example   var string     hello i want to  replace x  with eat    var replaced   string replaceSome           replace x  with       document write string     lt br gt     replaced      returns hello i want to eat  without brackets        jsFiddle  http   jsfiddle net CPj89

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Specific Solution  You can use a function to replace each one   var str    I have a cat  a dog  and a goat    var mapObj        cat  dog      dog  goat      goat  cat     str   str replace  cat dog goat gi  function matched     return mapObj matched         jsfiddle example  Generalizing it  If you want to dynamically maintain the regex and just add future exchanges to the map  you can do this  new RegExp Object keys mapObj  join       gi       to generate the regex   So then it would look like this  var mapObj    cat  dog  dog  goat  goat  cat     var re   new RegExp Object keys mapObj  join       gi    str   str replace re  function matched     return mapObj matched         And to add or change any more replacements you could just edit the map     fiddle with dynamic regex  Making it Reusable  If you want this to be a general pattern you could pull this out to a function like this  function replaceAll str mapObj       var re   new RegExp Object keys mapObj  join       gi         return str replace re  function matched           return mapObj matched toLowerCase                 So then you could just pass the str and a map of the replacements you want to the function and it would return the transformed string   fiddle with function  To ensure Object keys works in older browsers  add a polyfill eg from MDN or Es5

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With my replace-once package  you could do the following     const replaceOnce   require  replace-once    var str    I have a cat  a dog  and a goat   var find     cat    dog    goat   var replace     dog    goat    cat   replaceOnce str  find  replace   gi       gt   I have a dog  a goat  and a cat

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Just in case someone is wondering why the original poster s solution is not working   var str    I have a cat  a dog  and a goat     str   str replace  cat gi   dog       now str    I have a dog  a dog  and a goat    str   str replace  dog gi   goat       now str    I have a goat  a goat  and a goat    str   str replace  goat gi   cat       now str    I have a cat  a cat  and a cat

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user regular function to define the pattern to replace and then use replace function to work on input string   var i   new RegExp       g        j   new RegExp       g        k   data replace i      replace j

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You can use https   www npmjs com package union-replacer for this purpose  It is basically a string replace regexp       counterpart  which allows multiple replaces to happen in one pass while preserving full power of string replace        Disclosure  I am the author  The library was developed to support more complex user-configurable replacements and it addresses all the problematic things like capture groups  backreferences and callback function replacements   The solutions above are good enough for exact string replacements though

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This may not meet your exact need in this instance  but I ve found this a useful way to replace multiple parameters in strings  as a general solution  It will replace all instances of the parameters  no matter how many times they are referenced   String prototype fmt   function  hash            var string   this  key  for  key in hash  string   string replace new RegExp         key           gm    hash key    return string     You would invoke it as follows   var person     title   first   last   fmt   title   Agent   first   Jack   last   Bauer         person    Agent Jack Bauer

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I wrote this npm package stringinject https   www npmjs com package stringinject which allows you to do the following  var string   stringInject  this is a  0  string for  1      test    stringInject       which will replace the  0  and  1  with the array items and return the following string   this is a test string for stringInject    or you could replace placeholders with object keys and values like so   var str   stringInject  My username is  username  on  platform      username   tjcafferkey   platform   GitHub        My username is tjcafferkey on Github

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I expanded on  BenMcCormicks a bit  His worked for regular strings but not if I had escaped characters or wildcards  Here s what I did  str     curl  6  blah blah 234433 blah blah   mapObj        curl             d             function replaceAll  str  mapObj         var arr   Object keys mapObj           re         each arr  function  key  value            re   new RegExp value   g            str   str replace re  function  matched                return mapObj value                            return str     replaceAll str  mapObj    returns  blah blah 234433 blah blah   This way it will match the key in the mapObj and not the matched word

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using Array prototype reduce     const arrayOfObjects         plants   men         smart  dumb         peace   war      const sentence    plants are smart   arrayOfObjects reduce     f  s    gt     f   replace Object keys s  0   s Object keys s  0     sentence       as a reusable function const replaceManyStr    obj  sentence    gt  obj reduce  f  s    gt     f   replace Object keys s  0   s Object keys s  0     sentence   const result   replaceManyStr arrayOfObjects   sentence1    Example  x000D   x000D                      1  replacing using reduce and objects x000D   x000D     arrayOfObjects reduce  f  s    gt     f   replace Object keys s  0   s Object keys s  0     sentence  x000D   x000D     replaces the key in object with its value if found in the sentence x000D     doesn t break if words aren t found x000D   x000D     Example x000D   x000D  const arrayOfObjects     x000D      plants   men     x000D      smart  dumb     x000D      peace   war    x000D    x000D  const sentence1    plants are smart  x000D  const result1   arrayOfObjects reduce  f  s    gt     f   replace Object keys s  0   s Object keys s  0     sentence1  x000D   x000D  console log result1  x000D   x000D     result1   x000D     men are dumb x000D   x000D   x000D     Extra  string insertion python style with an array of words and indexes x000D   x000D     usage x000D   x000D     arrayOfWords reduce  f  s  i    gt     f   replace     i     s   sentence  x000D   x000D     where arrayOfWords has words you want to insert in sentence x000D   x000D     Example x000D   x000D     replaces as many words in the sentence as are defined in the arrayOfWords x000D     use python type  0    1  etc notation x000D   x000D     five to replace x000D  const sentence2     0  is  1  and  2  are  3  every  5   x000D   x000D     but four in array  doesn t break x000D  const words2     man   dumb   plants   smart   x000D   x000D     what happens   x000D  const result2   words2 reduce  f  s  i    gt     f   replace     i     s   sentence2  x000D   x000D  console log result2  x000D   x000D     result2   x000D     man is dumb and plants are smart every  5  x000D   x000D     replaces as many words as are defined in the array x000D     three to replace x000D  const sentence3     0  is  1  and  2   x000D   x000D     but five in array x000D  const words3     man   dumb   plant   smart   x000D   x000D     what happens   doesn t break x000D  const result3   words3 reduce  f  s  i    gt     f   replace     i     s   sentence3  x000D   x000D  console log result3  x000D   x000D     result3   x000D     man is dumb and plants x000D   x000D   x000D

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You can find and replace string using delimiters   x000D   x000D  var obj        firstname    John      lastname    Doe     var text    My firstname is  firstname  and my lastname is  lastname    alert mutliStringReplace obj text    function mutliStringReplace object  string          var val   string       var entries   Object entries object         entries forEach  para   gt              var find         para 0                  var regExp   new RegExp find  g          val   val replace regExp  para 1            return val    x000D   x000D   x000D

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lt  DOCTYPE html gt   lt html gt   lt body gt      lt p id  demo  gt Mr Blue  has a           blue house and a blue car  lt  p gt    lt button onclick  myFunction    gt Try it lt  button gt    lt script gt  function myFunction         var str   document getElementById  demo   innerHTML      var res   str replace   n   car gi  function myFunction x    if x    n   return x   lt br gt     if x       return x   amp nbsp    if x   car   return x  BMW   else return x    must need             document getElementById  demo   innerHTML   res     lt  script gt    lt  body gt   lt  html gt

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Use numbered items to prevent replacing again  eg  let str    I have a  1  a  2  and a  3   let pets     dog   cat    goat      then  str replace     d   g      n    gt  pets  n-1     How it works -   d  finds the numbers which come after a    The brackets capture the number   This number  as a string  is the 2nd parameter  n  to the lambda function   The  n-1 converts the string to the number then 1 is subtracted to index the pets array   The  number is then replaced with the string at the array index   The  g causes the lambda function to be called repeatedly with each number which is then replaced with a string from the array   In modern JavaScript -  replace n  str    ns   gt str replace     d   g    n   gt ns n-1

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var str    I have a cat  a dog  and a goat         str   str replace  goat i   cat           now str    I have a cat  a dog  and a cat        str   str replace  dog i   goat           now str    I have a cat  a goat  and a cat        str   str replace  cat i   dog           now str    I have a dog  a goat  and a cat

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Solution with Jquery  first include this file   Replace multiple strings with multiple other strings   var replacetext          abc    123        def    456       ghi    789        each replacetext  function txtorig  txtnew            eng-to-urd   each function               this  text   this  text   replace txtorig  txtnew

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All solutions work great  except when applied in programming languages that closures  e g  Coda  Excel  Spreadsheet s REGEXREPLACE   Two original solutions of mine below use only 1 concatenation and 1 regex  Method  1  Lookup for replacement values The idea is to append replacement values if they are not already in the string  Then  using a single regex  we perform all needed replacements   x000D   x000D  var str    I have a cat  a dog  and a goat    str    str      cat dog goat   replace      cat     s S   dog   dog     s S   goat   goat     s S   cat               gi    1 2 3    document body innerHTML   str  x000D   x000D   x000D   Explanations   cat     s S   dog   means that we look for  quot cat quot   If it matches  then a forward lookup will capture  quot dog quot  as group 1  and  quot  quot  otherwise  Same for  quot dog quot  that would capture  quot goat quot  as group 2  and  quot goat quot  that would capture  quot cat quot  as group 3  We replace with  quot  1 2 3 quot   the concatenation of all three groups   which will always be either  quot dog quot    quot cat quot  or  quot goat quot  for one of the above cases If we manually appended replacements to the string like str  quot     cat dog goat quot   we remove them by also matching              in which case the replacement  quot  1 2 3 quot  will evaluate to  quot  quot   the empty string   Method  2  Lookup for replacement pairs One problem with Method  1 is that it cannot exceed 9 replacements at a time  which is the maximum number of back-propagation groups  Method  2 states not to append just replacement values  but replacements directly   x000D   x000D  var str    I have a cat  a dog  and a goat    str    str       cat  gt dog dog  gt goat goat  gt cat   replace        b w  b      s S    1  gt                      gi    2    document body innerHTML   str  x000D   x000D   x000D   Explanations    str  quot      cat  gt dog dog  gt goat goat  gt cat quot   is how we append a replacement map to the end of the string    b w  b  states to  quot capture any word quot   that could be replaced by  quot  cat dog goat  or anything else       s S       is a forward lookup that will typically go to the end of the document until after the replacement map     1  gt  means  quot you should find the matched word between a comma and a right arrow quot          means  quot match anything after this arrow until the next comma or the end of the doc quot                 is how we remove the replacement map

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by using prototype function we can replace easily by passing object with keys and values and replacable text  x000D   x000D  String prototype replaceAll function obj keydata  key     const keys keydata split  key     return Object entries obj  reduce  a  key val    gt  a replace    keys 0    key   keys 1    val  this     const data  hids dv sdc sd   yathin    ok   console log data replaceAll  yathin 12 ok  hi      key     x000D   x000D   x000D

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This worked for me   String prototype replaceAll   function search  replacement        var target   this      return target replace new RegExp search   g    replacement       function replaceAll str  map       for key in map           str   str replaceAll key  map key              return str       testing    var str    bat  ball  cat   var map          bat     foo        ball     boo        cat     bar     var new   replaceAll str  map     result   foo  boo  bar

[javascript] Replace multiple strings with multiple other strings

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