You need to create an instance of the type that expose the Output
method:
static void Main(string[] args)
{
var DLL = Assembly.LoadFile(@"C:\visual studio 2012\Projects\ConsoleApplication1\ConsoleApplication1\DLL.dll");
var class1Type = DLL.GetType("DLL.Class1");
//Now you can use reflection or dynamic to call the method. I will show you the dynamic way
dynamic c = Activator.CreateInstance(class1Type);
c.Output(@"Hello");
Console.ReadLine();
}