[bash] Why is $$ returning the same id as the parent process?

  1. Parentheses invoke a subshell in Bash. Since it's only a subshell it might have the same PID - depends on implementation.
  2. The C program you invoke is a separate process, which has its own unique PID - doesn't matter if it's in a subshell or not.
  3. $$ is an alias in Bash to the current script PID. See differences between $$ and $BASHPID here, and right above that the additional variable $BASH_SUBSHELL which contains the nesting level.

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Why is $$ returning the same id as the parent process?