Split string with string as delimiter

Question

I m trying to split a string in a batch file using a string  rather than a character  as the delimiter   The string has the format   string1 by string2 txt   The delimiter is by  yes  space  the word  by   followed by space   The output I want is   string1  string2   So  basically  split the string into 2 parts by the delimiter by and remove the suffix from the second string  How can I do this

User · Answer

I recently discovered an interesting trick that allows to "Split String With String As Delimiter", so I couldn't resist the temptation to post it here as a new answer. Note that "obviously the question wasn't accurate. Firstly, both string1 and string2 can contain spaces. Secondly, both string1 and string2 can contain ampersands ('&')". This method correctly works with the new specifications (posted as a comment below Stephan's answer).

@echo off
setlocal

set "str=string1&with spaces by string2&with spaces.txt"

set "string1=%str: by =" & set "string2=%"
set "string2=%string2:.txt=%"

echo "%string1%"
echo "%string2%"

For further details on the split method, see this post.

User · Answer

I ve found two older scripts that use an indefinite or even a specific string to split  As an approach  these are always helpful   https   www administrator de contentid 226533 comment-1059704 https   www administrator de contentid 267522 comment-1000886   echo off  noOption if    1  neq    goto  nohelp echo Gibt eine Ausgabe bis zur angebenen Zeichenfolge amp echo  echo   n0 ist mit Eingabeumleitung zu nutzen echo   n0  Zeichenfolge    lt Quelldatei    gt Zieldatei  amp echo  echo    Zeichenfolge    die zu suchende Zeichenfolge wird mit FIND bestimmt echo            ohne AusgabeUmleitung Ausgabe im CMD Fenster exit  b  nohelp setlocal disabledelayedexpansion set  intemp  temp  time      set  string   1  set  stringlength 0   Laenge string bestimmen for  f eol       delims     i in    cmd  u  von  c  echo  string    find  v       do set  a Stringlength    1   Eingabe tempor  r speichern  gt   intemp   find  n  v      suchen der Zeichenfolge und Zeile bestimmen und speichen set  NRout   for  f  tokens  delims     a in    find   string    lt   intemp      do if not defined NRout  set  LineStr   a    for  f  delims       b in     a   do set  NRout   b    if not defined NRout  gt  amp 2 echo Zeichenfolge nicht gefunden  amp  set  a xcode 1  amp goto  end if  NRout  gtr 1 call  Line call  LineStr   end del   intemp   exit  b  xcode    LineStr Suche nur jeden ersten Buchstaben des Strings in der Treffer-Zeile dann Ausgabe bis dahin for  f eol       delims     a in   cmd  u  von  c  echo  String    findstr     do     for  f  delims       i in    cmd  u  von  c  echo  LineStr    find  n    a     do       setlocal enabledelayedexpansion     for  f   n in   set  a   i-1   do if  LineStr     n   stringlength   equ  string          set  Lineout  LineStr  0   n  string         echo  Lineout            exit  b           exit  b    Line vorige Zeilen ausgeben for  f  usebackq tokens   delims     i in    intemp    do     for  f  tokens 1 delims       n in     i   do if   n EQU  NRout   exit  b   set  Line   i    setlocal enabledelayedexpansion    echo  Line        endlocal   exit  b      echo off    CUTwithWildcards cmd  noOption if    1  neq    goto  nohelp echo Gibt eine Ausgabe ohne die angebene Zeichenfolge  echo Der Rest wird abgeschnitten  amp echo  echo   n0  Zeichenfolge  B n E   i   amp echo  echo    Zeichenfolge    String zum Durchsuchen echo    B   Zeichen Wonach am Anfang gesucht wird echo    n   Auszulassende Zeichenanzahl echo    E   Zeichen was das Ende der Zeichen Bestimmt echo     i  Case intensive exit  b  nohelp setlocal disabledelayedexpansion set   Original   1  set      Begin   2  set  a    Excl   3   echo Syntaxfehler  gt  amp 2  amp  amp exit  b 1 set        End   4  if not defined end echo Syntaxfehler  gt  amp 2  amp exit  b 1 set    CaseInt   5     end Setting Input Param set        out   set       more   call  read Original if errorlevel 1 echo Zeichenfolge nicht gefunden  gt  amp 2 exit  b  read VarName B   E   i  for  f  delims       a in    cmd  u  von  c  echo     1    find  n  CaseInt    Begin      do     if defined out exit  b 0   for  f  delims       b in    cmd  u  von  c  echo   1    more   Excl   find  n  CaseInt    End    find     a      do       set  out 1      setlocal enabledelayedexpansion     set  In    Original       set  In  In     a       echo  In   2      endlocal     if not defined out exit  b 1  exit  b    oneliner for CMDLine set  Dq    for  i in    S  E    do  set  out 1   amp for  f  delims      a in   cmd u c  echo   i   find  n  S    do  if defined out for  f  delims      b in   cmd u c  echo  i   more  2  find  n  E   find    a     do  if  a equ  b set  out    amp  set in    i   amp cmd  v c echo ren   i   in   0   a  Dq

User · Answer

I expanded Magoos answer to get both desired strings    ECHO OFF SETLOCAL enabledelayedexpansion SET  string string1 by string2 txt  SET  s2  string   by     set  s1  string  by  s2     set  s2  s2  txt    ECHO   s1   s2     EDIT  just to prove  my solution also works with the additional requirements    ECHO OFF SETLOCAL enabledelayedexpansion SET  string string amp 1 more words by string amp 2 with spaces txt  SET  s2  string   by     set  s1  string  by  s2     set  s2  s2  txt    ECHO    s1   s2    set s1 set s2   Output     string amp 1 more words string amp 2 with spaces   s1 string amp 1 more words s2 string amp 2 with spaces

User · Answer

ECHO OFF SETLOCAL SET  string string1 by string2 txt  SET  string  string   by     ECHO   string    GOTO  EOF   The above SET command will remove the unwanted data  Result shown between   to demonstrate absence of spaces   Formula  set var  somevar  string1 string2   will assign to var the value of somevar with all characters up to string1 replaced by string2  The enclosing quotes in a set command ensure that any stray trailing spaces on the line are not included in the value assigned

User · Answer

Try this   for  F  tokens 1 3 delims       a in    string    do      echo   a    echo   b     that is  take the first and third tokens delimited by space or point

[windows] Split string with string as delimiter

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