Swift - encode URL

Question

If I encode a string like this    var escapedString   originalString stringByAddingPercentEscapesUsingEncoding NSUTF8StringEncoding    it doesn t escape the slashes      I ve searched and found this Objective C code    NSString  encodedString    NSString   CFURLCreateStringByAddingPercentEscapes                          NULL                           CFStringRef unencodedString                          NULL                           CFStringRef            amp                                      kCFStringEncodingUTF8      Is there an easier way to encode an URL and if not  how do I write this in Swift

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This is working for me in Swift 5  The usage case is taking a URL from the clipboard or similar which may already have escaped characters but which also contains Unicode characters which could cause URLComponents or URL string   to fail   First  create a character set that includes all URL-legal characters   extension CharacterSet            Characters valid in at least one part of a URL                  These characters are not allowed in ALL parts of a URL  each part has different requirements  This set is useful for checking for Unicode characters that need to be percent encoded before performing a validity check on individual URL components      static var urlAllowedCharacters  CharacterSet              Start by including hash  which isn t in any set         var characters   CharacterSet charactersIn                  All URL-legal characters         characters formUnion  urlUserAllowed          characters formUnion  urlPasswordAllowed          characters formUnion  urlHostAllowed          characters formUnion  urlPathAllowed          characters formUnion  urlQueryAllowed          characters formUnion  urlFragmentAllowed           return characters           Next  extend String with a method to encode URLs   extension String            Converts a string to a percent-encoded URL  including Unicode characters                  - Returns  An encoded URL if all steps succeed  otherwise nil      func encodedUrl   - gt  URL                       Remove preexisting encoding          guard let decodedString   self removingPercentEncoding                 encode any Unicode characters so URLComponents doesn t choke              let unicodeEncodedString   decodedString addingPercentEncoding withAllowedCharacters   urlAllowedCharacters                  break into components to use proper encoding for each part              let components   URLComponents string  unicodeEncodedString                  and reencode  to revert decoding while encoding missed characters              let percentEncodedUrl   components url else                  Encoding failed             return nil                    return percentEncodedUrl            Which can be tested like   let urlText    https   www example com    search q 123 amp foo bar amp multi eggs and ham amp hangul    amp spaced lovely 20spam amp illegal  lt  gt  top  let url   encodedUrl from  urlText    Value of url at the end  https   www example com  ED 8F B4 EB 8D 94 search q 123 amp foo bar amp multi eggs and ham amp hangul  ED 95 9C EA B8 80 amp spaced lovely 20spam amp illegal  3C 3E top  Note that both  20 and   spacing are preserved  Unicode characters are encoded  the  20 in the original urlText is not double encoded  and the anchor  fragment  or    remains   Edit  Now checking for validity of each component

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Swift 3  In Swift 3 there is addingPercentEncoding  let originalString    test test  let escapedString   originalString addingPercentEncoding withAllowedCharacters   urlHostAllowed  print escapedString     Output      test 2Ftest   Swift 1  In iOS 7 and above there is stringByAddingPercentEncodingWithAllowedCharacters  var originalString    test test  var escapedString   originalString stringByAddingPercentEncodingWithAllowedCharacters  URLHostAllowedCharacterSet    println  escapedString    escapedString      Output        test 2Ftest   The following are useful  inverted  character sets    URLFragmentAllowedCharacterSet      lt  gt          URLHostAllowedCharacterSet           lt  gt          URLPasswordAllowedCharacterSet        lt  gt            URLPathAllowedCharacterSet           lt  gt           URLQueryAllowedCharacterSet         lt  gt          URLUserAllowedCharacterSet            lt  gt           If you want a different set of characters to be escaped create a set  Example with added     character   var originalString    test test 42  var customAllowedSet    NSCharacterSet charactersInString         lt  gt             invertedSet var escapedString   originalString stringByAddingPercentEncodingWithAllowedCharacters customAllowedSet  println  escapedString    escapedString      Output        test 2Ftest 3D42   Example to verify ascii characters not in the set   func printCharactersInSet set  NSCharacterSet        var characters          let iSet   set invertedSet     for i  UInt32 in 32   lt 127           let c   Character UnicodeScalar i           if iSet longCharacterIsMember i                characters   characters   String c                      print  characters not in set      characters

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Swift 4   It depends by the encoding rules followed by your server   Apple offer this class method  but it don t report wich kind of RCF protocol it follows   var escapedString   originalString addingPercentEncoding withAllowedCharacters   urlHostAllowed     Following this useful tool you should guarantee the encoding of these chars for your parameters       Dollar Sign  becomes  24  amp   Ampersand  becomes  26    Plus  becomes  2B    Comma  becomes  2C    Colon  becomes  3A    Semi-Colon  becomes  3B    Equals  becomes  3D    Question Mark  becomes  3F    Commercial A   At  becomes  40   In other words  speaking about URL encoding  you should following the RFC 1738 protocol   And Swift don t cover the encoding of the   char for example  but it works well with these three         chars   So  to correctly encoding each your parameter   the  urlHostAllowed option is not enough  you should add also the special chars as for example   encodedParameter   parameter replacingOccurrences of       with    2B     Hope this helps someone who become crazy to search these informations

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For Swift 5 to endcode string  func escape string  String  - gt  String       let allowedCharacters   string addingPercentEncoding withAllowedCharacters  CharacterSet charactersIn           lt  gt             inverted            return allowedCharacters     How to use    let strEncoded   self escape string   http   www edamam com ontologies edamam owl recipe e2a1b9bf2d996cbd9875b80612ed9aa4   print  escapedString    strEncoded

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Swift 4 2  A quick one line solution  Replace originalString with the String you want to encode   var encodedString   originalString addingPercentEncoding withAllowedCharacters  CharacterSet charactersIn            amp                 inverted    Online Playground Demo

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let Url   URL string  urlString addingPercentEncoding withAllowedCharacters   urlQueryAllowed

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What helped me was that I created a separate NSCharacterSet and used it on an UTF-8 encoded string i e  textToEncode to generate the required result  var queryCharSet   NSCharacterSet urlQueryAllowed queryCharSet remove charactersIn   quot   amp             quot        let utfedCharacterSet   String utf8String  textToEncode cString using   utf8     let encodedStr   utfedCharacterSet addingPercentEncoding withAllowedCharacters  queryCharSet        let paramUrl    quot https   api abc eu api search device true amp query   escapedStr  quot

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Swift 4  amp  5  Thanks  sumizome for suggestion   Thanks  FD  and  derickito for testing  var allowedQueryParamAndKey   NSCharacterSet urlQueryAllowed allowedQueryParamAndKey remove charactersIn   quot       amp       quot   paramOrKey addingPercentEncoding withAllowedCharacters  allowedQueryParamAndKey   Swift 3 let allowedQueryParamAndKey    NSCharacterSet urlQueryAllowed remove charactersIn   quot       amp       quot   paramOrKey addingPercentEncoding withAllowedCharacters  allowedQueryParamAndKey   Swift 2 2  Borrowing from Zaph s and correcting for url query key and parameter values  var allowedQueryParamAndKey    NSCharacterSet charactersInString   quot       amp       quot   invertedSet paramOrKey stringByAddingPercentEncodingWithAllowedCharacters allowedQueryParamAndKey   Example  let paramOrKey    quot https   some website com path to page srf a 1 amp b 2 top quot  paramOrKey addingPercentEncoding withAllowedCharacters  allowedQueryParamAndKey     produces   quot https 3A 2F 2Fsome website com 2Fpath 2Fto 2Fpage srf 3Fa 3D1 26b 3D2 23top quot   This is a shorter version of Bryan Chen s answer   I d guess that urlQueryAllowed is allowing the control characters through which is fine unless they form part of the key or value in your query string at which point they need to be escaped

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You can use URLComponents to avoid having to manually percent encode your query string   let scheme    https  let host    www google com  let path     search  let queryItem   URLQueryItem name   q   value   Formula One     var urlComponents   URLComponents   urlComponents scheme   scheme urlComponents host   host urlComponents path   path urlComponents queryItems    queryItem   if let url   urlComponents url       print url        https   www google com search q Formula 20One        extension URLComponents       init scheme  String    https            host  String    www google com            path  String     search            queryItems   URLQueryItem             self init           self scheme   scheme         self host   host         self path   path         self queryItems   queryItems             let query    Formula One  if let url   URLComponents queryItems   URLQueryItem name   q   value  query    url       print url      https   www google com search q Formula 20One

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None of these answers worked for me  Our app was crashing when a url contained non-English characters    let unreserved    -            let allowed   NSMutableCharacterSet alphanumeric        allowed addCharacters in  unreserved    let escapedString   urlString addingPercentEncoding withAllowedCharacters  allowed as CharacterSet    Depending on the parameters of what you are trying to do  you may want to just create your own character set  The above allows for english characters  and -

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Had need of this myself  so I wrote a String extension that both allows for URLEncoding strings  as well as the more common end goal  converting a parameter dictionary into  GET  style URL Parameters   extension String       func URLEncodedString   - gt  String            var escapedString   self addingPercentEncoding withAllowedCharacters   urlHostAllowed          return escapedString           static func queryStringFromParameters parameters  Dictionary lt String String gt   - gt  String            if  parameters count    0                        return nil                   var queryString   String    nil         for  key  value  in parameters               if let encodedKey   key URLEncodedString                     if let encodedValue   value URLEncodedString                         if queryString    nil                                               queryString                                                 else                                               queryString       amp                                             queryString     encodedKey         encodedValue                                                   return queryString           Enjoy

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Swift 3   let originalString    http   www ihtc cc name htc amp title iOS         1  encodingQuery   let escapedString   originalString addingPercentEncoding withAllowedCharacters NSCharacterSet urlQueryAllowed    result    http   www ihtc cc name htc amp title iOS E5 BC 80 E5 8F 91 E5 B7 A5 E7 A8 8B E5 B8 88       2  encodingURL   let escapedString   originalString addingPercentEncoding withAllowedCharacters   urlHostAllowed    result    http  2F 2Fwww ihtc cc 3Fname htc amp title iOS E5 BC 80 E5 8F 91 E5 B7 A5 E7 A8 8B E5 B8 88

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Swift 3   let allowedCharacterSet    CharacterSet charactersIn            amp               inverted   if let escapedString   originalString addingPercentEncoding withAllowedCharacters  allowedCharacterSet      do something with escaped string

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Swift 5 You can try  afURLQueryAllowed option if you want to encode string like below let testString    quot 6hAD9 RjY SnGm amp B quot  let escodedString   testString addingPercentEncoding withAllowedCharacters   afURLQueryAllowed  print escodedString     encoded string will be like en6hAD9 2FRjY 2BSnGm 26B

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This one is working for me   func stringByAddingPercentEncodingForFormData plusForSpace  Bool false  - gt  String         let unreserved     -        let allowed   NSMutableCharacterSet alphanumericCharacterSet       allowed addCharactersInString unreserved       if plusForSpace           allowed addCharactersInString                 var encoded   stringByAddingPercentEncodingWithAllowedCharacters allowed       if plusForSpace           encoded   encoded  stringByReplacingOccurrencesOfString      withString                 return encoded     I found above function from this link  http   useyourloaf com blog how-to-percent-encode-a-url-string

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Swift 4  amp  5 To encode a parameter in URL I find using  alphanumerics character set the easiest option  let encoded   parameter addingPercentEncoding withAllowedCharacters   alphanumerics  let url    quot http   www example com  name   encoded   quot   Using any of the standard Character Sets for URL Encoding  like URLQueryAllowedCharacterSet or URLHostAllowedCharacterSet  won t work  because they do not exclude   or  amp  characters  Note that by using  alphanumerics it will encode some characters that do not need to be encoded  like -       or   -    see 2 3  Unreserved characters in RFC 3986   I find using  alphanumerics simpler than constructing a custom character set and do not mind some additional characters to be encoded  If that bothers you  construct a custom character set as is described in How to percent encode a URL String  like for example  var allowed   CharacterSet alphanumerics allowed insert charactersIn   quot -    quot      as per RFC 3986 let encoded   parameter addingPercentEncoding withAllowedCharacters  allowed  let url    quot http   www example com  name   encoded   quot   Warning  The encoded parameter is force unwrapped  For invalid unicode string it might crash  See Why is the return value of String addingPercentEncoding   optional   Instead of force unwrapping encoded  you can use encoded     quot  quot  or use if let encoded

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SWIFT 4 2  Sometimes this happened just because there is space in slug OR absence of URL encoding for parameters passing through API URL   let myString   self slugValue                 let csCopy   CharacterSet bitmapRepresentation  CharacterSet urlPathAllowed bitmapRepresentation                  let escapedString   myString  addingPercentEncoding withAllowedCharacters  csCopy                     always  info hello 20world                  print escapedString    NOTE   Don t forget to explore about bitmapRepresentation

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Everything is same  var str   CFURLCreateStringByAddingPercentEscapes      nil       test test       nil                amp                  CFStringBuiltInEncodings UTF8 rawValue       test 2Ftest

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