How to urlencode a querystring in Python

Question

I am trying to urlencode this string before I submit    queryString    eventName     evt fields  eventName       amp      eventDescription     evt fields  eventDescription

User · Answer

For Python 3 urllib3 works properly  you can use as follow as per its official docs    import urllib3  http   urllib3 PoolManager   response   http request        GET         https   api prylabs net eth v1alpha1 beacon attestations        fields      here fields are the query params            epoch   1234             pageSize   pageSize              response   attestations data decode  UTF-8

User · Answer

for future references  ex  for python3    gt  gt  gt  import urllib request as req  gt  gt  gt  query    eventName theEvent amp eventDescription testDesc   gt  gt  gt  req pathname2url query   gt  gt  gt   eventName 3DtheEvent 26eventDescription 3DtestDesc

User · Answer

You need to pass your parameters into urlencode   as either a mapping  dict   or a sequence of 2-tuples  like    gt  gt  gt  import urllib  gt  gt  gt  f      eventName     myEvent    eventDescription     cool event    gt  gt  gt  urllib urlencode f   eventName myEvent amp eventDescription cool event    Python 3 or above  Use    gt  gt  gt  urllib parse urlencode f  eventName myEvent amp eventDescription cool event   Note that this does not do url encoding in the commonly used sense  look at the output   For that use urllib parse quote plus

User · Answer

Another thing that might not have been mentioned already is that urllib urlencode   will encode empty values in the dictionary as the string None instead of having that parameter as absent  I don t know if this is typically desired or not  but does not fit my use case  hence I have to use quote plus

User · Answer

For use in scripts programs which need to support both python 2 and 3  the six module provides quote and urlencode functions    gt  gt  gt  from six moves urllib parse import urlencode  quote  gt  gt  gt  data     some    query    for    encoding    gt  gt  gt  urlencode data   some query amp for encoding   gt  gt  gt  url     some url with spaces and     lt  gt  amp    gt  gt  gt  quote url    some url with 20spaces 20and 20 25 3B 21 3C 3E 26

User · Answer

Note that the urllib urlencode does not always do the trick  The problem is that some services care about the order of arguments  which gets lost when you create the dictionary  For such cases  urllib quote plus is better  as Ricky suggested

User · Answer

In Python 3  this worked with me  import urllib  urllib parse quote query

User · Answer

Python 2  What you re looking for is urllib quote plus    gt  gt  gt  urllib quote plus  string of characters like these        Q      string of characters like these 3A 24 23 40 3D 3F 25 5EQ 5E 24    Python 3  In Python 3  the urllib package has been broken into smaller components  You ll use urllib parse quote plus  note the parse child module   import urllib parse urllib parse quote plus

User · Answer

Try requests instead of urllib and you don t need to bother with urlencode   import requests requests get  http   youraddress com   params evt fields    EDIT   If you need ordered name-value pairs or multiple values for a name then set params like so   params    name1   value11      name1   value12      name2   value21           instead of using a dictionary

User · Answer

Context   Python  version 2 7 2     Problem   You want to generate a urlencoded query string  You have a dictionary or object containing the name-value pairs  You want to be able to control the output ordering of the name-value pairs    Solution   urllib urlencode urllib quote plus   Pitfalls   dictionary output arbitrary ordering of name-value pairs    see also  Why is python ordering my dictionary like so    see also  Why is the order in dictionaries and sets arbitrary    handling cases when you DO NOT care about the ordering of the name-value pairs handling cases when you DO care about the ordering of the name-value pairs handling cases where a single name needs to appear more than once in the set of all name-value pairs   Example  The following is a complete solution  including how to deal with some pitfalls                               init python  version 2 7 2   import urllib                              first setup a dictionary of name-value pairs dict name value pairs        bravo       True    False      alpha       http   www example com      charlie     hello world      delta       1234567        amp        echo        user example com                                    setup an exact ordering for the name-value pairs ary ordered names      ary ordered names append  alpha   ary ordered names append  bravo   ary ordered names append  charlie   ary ordered names append  delta   ary ordered names append  echo                                show the output results if  NO we DO NOT care about the ordering of name-value pairs      queryString    urllib urlencode dict name value pairs    print queryString          echo user 40example com amp bravo True  21 3D False amp delta 1234567  21 40 23 24 25 5E 26 2A amp charlie hello world amp alpha http 3A 2F 2Fwww example com        if  YES we DO care about the ordering of name-value pairs      queryString      amp   join    item     urllib quote plus dict name value pairs item   for item in ary ordered names       print queryString         alpha http 3A 2F 2Fwww example com amp bravo True  21 3D False amp charlie hello world amp delta 1234567  21 40 23 24 25 5E 26 2A amp echo user 40example com

User · Answer

Try this   urllib pathname2url stringToURLEncode    urlencode won t work because it only works on dictionaries  quote plus didn t produce the correct output

User · Answer

Python 3   urllib parse quote plus string  safe     encoding None  errors None

User · Answer

If the urllib parse urlencode    is giving you errors   then Try the urllib3 module   The syntax is as follows   import urllib3 urllib3 request urlencode   quot user quot     quot john quot

[python] How to urlencode a querystring in Python?

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