I'm trying to set UIImageView programmatically in Xcode 6.1:
@IBOutlet weak var bgImage: UIImageView!
var image : UIImage = UIImage(named:"afternoon")!
bgImage = UIImageView(image: image)
bgImage.frame = CGRect(x: 0, y: 0, width: 100, height: 200)
view.addSubview(bgImage)
But Xcode is saying "expected declaration" with bgImage = UIImageView(image: image)
Image "afternoon"
is a PNG, and my understanding is PNG does not need an extension in XCode 6.1.
Also tried just bgImage.image = UIImage(named: "afternoon")
, but still get:
UPDATE
OK, I have put the code to update UIImageView
into the viewDidLoad
function, but UIImageView
is still not showing the image (which exists in the base directory as afternoon.png):
@IBOutlet weak var bgImage: UIImageView!
@IBOutlet weak var dateLabel: UILabel!
@IBOutlet weak var timeLabel: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
updateTime()
var timer = NSTimer()
let aSelector : Selector = "updateTime"
timer = NSTimer.scheduledTimerWithTimeInterval(0.01, target: self, selector: aSelector, userInfo: nil, repeats: true)
var image : UIImage = UIImage(named:"afternoon")!
bgImage = UIImageView(image: image)
}
This code is in the wrong place:
var image : UIImage = UIImage(named:"afternoon")!
bgImage = UIImageView(image: image)
bgImage.frame = CGRect(x: 0, y: 0, width: 100, height: 200)
view.addSubview(bgImage)
You must place it inside a function. I recommend moving it inside the viewDidLoad
function.
In general, the only code you can add within the class that's not inside of a function are variable declarations like:
@IBOutlet weak var bgImage: UIImageView!
In Swift 4, if the image is returned as nil.
Click on image, on the right hand side (Utilities) -> Check Target Membership
With swift syntax this worked for me :
let leftImageView = UIImageView()
leftImageView.image = UIImage(named: "email")
let leftView = UIView()
leftView.addSubview(leftImageView)
leftView.frame = CGRect(x: 0, y: 0, width: 40, height: 40)
leftImageView.frame = CGRect(x: 10, y: 10, width: 20, height: 20)
userNameTextField.leftViewMode = .always
userNameTextField.leftView = leftView
You just need to drag and drop an ImageView
, create the outlet action, link it, and provide an image (Xcode is going to look in your assets
folder for the name you provided (here: "toronto"))
In yourProject/ViewController.swift
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var imgView: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
imgView.image = UIImage(named: "toronto")
}
}
If you want to do it the way you showed in your question, this is a way to do it inline
class YourClass: UIViewController{
@IBOutlet weak var tableView: UITableView!
//other IBOutlets
//THIS is how you declare a UIImageView inline
let placeholderImage : UIImageView = {
let placeholderImage = UIImageView(image: UIImage(named: "nophoto"))
placeholderImage.contentMode = .scaleAspectFill
return placeholderImage
}()
var someVariable: String!
var someOtherVariable: Int!
func someMethod(){
//method code
}
//and so on
}
How about this;
myImageView.image=UIImage(named: "image_1")
where image_1 is within the assets folder as image_1.png.
This worked for me since i'm using a switch case to display an image slide.
OK, got it working with this (creating the UIImageView programmatically):
var imageViewObject :UIImageView
imageViewObject = UIImageView(frame:CGRectMake(0, 0, 600, 600))
imageViewObject.image = UIImage(named:"afternoon")
self.view.addSubview(imageViewObject)
self.view.sendSubviewToBack(imageViewObject)
In xcode 8 you can directly choose image from the selection window (NEW)...
You just need to type - "image" and you will get a suggestion box then select -"Image Literal" from list (see in attached picture) and
then tap on the square you will be able to see all images(see in
second attached picture) which are in your image assets... or select
other image from there.
Source: Stackoverflow.com