I just wrote array intersection that correctly handles also duplicates
https://gist.github.com/gkucmierz/8ee04544fa842411f7553ef66ac2fcf0
// array intersection that correctly handles also duplicates_x000D_
_x000D_
const intersection = (a1, a2) => {_x000D_
const cnt = new Map();_x000D_
a2.map(el => cnt[el] = el in cnt ? cnt[el] + 1 : 1);_x000D_
return a1.filter(el => el in cnt && 0 < cnt[el]--);_x000D_
};_x000D_
_x000D_
const l = console.log;_x000D_
l(intersection('1234'.split``, '3456'.split``)); // [ '3', '4' ]_x000D_
l(intersection('12344'.split``, '3456'.split``)); // [ '3', '4' ]_x000D_
l(intersection('1234'.split``, '33456'.split``)); // [ '3', '4' ]_x000D_
l(intersection('12334'.split``, '33456'.split``)); // [ '3', '3', '4' ]
_x000D_