[python] How does functools partial do what it does?

I am not able to get my head on how the partial works in functools. I have the following code from here:

>>> sum = lambda x, y : x + y
>>> sum(1, 2)
3
>>> incr = lambda y : sum(1, y)
>>> incr(2)
3
>>> def sum2(x, y):
    return x + y

>>> incr2 = functools.partial(sum2, 1)
>>> incr2(4)
5

Now in the line

incr = lambda y : sum(1, y)

I get that whatever argument I pass to incr it will be passed as y to lambda which will return sum(1, y) i.e 1 + y.

I understand that. But I didn't understand this incr2(4).

How does the 4 gets passed as x in partial function? To me, 4 should replace the sum2. What is the relation between x and 4?

Also worth to mention, that when partial function passed another function where we want to "hard code" some parameters, that should be rightmost parameter

def func(a,b):
    return a*b
prt = partial(func, b=7)
    print(prt(4))
#return 28

but if we do the same, but changing a parameter instead

def func(a,b):
    return a*b
 prt = partial(func, a=7)
    print(prt(4))

it will throw error, "TypeError: func() got multiple values for argument 'a'"

This answer is more of an example code. All the above answers give good explanations regarding why one should use partial. I will give my observations and use cases about partial.

from functools import partial
 def adder(a,b,c):
    print('a:{},b:{},c:{}'.format(a,b,c))
    ans = a+b+c
    print(ans)
partial_adder = partial(adder,1,2)
partial_adder(3)  ## now partial_adder is a callable that can take only one argument

Output of the above code should be:

a:1,b:2,c:3
6

Notice that in the above example a new callable was returned that will take parameter (c) as it's argument. Note that it is also the last argument to the function.

args = [1,2]
partial_adder = partial(adder,*args)
partial_adder(3)

Output of the above code is also:

a:1,b:2,c:3
6

Notice that * was used to unpack the non-keyword arguments and the callable returned in terms of which argument it can take is same as above.

Another observation is: Below example demonstrates that partial returns a callable which will take the undeclared parameter (a) as an argument.

def adder(a,b=1,c=2,d=3,e=4):
    print('a:{},b:{},c:{},d:{},e:{}'.format(a,b,c,d,e))
    ans = a+b+c+d+e
    print(ans)
partial_adder = partial(adder,b=10,c=2)
partial_adder(20)

Output of the above code should be:

a:20,b:10,c:2,d:3,e:4
39

Similarly,

kwargs = {'b':10,'c':2}
partial_adder = partial(adder,**kwargs)
partial_adder(20)

Above code prints

a:20,b:10,c:2,d:3,e:4
39

I had to use it when I was using Pool.map_async method from multiprocessing module. You can pass only one argument to the worker function so I had to use partial to make my worker function look like a callable with only one input argument but in reality my worker function had multiple input arguments.

Partials can be used to make new derived functions that have some input parameters pre-assigned

To see some real world usage of partials, refer to this really good blog post:
http://chriskiehl.com/article/Cleaner-coding-through-partially-applied-functions/

A simple but neat beginner's example from the blog, covers how one might use partial on re.search to make code more readable. re.search method's signature is:

search(pattern, string, flags=0) 

By applying partial we can create multiple versions of the regular expression search to suit our requirements, so for example:

is_spaced_apart = partial(re.search, '[a-zA-Z]\s\=')
is_grouped_together = partial(re.search, '[a-zA-Z]\=')

Now is_spaced_apart and is_grouped_together are two new functions derived from re.search that have the pattern argument applied(since pattern is the first argument in the re.search method's signature).

The signature of these two new functions(callable) is:

is_spaced_apart(string, flags=0)     # pattern '[a-zA-Z]\s\=' applied
is_grouped_together(string, flags=0) # pattern '[a-zA-Z]\=' applied

This is how you could then use these partial functions on some text:

for text in lines:
    if is_grouped_together(text):
        some_action(text)
    elif is_spaced_apart(text):
        some_other_action(text)
    else:
        some_default_action()

You can refer the link above to get a more in depth understanding of the subject, as it covers this specific example and much more..

In my opinion, it's a way to implement currying in python.

from functools import partial
def add(a,b):
    return a + b

def add2number(x,y,z):
    return x + y + z

if __name__ == "__main__":
    add2 = partial(add,2)
    print("result of add2 ",add2(1))
    add3 = partial(partial(add2number,1),2)
    print("result of add3",add3(1))

The result is 3 and 4.

short answer, partial gives default values to the parameters of a function that would otherwise not have default values.

from functools import partial

def foo(a,b):
    return a+b

bar = partial(foo, a=1) # equivalent to: foo(a=1, b)
bar(b=10)
#11 = 1+10
bar(a=101, b=10)
#111=101+10

partials are incredibly useful.

For instance, in a 'pipe-lined' sequence of function calls (in which the returned value from one function is the argument passed to the next).

Sometimes a function in such a pipeline requires a single argument, but the function immediately upstream from it returns two values.

In this scenario, functools.partial might allow you to keep this function pipeline intact.

Here's a specific, isolated example: suppose you want to sort some data by each data point's distance from some target:

# create some data
import random as RND
fnx = lambda: RND.randint(0, 10)
data = [ (fnx(), fnx()) for c in range(10) ]
target = (2, 4)

import math
def euclid_dist(v1, v2):
    x1, y1 = v1
    x2, y2 = v2
    return math.sqrt((x2 - x1)**2 + (y2 - y1)**2)

To sort this data by distance from the target, what you would like to do of course is this:

data.sort(key=euclid_dist)

but you can't--the sort method's key parameter only accepts functions that take a single argument.

so re-write euclid_dist as a function taking a single parameter:

from functools import partial

p_euclid_dist = partial(euclid_dist, target)

p_euclid_dist now accepts a single argument,

>>> p_euclid_dist((3, 3))
  1.4142135623730951

so now you can sort your data by passing in the partial function for the sort method's key argument:

data.sort(key=p_euclid_dist)

# verify that it works:
for p in data:
    print(round(p_euclid_dist(p), 3))

    1.0
    2.236
    2.236
    3.606
    4.243
    5.0
    5.831
    6.325
    7.071
    8.602

Or for instance, one of the function's arguments changes in an outer loop but is fixed during iteration in the inner loop. By using a partial, you don't have to pass in the additional parameter during iteration of the inner loop, because the modified (partial) function doesn't require it.

>>> from functools import partial

>>> def fnx(a, b, c):
      return a + b + c

>>> fnx(3, 4, 5)
      12

create a partial function (using keyword arg)

>>> pfnx = partial(fnx, a=12)

>>> pfnx(b=4, c=5)
     21

you can also create a partial function with a positional argument

>>> pfnx = partial(fnx, 12)

>>> pfnx(4, 5)
      21

but this will throw (e.g., creating partial with keyword argument then calling using positional arguments)

>>> pfnx = partial(fnx, a=12)

>>> pfnx(4, 5)
      Traceback (most recent call last):
      File "<pyshell#80>", line 1, in <module>
      pfnx(4, 5)
      TypeError: fnx() got multiple values for keyword argument 'a'

another use case: writing distributed code using python's multiprocessing library. A pool of processes is created using the Pool method:

>>> import multiprocessing as MP

>>> # create a process pool:
>>> ppool = MP.Pool()

Pool has a map method, but it only takes a single iterable, so if you need to pass in a function with a longer parameter list, re-define the function as a partial, to fix all but one:

>>> ppool.map(pfnx, [4, 6, 7, 8])