How to concatenate characters in java

Question

How do you concatenate characters in java  Concatenating strings would only require a   between the strings  but concatenating chars using   will change the value of the char into ascii and hence giving a numerical output  I want to do System out println char1 char2 char3    and create a String word like this   I could do   System out print char1   System out print char2   System out print char3     But  this will only get me the characters in 1 line  I need it as a string  Any help would be appreciated   Thanks

User · Answer

simple example to selecting character from string and appending to string variable

private static String findaccountnum(String holdername, String mobile) {

    char n1=holdername.charAt(0);
    char n2=holdername.charAt(1);
    char n3=holdername.charAt(2);
    char n4=mobile.charAt(0);
    char n5=mobile.charAt(1);
    char n6=mobile.charAt(2);
    String number=new StringBuilder().append(n1).append(n2).append(n3).append(n4).append(n5).append(n6).toString();

    return number;
}

User · Answer

System out println char1    char2 char3    or  String s   char1    char2 char3

User · Answer

I don t really consider myself a Java programmer  but just thought I d add it here  for completeness   using the  C-inspired  String format static method   String s   String format   s s    a    b       s is  ab

User · Answer

If you have a bunch of chars and want to concat them into a string  why not do   System out println      char1   char2   char3

User · Answer

You need a String object of some description to hold your array of concatenated chars  since the char type will hold only a single character  e g     StringBuilder sb   new StringBuilder  a   append  b   append  c    System out println sb toString

User · Answer

You need to tell the compiler you want to do String concatenation by starting the sequence with a string  even an empty one  Like so   System out println      char1   char2   char3

User · Answer

You need to tell the compiler you want to do String concatenation by starting the sequence with a string  even an empty one  Like so   System out println      char1   char2   char3

User · Answer

Do you want to make a string out of them   String s   new StringBuilder   append char1  append char2  append char3  toString      Note that  String b    b   String s    a    b    c     Actually compiles to  String s   new StringBuilder  a   append b  append  c   toString      Edit  as litb pointed out  you can also do this        char1   char2   char3    That compiles to the following   new StringBuilder   append     append c  append c1  append c2  toString      Edit  2   Corrected string append comparison since  as cletus points out  a series of strings is handled by the compiler   The purpose of the above is to illustrate what the compiler does  not to tell you what you should do

User · Answer

You can use the String constructor   System out println new String new char   a b c

User · Answer

Do you want to make a string out of them   String s   new StringBuilder   append char1  append char2  append char3  toString      Note that  String b    b   String s    a    b    c     Actually compiles to  String s   new StringBuilder  a   append b  append  c   toString      Edit  as litb pointed out  you can also do this        char1   char2   char3    That compiles to the following   new StringBuilder   append     append c  append c1  append c2  toString      Edit  2   Corrected string append comparison since  as cletus points out  a series of strings is handled by the compiler   The purpose of the above is to illustrate what the compiler does  not to tell you what you should do

User · Answer

public class initials    public static void main  String    args         char initialA    M       char initialB    P       char initialC    T        System out println      initialA   initialB   initialC

User · Answer

simple example to selecting character from string and appending to string variable

private static String findaccountnum(String holdername, String mobile) {

    char n1=holdername.charAt(0);
    char n2=holdername.charAt(1);
    char n3=holdername.charAt(2);
    char n4=mobile.charAt(0);
    char n5=mobile.charAt(1);
    char n6=mobile.charAt(2);
    String number=new StringBuilder().append(n1).append(n2).append(n3).append(n4).append(n5).append(n6).toString();

    return number;
}

User · Answer

System out print a        b        c

User · Answer

I wasn t going to answer this question but there are two answers here  that are getting voted up   that are just plain wrong   Consider these expressions   String a    a     b     c   String b   System getProperty  blah      b     The first is evaluated at compile-time   The second is evaluated at run-time   So never replace constant concatenations  of any type  with StringBuilder  StringBuffer or the like   Only use those where variables are invovled and generally only when you re appending a lot of operands or you re appending in a loop   If the characters are constant  this is fine   String s         a     b     c     If however they aren t  consider this   String concat char    chars      if  chars length    0        return           StringBuilder s   new StringBuilder chars length     for  char c   chars        s append c         return s toString        as an appropriate solution   However some might be tempted to optimise   String s    Name       name           String name    into this   String s   new StringBuilder   append  Name     append name  append      toString      While this is well-intentioned  the bottom line is DON T   Why   As another answer correctly pointed out  the compiler does this for you   So in doing it yourself  you re not allowing the compiler to optimise the code or not depending if its a good idea  the code is harder to read and its unnecessarily complicated   For low-level optimisation the compiler is better at optimising code than you are   Let the compiler do its job   In this case the worst case scenario is that the compiler implicitly changes your code to exactly what you wrote   Concatenating 2-3 Strings might be more efficient than constructing a StringBuilder so it might be better to leave it as is   The compiler knows whats best in this regard

User · Answer

You need a String object of some description to hold your array of concatenated chars  since the char type will hold only a single character  e g     StringBuilder sb   new StringBuilder  a   append  b   append  c    System out println sb toString

User · Answer

If you have a bunch of chars and want to concat them into a string  why not do   System out println      char1   char2   char3

User · Answer

You need to tell the compiler you want to do String concatenation by starting the sequence with a string  even an empty one  Like so   System out println      char1   char2   char3

User · Answer

Do you want to make a string out of them   String s   new StringBuilder   append char1  append char2  append char3  toString      Note that  String b    b   String s    a    b    c     Actually compiles to  String s   new StringBuilder  a   append b  append  c   toString      Edit  as litb pointed out  you can also do this        char1   char2   char3    That compiles to the following   new StringBuilder   append     append c  append c1  append c2  toString      Edit  2   Corrected string append comparison since  as cletus points out  a series of strings is handled by the compiler   The purpose of the above is to illustrate what the compiler does  not to tell you what you should do

User · Answer

You need a String object of some description to hold your array of concatenated chars  since the char type will hold only a single character  e g     StringBuilder sb   new StringBuilder  a   append  b   append  c    System out println sb toString

User · Answer

I wasn t going to answer this question but there are two answers here  that are getting voted up   that are just plain wrong   Consider these expressions   String a    a     b     c   String b   System getProperty  blah      b     The first is evaluated at compile-time   The second is evaluated at run-time   So never replace constant concatenations  of any type  with StringBuilder  StringBuffer or the like   Only use those where variables are invovled and generally only when you re appending a lot of operands or you re appending in a loop   If the characters are constant  this is fine   String s         a     b     c     If however they aren t  consider this   String concat char    chars      if  chars length    0        return           StringBuilder s   new StringBuilder chars length     for  char c   chars        s append c         return s toString        as an appropriate solution   However some might be tempted to optimise   String s    Name       name           String name    into this   String s   new StringBuilder   append  Name     append name  append      toString      While this is well-intentioned  the bottom line is DON T   Why   As another answer correctly pointed out  the compiler does this for you   So in doing it yourself  you re not allowing the compiler to optimise the code or not depending if its a good idea  the code is harder to read and its unnecessarily complicated   For low-level optimisation the compiler is better at optimising code than you are   Let the compiler do its job   In this case the worst case scenario is that the compiler implicitly changes your code to exactly what you wrote   Concatenating 2-3 Strings might be more efficient than constructing a StringBuilder so it might be better to leave it as is   The compiler knows whats best in this regard

User · Answer

System out print a        b        c

User · Answer

If you have a bunch of chars and want to concat them into a string  why not do   System out println      char1   char2   char3

User · Answer

You can use the String constructor   System out println new String new char   a b c

User · Answer

If you have a bunch of chars and want to concat them into a string  why not do   System out println      char1   char2   char3

User · Answer

I wasn t going to answer this question but there are two answers here  that are getting voted up   that are just plain wrong   Consider these expressions   String a    a     b     c   String b   System getProperty  blah      b     The first is evaluated at compile-time   The second is evaluated at run-time   So never replace constant concatenations  of any type  with StringBuilder  StringBuffer or the like   Only use those where variables are invovled and generally only when you re appending a lot of operands or you re appending in a loop   If the characters are constant  this is fine   String s         a     b     c     If however they aren t  consider this   String concat char    chars      if  chars length    0        return           StringBuilder s   new StringBuilder chars length     for  char c   chars        s append c         return s toString        as an appropriate solution   However some might be tempted to optimise   String s    Name       name           String name    into this   String s   new StringBuilder   append  Name     append name  append      toString      While this is well-intentioned  the bottom line is DON T   Why   As another answer correctly pointed out  the compiler does this for you   So in doing it yourself  you re not allowing the compiler to optimise the code or not depending if its a good idea  the code is harder to read and its unnecessarily complicated   For low-level optimisation the compiler is better at optimising code than you are   Let the compiler do its job   In this case the worst case scenario is that the compiler implicitly changes your code to exactly what you wrote   Concatenating 2-3 Strings might be more efficient than constructing a StringBuilder so it might be better to leave it as is   The compiler knows whats best in this regard

User · Answer

public class initials    public static void main  String    args         char initialA    M       char initialB    P       char initialC    T        System out println      initialA   initialB   initialC

User · Answer

this is very simple approach to concatenate or append the character          StringBuilder desc   new StringBuilder            String Description  this is my land           desc desc append Description charAt i

User · Answer

You need to tell the compiler you want to do String concatenation by starting the sequence with a string  even an empty one  Like so   System out println      char1   char2   char3

User · Answer

You can use the String constructor   System out println new String new char   a b c

User · Answer

System out println char1    char2 char3    or  String s   char1    char2 char3

User · Answer

You need a String object of some description to hold your array of concatenated chars  since the char type will hold only a single character  e g     StringBuilder sb   new StringBuilder  a   append  b   append  c    System out println sb toString

User · Answer

You can use the String constructor   System out println new String new char   a b c

User · Answer

I don t really consider myself a Java programmer  but just thought I d add it here  for completeness   using the  C-inspired  String format static method   String s   String format   s s    a    b       s is  ab

User · Answer

I wasn t going to answer this question but there are two answers here  that are getting voted up   that are just plain wrong   Consider these expressions   String a    a     b     c   String b   System getProperty  blah      b     The first is evaluated at compile-time   The second is evaluated at run-time   So never replace constant concatenations  of any type  with StringBuilder  StringBuffer or the like   Only use those where variables are invovled and generally only when you re appending a lot of operands or you re appending in a loop   If the characters are constant  this is fine   String s         a     b     c     If however they aren t  consider this   String concat char    chars      if  chars length    0        return           StringBuilder s   new StringBuilder chars length     for  char c   chars        s append c         return s toString        as an appropriate solution   However some might be tempted to optimise   String s    Name       name           String name    into this   String s   new StringBuilder   append  Name     append name  append      toString      While this is well-intentioned  the bottom line is DON T   Why   As another answer correctly pointed out  the compiler does this for you   So in doing it yourself  you re not allowing the compiler to optimise the code or not depending if its a good idea  the code is harder to read and its unnecessarily complicated   For low-level optimisation the compiler is better at optimising code than you are   Let the compiler do its job   In this case the worst case scenario is that the compiler implicitly changes your code to exactly what you wrote   Concatenating 2-3 Strings might be more efficient than constructing a StringBuilder so it might be better to leave it as is   The compiler knows whats best in this regard

User · Answer

Do you want to make a string out of them   String s   new StringBuilder   append char1  append char2  append char3  toString      Note that  String b    b   String s    a    b    c     Actually compiles to  String s   new StringBuilder  a   append b  append  c   toString      Edit  as litb pointed out  you can also do this        char1   char2   char3    That compiles to the following   new StringBuilder   append     append c  append c1  append c2  toString      Edit  2   Corrected string append comparison since  as cletus points out  a series of strings is handled by the compiler   The purpose of the above is to illustrate what the compiler does  not to tell you what you should do

User · Answer

this is very simple approach to concatenate or append the character          StringBuilder desc   new StringBuilder            String Description  this is my land           desc desc append Description charAt i

[java] How to concatenate characters in java?

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