How to split strings into text and number

Question

I d like to split strings like these   foofo21   bar432   foobar12345    into    foofo    21     bar    432     foobar    12345     Does somebody know an easy and simple way to do this in python

User · Answer

Yet Another Option    gt  gt  gt   re split r   d     s  for s in   foofo21    bar432    foobar12345       foofo    21          bar    432          foobar    12345

User · Answer

import re  s   raw input   m   re match r   a-zA-Z     0-9     s  print m group 0  print m group 1  print m group 2

User · Answer

I would approach this by using re match in the  following way  import re match   re match r quot   a-z     0-9    quot    foofo21   re I  if match      items   match groups   print items   gt  gt    quot foofo quot    quot 21 quot

User · Answer

def mysplit s           head   s rstrip  0123456789           tail   s len head            return head  tail           mysplit s  for s in   foofo21    bar432    foobar12345       foofo    21      bar    432      foobar    12345

User · Answer

without using regex  using isdigit   built-in function  only works if starting part is text and latter part is number  def text num split item       for index  letter in enumerate item  0           if letter isdigit                return  item  index  item index     print text num split  foobar12345      OUTPUT      foobar    12345

User · Answer

def mysplit s           head   s rstrip  0123456789           tail   s len head            return head  tail           mysplit s  for s in   foofo21    bar432    foobar12345       foofo    21      bar    432      foobar    12345

User · Answer

Yet Another Option    gt  gt  gt   re split r   d     s  for s in   foofo21    bar432    foobar12345       foofo    21          bar    432          foobar    12345

User · Answer

I would approach this by using re match in the  following way  import re match   re match r quot   a-z     0-9    quot    foofo21   re I  if match      items   match groups   print items   gt  gt    quot foofo quot    quot 21 quot

User · Answer

Yet Another Option    gt  gt  gt   re split r   d     s  for s in   foofo21    bar432    foobar12345       foofo    21          bar    432          foobar    12345

User · Answer

gt  gt  gt  r   re compile    a-zA-Z     0-9       gt  gt  gt  m   r match  foobar12345    gt  gt  gt  m group 1   foobar   gt  gt  gt  m group 2   12345    So  if you have a list of strings with that format   import re r   re compile    a-zA-Z     0-9      strings     foofo21    bar432    foobar12345   print  r match string  groups   for string in strings    Output      foofo    21      bar    432      foobar    12345

User · Answer

import re  s   raw input   m   re match r   a-zA-Z     0-9     s  print m group 0  print m group 1  print m group 2

User · Answer

I would approach this by using re match in the  following way  import re match   re match r quot   a-z     0-9    quot    foofo21   re I  if match      items   match groups   print items   gt  gt    quot foofo quot    quot 21 quot

User · Answer

here is simple solution for that problem  no needs for that  cat walk  on keyboard  i mean regex          enjoy  -   user   input  Input       user    foobar12345  int list  str list           for item in user   try      item   int item     searching for integers in your string   except      str list append item      string      join str list    else     if there are integers i will add it to int list but as str  because join function only can work with str     int list append str item       integer   int    join int list      if you want it to be string just do z      join int list   final    string  integer     you can also add it to dictionary d    string  integer  print final

User · Answer

gt  gt  gt  r   re compile    a-zA-Z     0-9       gt  gt  gt  m   r match  foobar12345    gt  gt  gt  m group 1   foobar   gt  gt  gt  m group 2   12345    So  if you have a list of strings with that format   import re r   re compile    a-zA-Z     0-9      strings     foofo21    bar432    foobar12345   print  r match string  groups   for string in strings    Output      foofo    21      bar    432      foobar    12345

User · Answer

I m always the one to bring up findall        gt  gt  gt  strings     foofo21    bar432    foobar12345    gt  gt  gt   re findall r   w     d     s  0  for s in strings     foofo    21      bar    432      foobar    12345      Note that I m using a simpler  less to type  regex than most of the previous answers

User · Answer

This is a little longer  but more versatile for cases where there are multiple  randomly placed  numbers in the string  Also  it requires no imports  def getNumbers  input          Collect Info     compile    quot  quot      complete           for letter in input            If compiled string         if compile                If compiled and letter are same type  append letter             if compile isdigit      letter isdigit                    compile    letter                            If compiled and letter are different types  append compiled string  and begin with letter             else                  complete append  compile                   compile   letter                        If no compiled string  begin with letter         else              compile   letter                Append leftover compiled string     if compile          complete append  compile              Return numbers only     numbers     word for word in complete if word isdigit                  return numbers

User · Answer

I would approach this by using re match in the  following way  import re match   re match r quot   a-z     0-9    quot    foofo21   re I  if match      items   match groups   print items   gt  gt    quot foofo quot    quot 21 quot

User · Answer

I m always the one to bring up findall        gt  gt  gt  strings     foofo21    bar432    foobar12345    gt  gt  gt   re findall r   w     d     s  0  for s in strings     foofo    21      bar    432      foobar    12345      Note that I m using a simpler  less to type  regex than most of the previous answers

User · Answer

gt  gt  gt  r   re compile    a-zA-Z     0-9       gt  gt  gt  m   r match  foobar12345    gt  gt  gt  m group 1   foobar   gt  gt  gt  m group 2   12345    So  if you have a list of strings with that format   import re r   re compile    a-zA-Z     0-9      strings     foofo21    bar432    foobar12345   print  r match string  groups   for string in strings    Output      foofo    21      bar    432      foobar    12345

User · Answer

I m always the one to bring up findall        gt  gt  gt  strings     foofo21    bar432    foobar12345    gt  gt  gt   re findall r   w     d     s  0  for s in strings     foofo    21      bar    432      foobar    12345      Note that I m using a simpler  less to type  regex than most of the previous answers

User · Answer

gt  gt  gt  r   re compile    a-zA-Z     0-9       gt  gt  gt  m   r match  foobar12345    gt  gt  gt  m group 1   foobar   gt  gt  gt  m group 2   12345    So  if you have a list of strings with that format   import re r   re compile    a-zA-Z     0-9      strings     foofo21    bar432    foobar12345   print  r match string  groups   for string in strings    Output      foofo    21      bar    432      foobar    12345

User · Answer

here is a simple function to seperate multiple words and numbers from a string of any length  the re method only seperates first two words and numbers  I think this will help everyone else in the future   def seperate string number string       previous character   string 0      groups          newword   string 0      for x  i in enumerate string 1             if i isalpha   and previous character isalpha                newword    i         elif i isnumeric   and previous character isnumeric                newword    i         else              groups append newword              newword   i          previous character   i          if x    len string  - 2              groups append newword              newword          return groups  print seperate string number  10in20ft10400bg      outputs     10    in    20    ft    10400    bg

User · Answer

Yet Another Option    gt  gt  gt   re split r   d     s  for s in   foofo21    bar432    foobar12345       foofo    21          bar    432          foobar    12345

User · Answer

def mysplit s           head   s rstrip  0123456789           tail   s len head            return head  tail           mysplit s  for s in   foofo21    bar432    foobar12345       foofo    21      bar    432      foobar    12345

User · Answer

This is a little longer  but more versatile for cases where there are multiple  randomly placed  numbers in the string  Also  it requires no imports  def getNumbers  input          Collect Info     compile    quot  quot      complete           for letter in input            If compiled string         if compile                If compiled and letter are same type  append letter             if compile isdigit      letter isdigit                    compile    letter                            If compiled and letter are different types  append compiled string  and begin with letter             else                  complete append  compile                   compile   letter                        If no compiled string  begin with letter         else              compile   letter                Append leftover compiled string     if compile          complete append  compile              Return numbers only     numbers     word for word in complete if word isdigit                  return numbers

User · Answer

I m always the one to bring up findall        gt  gt  gt  strings     foofo21    bar432    foobar12345    gt  gt  gt   re findall r   w     d     s  0  for s in strings     foofo    21      bar    432      foobar    12345      Note that I m using a simpler  less to type  regex than most of the previous answers

User · Answer

here is a simple function to seperate multiple words and numbers from a string of any length  the re method only seperates first two words and numbers  I think this will help everyone else in the future   def seperate string number string       previous character   string 0      groups          newword   string 0      for x  i in enumerate string 1             if i isalpha   and previous character isalpha                newword    i         elif i isnumeric   and previous character isnumeric                newword    i         else              groups append newword              newword   i          previous character   i          if x    len string  - 2              groups append newword              newword          return groups  print seperate string number  10in20ft10400bg      outputs     10    in    20    ft    10400    bg

User · Answer

here is simple solution for that problem  no needs for that  cat walk  on keyboard  i mean regex          enjoy  -   user   input  Input       user    foobar12345  int list  str list           for item in user   try      item   int item     searching for integers in your string   except      str list append item      string      join str list    else     if there are integers i will add it to int list but as str  because join function only can work with str     int list append str item       integer   int    join int list      if you want it to be string just do z      join int list   final    string  integer     you can also add it to dictionary d    string  integer  print final

User · Answer

without using regex  using isdigit   built-in function  only works if starting part is text and latter part is number  def text num split item       for index  letter in enumerate item  0           if letter isdigit                return  item  index  item index     print text num split  foobar12345      OUTPUT      foobar    12345

User · Answer

def mysplit s           head   s rstrip  0123456789           tail   s len head            return head  tail           mysplit s  for s in   foofo21    bar432    foobar12345       foofo    21      bar    432      foobar    12345

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