How to get the filename without the extension from a path in Python

Question

How to get the filename without the extension from a path in Python  For instance  if I had  quot  path to some file txt quot   I would want  quot file quot

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The other methods don t remove multiple extensions  Some also have problems with filenames that don t have extensions  This snippet deals with both instances and works in both Python 2 and 3  It grabs the basename from the path  splits the value on dots  and returns the first one which is the initial part of the filename   import os  def get filename without extension file path       file basename   os path basename file path      filename without extension   file basename split      0      return filename without extension   Here s a set of examples to run   example paths          FileName           FileName              FileName        FileName txt           FileName txt zip asc         path to some FileName         path to some FileName txt         path to some FileName txt zip asc     for example path in example paths      print get filename without extension example path     In every case  the value printed is   FileName

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import os  filename   C   Users  Public  Videos  Sample Videos  wildlife wmv   This returns the filename without the extension C  Users Public Videos Sample Videos wildlife   temp   os path splitext filename  0      Now you can get just the filename from the temp with  os path basename temp     this returns just the filename  wildlife

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Use  stem from pathlib in Python 3 4  from pathlib import Path  Path   root dir sub file ext   stem  will return  file   Note that if your file has multiple extensions  stem will only remove the last extension  For example  Path  file tar gz   stem will return  file tar

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On Windows system I used drivername prefix as well  like    gt  gt  gt  s    c   temp  akarmi txt   gt  gt  gt  print os path splitext s  0   c  temp akarmi   So because I do not need drive letter or directory name  I use    gt  gt  gt  print os path splitext os path basename s   0   akarmi

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But even when I import os  I am not able to call it path basename  Is it possible to call it as directly as basename    import os  and then use os path basename  importing os doesn t mean you can use os foo without referring to os

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IceAdor s refers to rsplit in a comment to  user2902201 s solution   rsplit is the simplest solution that supports multiple periods   Here it is spelt out   file    my report txt  print file rsplit      1  0    my report

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the easiest way to resolve this is to   import ntpath  print  Base name is   ntpath basename   path to the file       this saves you time and computation cost

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Getting the name of the file without the extension   import os print os path splitext   path to some file txt   0     Prints    path to some file   Documentation for os path splitext   Important Note  If the filename has multiple dots  only the extension after the last one is removed  For example   import os print os path splitext   path to some file txt zip asc   0     Prints    path to some file txt zip   See other answers below if you need to handle that case

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import os path    a b c abc txt  print os path splitext os path basename path   0

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Two or fewer extensions As mentioned in the comments of other Pathlib answers  it can be awkward to handle multiple suffixes  Two or fewer suffixes is not so bad to handle with  with suffix     and  stem  from pathlib import Path  pth   Path  foo bar baz baz thefile tar gz    fn   pth with suffix     stem  print fn         thefile  Any number of extensions If there may be more than two extensions  you may use a loop to handle the general case where there could be 0  1  or many suffixes  pth   Path  foo bar baz thefile tar gz bz 7zip    pth name          thefile tar gz bz 7zip  pth suffixes        tar     gz     bz     7zip     so fn   pth name for s in pth suffixes      fn   fn rsplit s  0       print fn         thefile  or fnp   Path pth name    for   in fnp suffixes      fnp   fnp with suffix          print fnp        thefile  Note here that fnp is a path  while fn is a string  which may determine the form of the loop that is preferred  In the case that you know the first extension For instance  if the extension could be  tar   tar gz   tar gz bz  etc  you can simply rsplit the known extension and take the first element   pth   Path  foo bar baz baz thefile tar gz    fn   pth name rsplit   tar   0   print fn         thefile

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https   docs python org 3 library os path html  In python 3 pathlib  The pathlib module offers high-level path objects   so     gt  gt  gt  from pathlib import Path  gt  gt  gt  p   Path   a b c txt    gt  gt  gt  print p with suffix       a b c  gt  gt  gt  print p stem  c

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If you want to keep the path to the file and just remove the extension   gt  gt  gt  file     root dir sub exten file data 1 2 dat   gt  gt  gt  print       join file split       -1    root dir sub exten file data 1 2

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In Python 3 4  you can use the pathlib solution   from pathlib import Path  print Path your path  resolve   stem

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Thought I would throw in a variation to the use of the os path splitext without the need to use array indexing    The function always returns a  root  ext  pair so it is safe to use   root  ext   os path splitext path   Example    gt  gt  gt  import os  gt  gt  gt  path    my text file txt   gt  gt  gt  root  ext   os path splitext path   gt  gt  gt  root  my text file   gt  gt  gt  ext   txt

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For convenience  a simple function wrapping the two methods from os path    def filename path        Return file name without extension from path     See https   docs python org 3 library os path html         import os path   b   os path split path  1     path   filename    f   os path splitext b  0      file   ext    print path  b  f    return f   Tested with Python 3 5

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Very very very simpely no other modules       import os p   r C  Users bilal Documents face Recognition python imgs northon jpg     Get the filename only from the initial file path  filename   os path basename p     Use splitext   to get filename and extension separately   file  ext    os path splitext filename     Print outcome  print  Filename without extension     file  print  Extension     ext

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We could do some simple split   pop magic as seen here  https   stackoverflow com a 424006 1250044   to extract the filename  respecting the windows and POSIX differences    def getFileNameWithoutExtension path     return path split       pop   split      pop   rsplit      1  0   getFileNameWithoutExtension   path to file-0 0 1 ext       gt  file-0 0 1  getFileNameWithoutExtension    path  to  file-0 0 1 ext       gt  file-0 0 1

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You can make your own with    gt  gt  gt  import os  gt  gt  gt  base os path basename   root dir sub file ext    gt  gt  gt  base  file ext   gt  gt  gt  os path splitext base    file     ext    gt  gt  gt  os path splitext base  0   file    Important note  If there is more than one   in the filename  only the last one is removed  For example    root dir sub file ext zip - gt  file ext   root dir sub file ext tar gz - gt  file ext tar   See below for other answers that address that

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A multiple extension aware procedure  Works for str and unicode paths  Works in Python 2 and 3   import os  def file base name file name       if     in file name          separator index   file name index              base name   file name  separator index          return base name     else          return file name  def path base name path       file name   os path basename path      return file base name file name    Behavior    gt  gt  gt  path base name  file    file   gt  gt  gt  path base name u file   u file   gt  gt  gt  path base name  file txt    file   gt  gt  gt  path base name u file txt   u file   gt  gt  gt  path base name  file tar gz    file   gt  gt  gt  path base name  file a b c d e f g    file   gt  gt  gt  path base name  relative path file ext    file   gt  gt  gt  path base name   absolute path file ext    file   gt  gt  gt  path base name  Relative  Windows  Path  file txt    file   gt  gt  gt  path base name  C   Absolute  Windows  Path  file txt    file   gt  gt  gt  path base name   path with spaces file ext    file   gt  gt  gt  path base name  C   Windows Path With Spaces  file txt    file   gt  gt  gt  path base name  some path file name with spaces tar gz zip rar 7z    file name with spaces

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I didn t look very hard but I didn t see anyone who used regex for this problem   I interpreted the question as  given a path  return the basename without the extension    e g    path to file json      file    path to my file json      my file   In Python 2 7  where we still live without pathlib     def get file name prefix file path       basename   os path basename file path       file name prefix match   re compile r    P lt file name pre fix gt            match basename       if file name prefix match is None          return file name     else          return file name prefix match group  file name prefix     get file name prefix  path to file json    gt  gt  file  get file name prefix  path to my file json    gt  gt  my file  get file name prefix  path to no extension    gt  gt  no extension

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import os list      def getFileName  path    for file in os listdir path        print file     try          base os path basename file          splitbase os path splitext base          ext   os path splitext base  1          if ext               list append base          else              newpath   path     file              print path             getFileName newpath      except          pass return list  getFileName   home weexcel-java3 Desktop backup   print list

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import os filename  file extension   os path splitext   d1 d2 example cs   filename is   d1 d2 example  file extension is   cs

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gt  gt  gt  print os path splitext os path basename  quot  path to file hemanth txt quot    0   hemanth

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os path splitext   won t work if there are multiple dots in the extension   For example  images tar gz   gt  gt  gt  import os  gt  gt  gt  file path     home dc images tar gz   gt  gt  gt  file name   os path basename file path   gt  gt  gt  print os path splitext file name  0  images tar   You can just find the index of the first dot in the basename and then slice the basename to get just the filename without extension    gt  gt  gt  import os  gt  gt  gt  file path     home dc images tar gz   gt  gt  gt  file name   os path basename file path   gt  gt  gt  index of dot   file name index       gt  gt  gt  file name without extension   file name  index of dot   gt  gt  gt  print file name without extension images

[python] How to get the filename without the extension from a path in Python?

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