Convert A String like testing123 To Binary In Java

Question

I would like to be able to convert a String  with words letters  to other forms  like binary  How would I go about doing this  I am coding in BLUEJ  Java   Thanks

User · Answer

A String in Java can be converted to  binary  with its getBytes Charset  method   byte   encoded               getBytes StandardCharsets UTF 8     The argument to this method is a  character-encoding   this is a standardized mapping between a character and a sequence of bytes  Often  each character is encoded to a single byte  but there aren t enough unique byte values to represent every character in every language  Other encodings use multiple bytes  so they can handle a wider range of characters   Usually  the encoding to use will be specified by some standard or protocol that you are implementing  If you are creating your own interface  and have the freedom to choose   UTF-8  is an easy  safe  and widely supported encoding     It s easy  because rather than including some way to note the encoding of each message  you can default to UTF-8  It s safe  because UTF-8 can encode any character that can be used in a Java character string  It s widely supported  because it is one of a small handful of character encodings that is required to be present in any Java implementation  all the way down to J2ME  Most other platforms support it too  and it s used as a default in standards like XML

User · Answer

You can also do this with the ol  good method    String inputLine    test123   String translatedString   null  char   stringArray   inputLine toCharArray    for int i 0 i lt stringArray length i           translatedString    Integer toBinaryString  int  stringArray i

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This is my implementation   public class Test       public String toBinary String text            StringBuilder sb   new StringBuilder             for  char character   text toCharArray                  sb append Integer toBinaryString character      n                       return sb toString

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While playing around with the answers I found here to become familiar with it I twisted Nuoji s solution a bit so that I could understand it faster when looking at it in the future   public static String stringToBinary String str  boolean pad         byte   bytes   str getBytes        StringBuilder binary   new StringBuilder        for  byte b   bytes               binary append Integer toBinaryString  int  b           if pad    binary append                   return binary toString

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int no 44               String bNo Integer toString no 2    binary output 101100              String oNo Integer toString no 8    Oct output 54              String hNo Integer toString no 16    Hex output 2C                String bNo1  Integer toBinaryString no    binary output 101100               String  oNo1 Integer toOctalString no    Oct output 54               String  hNo1 Integer toHexString no    Hex output 2C                String sBNo  101100                 no Integer parseInt sBNo 2    binary to int output 44                String sONo  54                 no Integer parseInt sONo 8    oct to int  output 44                String sHNo  2C                 no Integer parseInt sHNo 16    hex to int output 44

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A shorter example  private static final Charset UTF 8   Charset forName  UTF-8     String text    Hello World    byte   bytes   text getBytes UTF 8   System out println  bytes    Arrays toString bytes    System out println  text again    new String bytes  UTF 8      prints  bytes   72  101  108  108  111  32  87  111  114  108  100  33  text again  Hello World

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import java lang    import java io    class d2b     public static void main String args    throws IOException    BufferedReader b   new BufferedReader new InputStreamReader System in      System out println  Enter the decimal value       String h   b readLine      int k   Integer parseInt h       String out   Integer toBinaryString k     System out println  Binary      out

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public class HexadecimalToBinaryAndLong    public static void main String   args  throws IOException      BufferedReader bf   new BufferedReader new InputStreamReader System in        System out println  Enter the hexa value         String hex   bf readLine        int i   Integer parseInt hex                   hex to decimal     String by   Integer toBinaryString i           decimal to binary     System out println  This is Binary      by

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The usual way is to use String getBytes   to get the underlying bytes and then present those bytes in some other form  hex  binary whatever     Note that getBytes   uses the default charset  so if you want the string converted to some specific character encoding  you should use getBytes String encoding  instead  but many times  esp when dealing with ASCII  getBytes   is enough  and has the advantage of not throwing a checked exception    For specific conversion to binary  here is an example     String s    foo     byte   bytes   s getBytes      StringBuilder binary   new StringBuilder      for  byte b   bytes           int val   b       for  int i   0  i  lt  8  i                   binary append  val  amp  128     0   0   1           val  lt  lt   1              binary append             System out println       s      to binary      binary     Running this example will yield    foo  to binary  01100110 01101111 01101111

User · Answer

Here are my solutions  Their advantages are   easy-understanding code  works for all characters  Enjoy   Solution 1    public static void main String   args         String str    CC        String result           char   messChar   str toCharArray         for  int i   0  i  lt  messChar length  i              result    Integer toBinaryString messChar i                     System out println result       prints    1000011 1000011 100101   Solution 2    Possibility to choose the number of displayed bits per char   public static String toBinary String str  int bits        String result           String tmpStr      int tmpInt      char   messChar   str toCharArray         for  int i   0  i  lt  messChar length  i              tmpStr   Integer toBinaryString messChar i            tmpInt   tmpStr length            if tmpInt    bits                tmpInt   bits - tmpInt              if  tmpInt    bits                    result    tmpStr                else if  tmpInt  gt  0                    for  int j   0  j  lt  tmpInt  j                          result     0                                     result    tmpStr                else                   System err println  argument  bits  is too small                            else               result    tmpStr                    result            separator            return result        public static void main String args          System out println toBinary  CC    8        prints    01000011 01000011 00100101

[java] Convert A String (like testing123) To Binary In Java

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