Convert character to ASCII numeric value in java

Question

I have String name    quot admin quot   then I do String charValue   name substring 0 1     charValue  quot a quot  I want to convert the charValue to its ASCII value  97   how can I do this in java

User · Answer

String str    abc       or anything else     Stores strings of integer representations in sequence StringBuilder sb   new StringBuilder    for  char c   str toCharArray        sb append  int c        store ascii integer string array in large integer BigInteger mInt   new BigInteger sb toString     System out println mInt

User · Answer

As  Raedwald pointed out  Java s Unicode doesn t cater to all the characters to get ASCII value  The correct way  Java 1 7   is as follows    byte   asciiBytes    MyAscii  getBytes StandardCharsets US ASCII   String asciiString   new String asciiBytes     asciiString   Arrays toString asciiBytes

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using Java 9    String chars    String input    stackoverflow   System out println input chars   boxed   collect Collectors toList        output -  115  116  97  99  107  111  118  101  114  102  108  111  119

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The several answers that purport to show how to do this are all wrong because Java characters are not ASCII characters  Java uses a multibyte encoding of Unicode characters  The Unicode character set is a super set of ASCII  So there can be characters in a Java string that do not belong to ASCII  Such characters do not have an ASCII numeric value  so asking how to get the ASCII numeric value of a Java character is unanswerable   But why do you want to do this anyway  What are you going to do with the value   If you want the numeric value so you can convert the Java String to an ASCII string  the real question is  how do I encode a Java String as ASCII   For that  use the object StandardCharsets US ASCII

User · Answer

Convert the char to int       String name    admin       int ascii   name toCharArray   0     Also    int ascii   name charAt 0

User · Answer

Very simple  Just cast your char as an int   char character    a       int ascii    int  character    In your case  you need to get the specific Character from the String first and then cast it    char character   name charAt 0      This gives the character  a  int ascii    int  character     ascii is now 97    Though cast is not required explicitly  but its improves readability   int ascii   character     Even this will do the trick

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Or you can use Stream API for 1 character or a String starting in Java 1 8   public class ASCIIConversion       public static void main String   args            String text    adskjfhqewrilfgherqifvehwqfjklsdbnf           text chars                    forEach System out  println

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You can check the ASCII  s number with this code   String name    admin   char a1   a charAt 0   int a2   a1  System out println  The number is     a2      the value is 97   If I am wrong  apologies

User · Answer

It s simple  get the character you want  and convert it to int   String name    admin   int ascii   name charAt 0

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I know this has already been answered in several forms but here is my bit of code with a look to go through all the characters   Here is the code  started with the class  public class CheckChValue       Class name public static void main String   args       class main      String name    admin      String to check it s value     int nameLenght   name length       length of the string used for the loop      for int i   0  i  lt  nameLenght   i          while counting characters if less than the length add one                 char character   name charAt i      start on the first character         int ascii    int  character    convert the first character         System out println character        ascii      print the character and it s value in ascii

User · Answer

Just cast the char to an int   char character    a   int number    int  character    The value of number will be 97

User · Answer

If you wanted to convert the entire string into concatenated ASCII values then you can use this -      String str    abc       or anything else      StringBuilder sb   new StringBuilder        for  char c   str toCharArray        sb append  int c        BigInteger mInt   new BigInteger sb toString         System out println mInt     wherein you will get 979899 as output   Credit to this   I just copied it here so that it would be convenient for others

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String name    admin   char   ch   name toString   toCharArray      it will read and store each character of String and store into char     for int i 0  i lt ch length  i          System out println ch i                           -- gt                            int ch i      this will print both character and its value

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One line solution without using extra int variable  String name    quot admin quot   System out println  int name charAt 0

User · Answer

The easy way to do this is    For whole String into ASCII      public class ConvertToAscii      public static void main String args           String abc    admin         int   arr   new int abc length           System out println  THe asscii value of each character is            for int i 0 i lt arr length i               arr i    abc charAt i      assign the integer value of character i e ascii           System out print     arr i                       The output is    THe asscii value of each character is    97 100 109 105 110  Here  abc charAt i  gives the single character of String array  When we assign each character to integer type then  the compiler do type conversion as   arr i     int  character    Here  every individual character is coverted in ascii value   But  for single character   String name   admin  asciiValue    int  name charAt 0     for character  a  System out println asciiValue

User · Answer

I was trying the same thing  but best and easy solution would be to use charAt and to access the indexes we should create an integer array of  128  size   String name    admin    int ascii   name charAt 0    int   letters   new int 128     this will allocate space with 128byte size  letters ascii       increments the value of 97 to 1  System out println  Output     ascii     Outputs 97 System out println  Output      letters ascii      Outputs 1 if you debug you ll see 97th index value will be 1    In case if you want to display ascii values of complete String  you need to do this   String name    admin   char   val   name toCharArray    for char b  val     int c   b   System out println  Ascii value of     b     is      c       Your output  in this case  will be   Ascii value of a is  97 Ascii value of d is  100 Ascii value of m is  109 Ascii value of i is  105 Ascii value of n is  110

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Instead of this   String char   name substring 0 1     char  a    You should use the charAt   method   char c   name charAt 0      c  a  int ascii    int c

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For this we could straight away use String classe s      input codePointAt index     I would like to give one more suggestion as to get whole of string converted to corresponding ascii codes  using java 8 for example   abcde  to  979899100101        String input    abcde       System out println              input codePoints                        mapToObj  t  - gt       t                       collect joining

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An easy way for this is       int character    a     If you print  character   you get 97

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just a different approach      String s    admin       byte   bytes   s getBytes  US-ASCII      bytes 0  will represent ascii of a   and thus the other characters in the whole array

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public class Ascii       public static void main String    args           String a args 0           char    z a toCharArray            for int i 0 i lt z length i                  System out println  int z i

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If you want the ASCII value of all the characters in a String  You can use this     String a   asdasd   int count  0  for int i   a toCharArray        count  i    and if you want ASCII of a single character in a String you can go for      int a charAt index

[java] Convert character to ASCII numeric value in java

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