Use $n
(where n is a digit) to refer to captured subsequences in replaceFirst(...)
. I'm assuming you wanted to replace the first group with the literal string "number" and the second group with the value of the first group.
Pattern p = Pattern.compile("(\\d)(.*)(\\d)");
String input = "6 example input 4";
Matcher m = p.matcher(input);
if (m.find()) {
// replace first number with "number" and second number with the first
String output = m.replaceFirst("number $3$1"); // number 46
}
Consider (\D+)
for the second group instead of (.*)
. *
is a greedy matcher, and will at first consume the last digit. The matcher will then have to backtrack when it realizes the final (\d)
has nothing to match, before it can match to the final digit.